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Integral as Area infographic - Riemann Sums, the Fundamental Theorem, and Accumulation

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The definite integral abf(x)dx\int_{a}^{b} f(x) \, dx measures the signed area between the curve f(x)f(x) and the x-axis from x=ax = a to x=bx = b. The concept arises from Riemann sums: dividing the interval [a,b][a, b] into nn subintervals, forming rectangles of width Δx\Delta x and height f(xi)f(x_i), and summing all their areas. As nn \to \infty and Δx0\Delta x \to 0, this sum converges to the exact integral. Regions where f(x)f(x) is negative contribute negative area to the definite integral.

The Fundamental Theorem of Calculus (FTC) connects differentiation and integration. Part 1 states that if FF is the antiderivative of ff, then ddx[f(t)dt from a to x]=f(x)\frac{d}{dx}\left[\int f(t) \, dt \text{ from } a \text{ to } x\right] = f(x). Part 2 provides the evaluation shortcut: abf(x)dx=F(b)F(a)\int_{a}^{b} f(x) \, dx = F(b) - F(a), where FF is any antiderivative of ff. Integration also computes displacement, net change, work, and probability - any quantity that accumulates continuously over a continuous variable. The indefinite integral f(x)dx=F(x)+C\int f(x) \, dx = F(x) + C finds families of antiderivatives, with the constant CC representing the entire family.

Key Facts

  • Definite integral = signed area under curve; negative where f(x)<0f(x) < 0
  • Riemann sum: f(xi)Δxabf(x)dx\sum f(x_i)\Delta x \to \int_{a}^{b} f(x) \, dx as nn \to \infty
  • FTC Part 2: abf(x)dx=F(b)F(a)\int_{a}^{b} f(x) \, dx = F(b) - F(a), where F(x)=f(x)F'(x) = f(x)
  • Power rule for integration: xndx=xn+1n+1+C\int x^n \, dx = \frac{x^{n+1}}{n+1} + C (n1n \neq -1)
  • abf(x)dx=baf(x)dx\int_{a}^{b} f(x) \, dx = -\int_{b}^{a} f(x) \, dx (reversing limits changes sign)
  • Net displacement ≠ total distance; total distance = ∫|v(t)| dt

Vocabulary

Definite integral
The limit of a Riemann sum giving the signed area under a curve f(x)f(x) between x=ax = a and x=bx = b.
Antiderivative
A function F(x)F(x) whose derivative is f(x)f(x); also called an indefinite integral. Differs from another antiderivative by only a constant CC.
Riemann sum
An approximation of the area under a curve using rectangles; the basis for the definition of the definite integral.
Fundamental Theorem of Calculus
The theorem connecting differentiation and integration: differentiation and integration are inverse operations, and antiderivatives evaluate definite integrals.
Accumulation function
A function of the form A(x)=axf(t)dtA(x) = \int_a^x f(t)\,dt that represents the accumulated area (or net change) from a fixed point aa up to xx.

Common Mistakes to Avoid

  • Forgetting the constant of integration for indefinite integrals. f(x)dx=F(x)+C\int f(x)\,dx = F(x) + C, not just F(x)F(x). The constant matters because it represents an entire family of antiderivatives.
  • Treating negative areas as zero. If f(x)f(x) is negative on part of [a,b][a,b], the integral subtracts that region's area. The definite integral gives net signed area, not total area.
  • Applying the power rule to 1xdx\int \frac{1}{x}\,dx. xndx=xn+1n+1\int x^n\,dx = \frac{x^{n+1}}{n+1} fails when n=1n = -1 (division by zero). Instead, 1xdx=lnx+C\int \frac{1}{x}\,dx = \ln|x| + C.
  • Confusing indefinite and definite integrals. f(x)dx\int f(x)\,dx is a family of functions +C+ C; abf(x)dx\int_a^b f(x)\,dx is a single number (the area). The definite integral needs bounds.

Practice Questions

  1. 1 Evaluate ∫[0 to 3] (x² − 2x) dx. Identify any regions where the integrand is negative and how they affect the result.
  2. 2 Find the total area (not net area) between f(x)=x24f(x) = x^2 - 4 and the xx-axis from x=0x = 0 to x=3x = 3.
  3. 3 A particle moves with velocity v(t)=t24t+3v(t) = t^2 - 4t + 3 m/s. Find the displacement and total distance traveled from t=0t = 0 to t=4t = 4 s.