Determinants and Cramer's Rule Worksheet

Question 1

Find the determinant of the matrix [[4, 7], [2, 5]].

Accepted Answer

The determinant is 4(5) - 7(2) = 20 - 14 = 6.

Question 2

Find the determinant of the matrix [[-3, 6], [4, -2]].

Accepted Answer

The determinant is (-3)(-2) - 6(4) = 6 - 24 = -18.

Question 3

Find the determinant of the matrix [[1, 2, 3], [0, 4, 5], [0, 0, 6]].

Accepted Answer

The determinant is 1(4)(6) = 24 because the matrix is triangular, so the determinant is the product of the diagonal entries.

Question 4

Find the determinant of the matrix [[2, 1, 0], [3, -1, 4], [1, 2, 5]].

Accepted Answer

Expanding along the first row gives 2((-1)(5) - 4(2)) - 1(3(5) - 4(1)) + 0 = 2(-13) - 11 = -37. The determinant is -37.

Question 5

Use Cramer's Rule to solve the system: 2x + y = 7 and x - y = 2.

Accepted Answer

The coefficient determinant is D = 2(-1) - 1(1) = -3. The x determinant is Dx = 7(-1) - 1(2) = -9, so x = Dx/D = 3. The y determinant is Dy = 2(2) - 7(1) = -3, so y = Dy/D = 1. The solution is x = 3 and y = 1.

Question 6

Use Cramer's Rule to solve the system: 3x - 2y = 4 and x + y = 5.

Accepted Answer

The coefficient determinant is D = 3(1) - (-2)(1) = 5. The x determinant is Dx = 4(1) - (-2)(5) = 14, so x = 14/5. The y determinant is Dy = 3(5) - 4(1) = 11, so y = 11/5. The solution is x = 14/5 and y = 11/5.

Question 7

A system has coefficient matrix [[5, 2], [10, 4]]. Explain why Cramer's Rule cannot give a unique solution for this system.

Accepted Answer

The determinant is 5(4) - 2(10) = 20 - 20 = 0. Since the coefficient determinant is 0, Cramer's Rule cannot be used to find a unique solution.

Question 8

Use Cramer's Rule to solve the system: 4x + 3y = 18 and 2x - y = 0.

Accepted Answer

The coefficient determinant is D = 4(-1) - 3(2) = -10. The x determinant is Dx = 18(-1) - 3(0) = -18, so x = 9/5. The y determinant is Dy = 4(0) - 18(2) = -36, so y = 18/5. The solution is x = 9/5 and y = 18/5.

Question 9

Find the determinant of the matrix [[0, 3, -1], [2, 1, 4], [5, 0, 2]] using cofactor expansion along the first row.

Accepted Answer

Expanding along the first row gives 0 - 3(2(2) - 4(5)) + (-1)(2(0) - 1(5)). This equals -3(4 - 20) + (-1)(-5) = 48 + 5 = 53. The determinant is 53.

Question 10

Use Cramer's Rule to solve the system: x + y + z = 6, 2x - y + z = 3, and x + 2y - z = 2.

Accepted Answer

The coefficient determinant is D = 6. Replacing the x-column gives Dx = 6, so x = 1. Replacing the y-column gives Dy = 12, so y = 2. Replacing the z-column gives Dz = 18, so z = 3. The solution is x = 1, y = 2, and z = 3.

Question 11

For the system ax + by = e and cx + dy = f, write the Cramer's Rule formulas for x and y, assuming the coefficient determinant is not 0.

Accepted Answer

The coefficient determinant is D = ad - bc. The formula for x is x = (ed - bf)/(ad - bc), and the formula for y is y = (af - ec)/(ad - bc).

Question 12

Use determinants to decide whether the system 6x - 9y = 12 and -2x + 3y = -4 has a unique solution. Then explain your conclusion.

Accepted Answer

The coefficient determinant is 6(3) - (-9)(-2) = 18 - 18 = 0. Since the determinant is 0, the system does not have a unique solution. The second equation is a multiple of the first, so the system has infinitely many solutions.

Determinants and Cramer's Rule

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