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First- and second-order differential equations model how quantities change in time, space, or another independent variable. This cheat sheet helps students recognize common equation types and choose a solution method quickly. It is especially useful for reviewing solution forms, initial conditions, and the behavior of linear systems.

Clear formulas reduce confusion when moving between algebra, calculus, and applications.

Key Facts

  • A separable first-order equation has the form dydx=g(x)h(y)\frac{dy}{dx} = g(x)h(y) and is solved by rewriting it as 1h(y)dy=g(x)dx\frac{1}{h(y)}\,dy = g(x)\,dx before integrating.
  • A linear first-order equation has the form y+P(x)y=Q(x)y' + P(x)y = Q(x) and uses the integrating factor μ(x)=eP(x)dx\mu(x) = e^{\int P(x)\,dx}.
  • After multiplying by the integrating factor, y+P(x)y=Q(x)y' + P(x)y = Q(x) becomes ddx[μ(x)y]=μ(x)Q(x)\frac{d}{dx}\left[\mu(x)y\right] = \mu(x)Q(x).
  • A homogeneous second-order linear equation with constant coefficients has the form ay+by+cy=0ay'' + by' + cy = 0 and characteristic equation ar2+br+c=0ar^2 + br + c = 0.
  • If the characteristic roots are distinct real numbers r1r_1 and r2r_2, then the general solution is y=C1er1x+C2er2xy = C_1e^{r_1x} + C_2e^{r_2x}.
  • If the characteristic equation has a repeated real root rr, then the general solution is y=C1erx+C2xerxy = C_1e^{rx} + C_2xe^{rx}.
  • If the characteristic roots are complex r=α±βir = \alpha \pm \beta i, then the general solution is y=eαx(C1cos(βx)+C2sin(βx))y = e^{\alpha x}\left(C_1\cos(\beta x) + C_2\sin(\beta x)\right).
  • For a nonhomogeneous equation ay+by+cy=f(x)ay'' + by' + cy = f(x), the general solution is y=yh+ypy = y_h + y_p, where yhy_h solves the homogeneous equation and ypy_p is one particular solution.

Vocabulary

Differential equation
An equation involving an unknown function and one or more of its derivatives.
Order
The order of a differential equation is the highest derivative that appears, such as first order for yy' or second order for yy''.
Initial condition
A value such as y(0)=2y(0)=2 or y(0)=1y'(0)=-1 that is used to determine constants in a general solution.
Integrating factor
A function μ(x)=eP(x)dx\mu(x) = e^{\int P(x)\,dx} that turns a first-order linear equation into an exact derivative.
Characteristic equation
The algebraic equation ar2+br+c=0ar^2 + br + c = 0 obtained from a constant-coefficient homogeneous equation ay+by+cy=0ay'' + by' + cy = 0.
Particular solution
A single solution ypy_p that satisfies a nonhomogeneous differential equation such as ay+by+cy=f(x)ay'' + by' + cy = f(x).

Common Mistakes to Avoid

  • Forgetting the constant of integration in a first-order solution is wrong because the general solution needs an arbitrary constant such as CC before applying an initial condition.
  • Using an integrating factor on an equation that is not in the form y+P(x)y=Q(x)y' + P(x)y = Q(x) is wrong because P(x)P(x) must be the coefficient of yy after the coefficient of yy' is 11.
  • Solving ar2+br+c=0ar^2 + br + c = 0 incorrectly is serious because every second-order homogeneous solution depends on the correct characteristic roots.
  • Using y=C1erx+C2erxy = C_1e^{rx} + C_2e^{rx} for a repeated root is wrong because the two terms are not independent, so the correct form is y=C1erx+C2xerxy = C_1e^{rx} + C_2xe^{rx}.
  • Choosing a particular solution that duplicates part of yhy_h is wrong because it will not be linearly independent, so the trial form must be multiplied by xx when overlap occurs.

Practice Questions

  1. 1 Solve the separable equation dydx=3x2y\frac{dy}{dx} = 3x^2y with initial condition y(0)=4y(0)=4.
  2. 2 Solve the first-order linear equation y+2y=exy' + 2y = e^x using the integrating factor method.
  3. 3 Find the general solution of y5y+6y=0y'' - 5y' + 6y = 0.
  4. 4 Explain how the solution behavior changes when the characteristic roots of ay+by+cy=0ay'' + by' + cy = 0 are real distinct, repeated, or complex.