Sign in to save

Bookmark this page so you can find it later.

Sign in to save

Bookmark this page so you can find it later.

Lagrange's Theorem (Group Theory) Reference cheat sheet - grade college

Click image to open full size

Math Grade college

Lagrange's Theorem (Group Theory) Reference Cheat Sheet

A printable reference covering Lagrange's theorem, subgroup order, index, cosets, element order, and finite group consequences for college.

Download PNG

Study as Flashcards

Lagrange's Theorem is a central result in finite group theory that connects the size of a group to the size of each subgroup. This cheat sheet helps students organize the ideas of subgroup order, cosets, index, and element order. It is especially useful when proving divisibility statements, ruling out possible subgroups, and analyzing cyclic subgroups in finite groups.

The main theorem says that if HGH \leq G and GG is finite, then H|H| divides G|G|. The quotient [G:H]=GH[G:H] = \frac{|G|}{|H|} counts the number of left cosets of HH in GG. A key consequence is that the order of any element aGa \in G divides G|G|, because a=a|a| = |\langle a \rangle|.

Lagrange's Theorem gives necessary conditions for subgroup orders, but it does not guarantee that every divisor of G|G| is the order of a subgroup.

Key Facts

  • If GG is a finite group and HGH \leq G, then Lagrange's Theorem states that G=[G:H]H|G| = [G:H]|H|.
  • The index [G:H][G:H] is the number of distinct left cosets gHgH of HH in GG.
  • Every left coset gHgH has the same size as HH, so gH=H|gH| = |H| for every gGg \in G.
  • The distinct left cosets of HH partition GG, meaning every element of GG lies in exactly one left coset.
  • If aGa \in G, then the order of aa satisfies a=a|a| = |\langle a \rangle| and therefore a|a| divides G|G|.
  • If G=p|G| = p for a prime pp, then GG is cyclic and its only subgroups have orders 11 and pp.
  • For every aGa \in G with GG finite, aG=ea^{|G|} = e because a|a| divides G|G|.
  • Lagrange's Theorem implies possible subgroup orders must divide G|G|, but not every divisor of G|G| must occur as a subgroup order.

Vocabulary

Group
A group is a set GG with an operation that is closed, associative, has an identity element ee, and gives every element an inverse.
Subgroup
A subgroup HGH \leq G is a subset of GG that is itself a group under the same operation.
Coset
A left coset of HH in GG is a set gH={gh:hH}gH = \{gh : h \in H\} for some gGg \in G.
Index
The index [G:H][G:H] is the number of distinct cosets of HH in GG.
Order of a Group
The order of a finite group GG is the number of elements in GG, written G|G|.
Order of an Element
The order of an element aGa \in G is the smallest positive integer nn such that an=ea^n = e.

Common Mistakes to Avoid

  • Assuming every divisor gives a subgroup is wrong because Lagrange's Theorem only says subgroup orders must divide G|G|, not that every divisor of G|G| occurs.
  • Confusing G|G|, H|H|, and [G:H][G:H] is wrong because they measure different things: group size, subgroup size, and number of cosets.
  • Forgetting that cosets partition GG is wrong because the proof of G=[G:H]H|G| = [G:H]|H| depends on distinct cosets being disjoint and covering all of GG.
  • Thinking all cosets are subgroups is wrong because a coset gHgH is a subgroup only in special cases, such as when gHg \in H.
  • Using Lagrange's Theorem for infinite groups without care is wrong because the standard divisibility statement HG|H| \mid |G| applies to finite groups.

Practice Questions

  1. 1 Let GG be a finite group with G=60|G| = 60 and let HGH \leq G with H=12|H| = 12. Find [G:H][G:H].
  2. 2 If G=35|G| = 35, list all possible orders of an element aGa \in G according to Lagrange's Theorem.
  3. 3 Suppose GG is a finite group with G=18|G| = 18. Can GG have an element of order 88? Explain using Lagrange's Theorem.
  4. 4 Explain why Lagrange's Theorem can rule out some subgroup orders but cannot prove that a subgroup of every divisor order exists.

Understanding Lagrange's Theorem (Group Theory) Reference

The reason behind the theorem is a counting argument based on translation. Start with a subgroup H and choose any element g of the larger group. Multiplying every element of H by g produces a coset.

This process does not lose or repeat elements. If two products are equal, multiplying by the inverse of g shows that the original subgroup elements were equal. Thus multiplication by g gives a perfect pairing between H and its coset.

Every coset therefore contains exactly as many elements as H. The important next step is that two cosets either have no shared elements or are actually the same set. This is what allows the whole group to be broken into equal sized blocks.

Symmetry groups give a concrete picture. Consider all eight symmetries of a square. The four rotations form a subgroup.

One coset is the rotation subgroup itself. A reflection followed by each possible rotation gives the other coset. These two collections contain four symmetries each, with no overlap, and together they include all eight symmetries.

This example shows that a coset need not be a subgroup. The reflection coset does not contain the identity symmetry, so it cannot be a subgroup. Cosets are translated copies used for counting, not necessarily smaller groups with their own identity.

Element order turns this counting result into a useful test for calculations. Repeatedly applying an element eventually returns to the identity in a finite group. The first positive number of repetitions that returns to the identity is the element order.

Since the powers of one element form a cyclic subgroup, that number must fit evenly into the size of the full group. This helps in modular arithmetic, where the nonzero residue classes that are relatively prime to a modulus form a group under multiplication. It explains why large powers can often be reduced to smaller ones.

It is important to check that the numbers being used are invertible modulo the modulus. All residues modulo a number do not form a multiplicative group when some have no inverse.

Students should treat divisibility as a filter, not as a construction method. If a proposed subgroup size does not divide the group size, the proposal is impossible immediately. If it does divide, more work is needed.

For example, the alternating group on four letters has twelve elements, yet it has no subgroup with six elements. Group structure matters, not just the total count. Another point to watch is the difference between left cosets and right cosets.

In a commutative group they match. In a noncommutative group they can differ. When they match for every group element, the subgroup is called normal, and this extra condition is needed before cosets can themselves be used to form a quotient group.