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The most important idea is that logb(x)=y\log_b(x)=y means by=xb^y=x, where b>0b>0, b1b\ne 1, and x>0x>0. Logarithm rules turn multiplication into addition, division into subtraction, and powers into coefficients. The change of base formula lets you evaluate logs in any base using a calculator.

When solving logarithmic equations, always check that every log argument is positive.

Key Facts

  • The definition of a logarithm is logb(x)=y\log_b(x)=y if and only if by=xb^y=x, where b>0b>0, b1b\ne 1, and x>0x>0.
  • The product rule is logb(MN)=logb(M)+logb(N)\log_b(MN)=\log_b(M)+\log_b(N) for positive MM and NN.
  • The quotient rule is logb(MN)=logb(M)logb(N)\log_b\left(\frac{M}{N}\right)=\log_b(M)-\log_b(N) for positive MM and NN.
  • The power rule is logb(Mp)=plogb(M)\log_b(M^p)=p\log_b(M) for positive MM.
  • The change of base formula is logb(x)=loga(x)loga(b)\log_b(x)=\frac{\log_a(x)}{\log_a(b)}, commonly written as logb(x)=log(x)log(b)\log_b(x)=\frac{\log(x)}{\log(b)}.
  • Common logarithms use base 1010, so log(x)=log10(x)\log(x)=\log_{10}(x).
  • Natural logarithms use base ee, so ln(x)=loge(x)\ln(x)=\log_e(x).
  • Inverse identities include logb(bx)=x\log_b(b^x)=x and blogb(x)=xb^{\log_b(x)}=x for valid values of bb and xx.

Vocabulary

Logarithm
A logarithm is the exponent needed to raise a base to a given positive number.
Base
The base is the positive number bb in logb(x)\log_b(x), where b1b\ne 1.
Argument
The argument is the input xx in logb(x)\log_b(x), and it must be positive.
Common Logarithm
A common logarithm is a logarithm with base 1010, written as log(x)\log(x).
Natural Logarithm
A natural logarithm is a logarithm with base ee, written as ln(x)\ln(x).
Change of Base
Change of base is the formula logb(x)=loga(x)loga(b)\log_b(x)=\frac{\log_a(x)}{\log_a(b)} used to rewrite a logarithm in a different base.

Common Mistakes to Avoid

  • Adding logs incorrectly, such as writing logb(M)+logb(N)=logb(M+N)\log_b(M)+\log_b(N)=\log_b(M+N), is wrong because the product rule gives logb(MN)\log_b(MN) instead.
  • Dropping the domain restriction is a mistake because logb(x)\log_b(x) is only defined for x>0x>0 in real-number algebra.
  • Using the power rule backward incorrectly, such as changing logb(Mp)\log_b(M^p) into (logb(M))p\left(\log_b(M)\right)^p, is wrong because the exponent becomes a multiplier: plogb(M)p\log_b(M).
  • Forgetting to check solutions can produce extraneous answers because solving may create values that make a log argument zero or negative.
  • Confusing the base and the argument in exponential form is wrong because logb(x)=y\log_b(x)=y converts to by=xb^y=x, not xy=bx^y=b.

Practice Questions

  1. 1 Rewrite log3(81)=4\log_3(81)=4 in exponential form.
  2. 2 Evaluate log2(32)\log_2(32).
  3. 3 Use log rules to expand log5(x3y25)\log_5\left(\frac{x^3y}{25}\right), assuming x>0x>0 and y>0y>0.
  4. 4 Explain why the equation log4(x2)+log4(x+2)=1\log_4(x-2)+\log_4(x+2)=1 requires checking the domain before accepting a solution.