Exact differential equations use partial derivatives to recognize when a first order differential equation comes from a single potential function. This cheat sheet helps students test exactness, build the potential function, and write the implicit solution clearly. It is especially useful for solving equations written in differential form, where algebra and partial integration can become confusing.
The goal is to make the method systematic and easy to check.
The main form is , which is exact when on a suitable region. If exact, there is a function such that and , and the solution is . If the equation is not exact, an integrating factor such as or may make it exact.
The most important shortcuts test whether depends only on or whether depends only on .
Key Facts
- A first order equation in differential form is written as .
- The equation is exact when on a region where the needed derivatives are continuous.
- For an exact equation, find a potential function satisfying and .
- The implicit general solution of an exact equation is , where is an arbitrary constant.
- A common way to build is , then use to find .
- If depends only on , then an integrating factor is .
- If depends only on , then an integrating factor is .
- For a linear equation , the integrating factor is .
Vocabulary
- Differential form
- A first order differential equation written as .
- Exact equation
- An equation is exact when it can be written as for some potential function .
- Potential function
- A function whose differential is .
- Integrating factor
- A nonzero function that multiplies a differential equation to make it exact or easier to integrate.
- Implicit solution
- A solution written as a relation such as instead of solving explicitly for .
- Exactness condition
- The test used to determine whether is exact.
Common Mistakes to Avoid
- Testing exactness with the wrong derivatives is incorrect because the condition is , not .
- Forgetting the unknown function after partial integration is incorrect because may still need an added term .
- Treating as a constant in every step is wrong because is constant only when integrating with respect to , while is constant when integrating with respect to .
- Using when still contains is invalid because that formula requires dependence on only.
- Stopping after finding an integrating factor is incomplete because the multiplied equation must still be solved as an exact equation.
Practice Questions
- 1 Determine whether is exact, and if it is exact, find the implicit solution.
- 2 Solve by first testing exactness and then finding .
- 3 For , test whether an integrating factor of the form exists using .
- 4 Explain why an integrating factor can change a non-exact equation into an exact equation without changing the solution curves when .