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Tangent Lines & The Derivative as a Limit cheat sheet - grade 11-12

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This cheat sheet covers how tangent lines are connected to derivatives and limits. Students need it because many calculus problems begin with finding an instantaneous rate of change at a point. It helps connect the graph of a function, the slope of a secant line, and the slope of a tangent line. The goal is to make the derivative definition clear and usable.

Key Facts

  • The slope of the secant line through x=ax=a and x=a+hx=a+h is f(a+h)f(a)h\frac{f(a+h)-f(a)}{h}, where h0h \neq 0.
  • The derivative of ff at x=ax=a is f(a)=limh0f(a+h)f(a)hf'(a)=\lim_{h\to 0}\frac{f(a+h)-f(a)}{h} if the limit exists.
  • An equivalent derivative definition is f(a)=limxaf(x)f(a)xaf'(a)=\lim_{x\to a}\frac{f(x)-f(a)}{x-a}.
  • The tangent line to y=f(x)y=f(x) at x=ax=a has slope f(a)f'(a) and passes through (a,f(a))(a,f(a)).
  • The tangent line equation is yf(a)=f(a)(xa)y-f(a)=f'(a)(x-a).
  • If f(a)>0f'(a)>0, the function is increasing near x=ax=a; if f(a)<0f'(a)<0, the function is decreasing near x=ax=a.
  • A derivative does not exist at x=ax=a if the limit of the difference quotient fails to exist, such as at a corner, cusp, vertical tangent, or discontinuity.
  • The units of f(a)f'(a) are the units of f(x)f(x) divided by the units of xx.

Vocabulary

Secant line
A secant line is a line that passes through two points on a graph, such as (a,f(a))(a,f(a)) and (a+h,f(a+h))(a+h,f(a+h)).
Tangent line
A tangent line is the line that best matches the direction of a curve at one point and has slope f(a)f'(a).
Difference quotient
The difference quotient f(a+h)f(a)h\frac{f(a+h)-f(a)}{h} gives the average rate of change from x=ax=a to x=a+hx=a+h.
Derivative at a point
The derivative at a point is the instantaneous rate of change, defined by f(a)=limh0f(a+h)f(a)hf'(a)=\lim_{h\to 0}\frac{f(a+h)-f(a)}{h}.
Instantaneous rate of change
An instantaneous rate of change describes how fast a function is changing at a single input value.
Point-slope form
Point-slope form is yy1=m(xx1)y-y_1=m(x-x_1), which is useful for writing a tangent line when a point and slope are known.

Common Mistakes to Avoid

  • Using f(a+h)f(a)a+ha\frac{f(a+h)-f(a)}{a+h-a} but not simplifying the denominator to hh is wrong because the derivative limit depends on the quotient f(a+h)f(a)h\frac{f(a+h)-f(a)}{h} before taking h0h\to 0.
  • Substituting h=0h=0 too early is wrong because f(a+h)f(a)h\frac{f(a+h)-f(a)}{h} is undefined at h=0h=0 and must be simplified before evaluating the limit.
  • Finding f(x)f'(x) but forgetting to evaluate at x=ax=a is wrong because the tangent line at x=ax=a needs the specific slope f(a)f'(a).
  • Using f(a)f(a) as the slope of the tangent line is wrong because f(a)f(a) is the height of the graph, while f(a)f'(a) is the slope.
  • Writing the tangent line through the wrong point is wrong because the tangent line at x=ax=a must pass through (a,f(a))(a,f(a)), not through (a,f(a))(a,f'(a)).

Practice Questions

  1. 1 For f(x)=x2+3xf(x)=x^2+3x, use f(a)=limh0f(a+h)f(a)hf'(a)=\lim_{h\to 0}\frac{f(a+h)-f(a)}{h} to find f(2)f'(2).
  2. 2 Find the equation of the tangent line to f(x)=x24x+1f(x)=x^2-4x+1 at x=3x=3.
  3. 3 Use the limit definition f(a)=limxaf(x)f(a)xaf'(a)=\lim_{x\to a}\frac{f(x)-f(a)}{x-a} to find f(1)f'(1) for f(x)=1xf(x)=\frac{1}{x}.
  4. 4 Explain why a function with a sharp corner at x=ax=a may fail to have a derivative at x=ax=a, even if the function is continuous there.