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This cheat sheet covers two powerful ways to find the area of a triangle when the height is not given directly. The sine area formula works when two sides and the included angle are known. Heron's formula works when all three side lengths are known.

Students need these methods for geometry, trigonometry, coordinate geometry, and problem solving with non-right triangles.

The most important formulas are K=12absinCK = \frac{1}{2}ab\sin C and K=s(sa)(sb)(sc)K = \sqrt{s(s-a)(s-b)(s-c)}. In the sine formula, CC must be the angle between sides aa and bb. In Heron's formula, the semiperimeter is s=a+b+c2s = \frac{a+b+c}{2}.

Both methods give the same area when the given measurements describe the same triangle.

Key Facts

  • The standard triangle area formula is K=12bhK = \frac{1}{2}bh, where bb is the base and hh is the perpendicular height.
  • The sine area formula is K=12absinCK = \frac{1}{2}ab\sin C, where CC is the included angle between sides aa and bb.
  • Equivalent sine area forms are K=12bcsinAK = \frac{1}{2}bc\sin A, K=12acsinBK = \frac{1}{2}ac\sin B, and K=12absinCK = \frac{1}{2}ab\sin C.
  • Heron's formula is K=s(sa)(sb)(sc)K = \sqrt{s(s-a)(s-b)(s-c)}, where aa, bb, and cc are the side lengths.
  • The semiperimeter is s=a+b+c2s = \frac{a+b+c}{2}, which is half of the triangle's perimeter.
  • Before using Heron's formula, the side lengths must satisfy the triangle inequality: a+b>ca+b>c, a+c>ba+c>b, and b+c>ab+c>a.
  • If the included angle is 9090^\circ, then K=12absin90=12abK = \frac{1}{2}ab\sin 90^\circ = \frac{1}{2}ab because sin90=1\sin 90^\circ = 1.
  • Area units are always square units, such as cm2\text{cm}^2, m2\text{m}^2, or in2\text{in}^2.

Vocabulary

Area
The area of a triangle is the amount of flat space inside it, measured in square units.
Included Angle
The included angle is the angle formed by two given sides of a triangle.
Sine
In triangle area problems, sinθ\sin \theta connects an angle to the perpendicular height created from a side.
Semiperimeter
The semiperimeter is half the perimeter of a triangle, given by s=a+b+c2s = \frac{a+b+c}{2}.
Heron's Formula
Heron's formula finds triangle area from three side lengths using K=s(sa)(sb)(sc)K = \sqrt{s(s-a)(s-b)(s-c)}.
Triangle Inequality
The triangle inequality says the sum of any two side lengths must be greater than the third side length.

Common Mistakes to Avoid

  • Using a non-included angle in K=12absinCK = \frac{1}{2}ab\sin C is wrong because CC must be the angle between sides aa and bb.
  • Forgetting to divide by 22 in the sine formula is wrong because triangle area is half the area of the related parallelogram.
  • Using the perimeter instead of the semiperimeter in Heron's formula is wrong because ss must equal a+b+c2\frac{a+b+c}{2}, not a+b+ca+b+c.
  • Skipping the triangle inequality check is risky because side lengths that do not satisfy a+b>ca+b>c, a+c>ba+c>b, and b+c>ab+c>a cannot form a triangle.
  • Reporting linear units instead of square units is wrong because area must be written in units such as cm2\text{cm}^2 or m2\text{m}^2.

Practice Questions

  1. 1 Find the area of a triangle with sides a=10 cma = 10\text{ cm} and b=14 cmb = 14\text{ cm} and included angle C=35C = 35^\circ.
  2. 2 Use Heron's formula to find the area of a triangle with side lengths a=8 ma = 8\text{ m}, b=9 mb = 9\text{ m}, and c=13 mc = 13\text{ m}.
  3. 3 A triangle has sides a=7 ina = 7\text{ in} and b=12 inb = 12\text{ in} with included angle C=90C = 90^\circ. Find its area.
  4. 4 Explain when you would choose K=12absinCK = \frac{1}{2}ab\sin C instead of Heron's formula, and why the included angle matters.