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Exponential growth and decay describe situations where a quantity changes by the same percent over equal time intervals. This cheat sheet helps students recognize exponential patterns, write equations, and interpret the meaning of each parameter. These models are important in algebra, finance, biology, chemistry, and real-world data analysis.

The basic exponential model is y=abxy = a b^{x}, where aa is the starting value and bb is the growth or decay factor. Growth happens when b>1b > 1, and decay happens when 0<b<10 < b < 1. Percent growth uses b=1+rb = 1 + r, while percent decay uses b=1rb = 1 - r, with rr written as a decimal.

Key Facts

  • The standard exponential model is y=abxy = a b^{x}, where aa is the initial value, bb is the constant factor, and xx is the number of equal time intervals.
  • Exponential growth has the form y=a(1+r)ty = a(1 + r)^{t}, where rr is the growth rate written as a decimal.
  • Exponential decay has the form y=a(1r)ty = a(1 - r)^{t}, where rr is the decay rate written as a decimal and 0<r<10 < r < 1.
  • The growth or decay factor can be found from two consecutive outputs using b=y2y1b = \frac{y_{2}}{y_{1}} when the input increases by 11.
  • For compound interest, the model is A=P(1+rn)ntA = P\left(1 + \frac{r}{n}\right)^{nt}, where PP is principal, rr is annual interest rate, nn is compounds per year, and tt is years.
  • Continuous growth or decay uses A=PertA = Pe^{rt}, where r>0r > 0 represents growth and r<0r < 0 represents decay.
  • Doubling time can be modeled by A=P2tdA = P \cdot 2^{\frac{t}{d}}, where dd is the time required for the quantity to double.
  • Half-life can be modeled by A=P(12)thA = P\left(\frac{1}{2}\right)^{\frac{t}{h}}, where hh is the time required for the quantity to decrease by half.

Vocabulary

Exponential Function
A function in which the variable appears in the exponent, commonly written as y=abxy = a b^{x}.
Initial Value
The starting amount in an exponential model, represented by aa in y=abxy = a b^{x}.
Growth Factor
The multiplier bb in an exponential growth model, where b>1b > 1.
Decay Factor
The multiplier bb in an exponential decay model, where 0<b<10 < b < 1.
Half-Life
The amount of time required for a decaying quantity to become half of its previous amount.
Compound Interest
Interest calculated on both the original principal and previously earned interest using A=P(1+rn)ntA = P\left(1 + \frac{r}{n}\right)^{nt}.

Common Mistakes to Avoid

  • Using rr instead of 1+r1 + r for growth is wrong because the base must include the original 100%100\% plus the percent increase.
  • Using 1+r1 + r for decay is wrong because decay reduces the amount, so the correct factor is 1r1 - r.
  • Writing a percent as a whole number is wrong because 8%8\% must be written as 0.080.08, not 88, in formulas such as y=a(1+r)ty = a(1 + r)^{t}.
  • Treating exponential change like linear change is wrong because exponential models multiply by a constant factor instead of adding a constant difference.
  • Forgetting to match time units is wrong because tt, doubling time, half-life, and compounding periods must all use consistent units.

Practice Questions

  1. 1 A population starts at 500500 and grows by 6%6\% each year. Write an exponential model for the population after tt years.
  2. 2 A car worth 2400024000 loses 12%12\% of its value each year. Find its value after 55 years using V=24000(10.12)5V = 24000(1 - 0.12)^{5}.
  3. 3 An investment of 15001500 earns 4%4\% annual interest compounded quarterly. Use A=1500(1+0.044)43A = 1500\left(1 + \frac{0.04}{4}\right)^{4 \cdot 3} to find the amount after 33 years.
  4. 4 A table of values shows outputs multiplied by 0.70.7 each time the input increases by 11. Explain whether the function represents exponential growth or exponential decay.

Understanding Exponential Growth & Decay Reference

A key clue is the difference between adding and multiplying. In a linear pattern, the amount added stays fixed. A savings balance might gain fifty dollars each month.

In an exponential pattern, the multiplier stays fixed. A population that rises by five percent each year does not add the same number of organisms each year. The increase becomes larger as the population grows.

Build a table to see this clearly. Find the ratio of each output to the previous output.

Matching ratios point to an exponential model. Matching differences point to a linear model.

Percent language causes many errors. A rate of eight percent means eight out of every one hundred, or zero point zero eight in decimal form. For growth, the full multiplier includes the original one hundred percent plus the change.

For decay, it includes what remains after the loss. A twenty percent decrease leaves eighty percent, not twenty percent.

This is why repeated discounts, depreciation, and population loss must be calculated from the current amount. Subtracting the same percent of the original amount each time creates a different kind of model.

Graphs of these models have useful features. With a positive starting amount, a growth graph rises slowly at first and then becomes steeper. A decay graph falls quickly at first and then flattens.

In ordinary decay situations, the graph approaches zero without reaching it. Zero is called a horizontal asymptote. It represents a limit in the mathematical model, though a real quantity may eventually be rounded to zero or stop being measured.

The starting value is the output when time is zero. Always check whether the time unit is days, months, years, or another equal interval. A monthly rate cannot be used directly with a number of years.

Compound interest shows why the number of compounding periods matters. Interest added once per year has a full year to grow before the next addition. Interest added monthly begins earning interest sooner.

The annual rate must therefore be divided among the periods, while the total number of periods must be counted over the whole investment time. Taxes, fees, and withdrawals can make real account balances differ from a simple model. Read carefully to determine whether a problem asks for the final balance, only the interest earned, or the original principal.

Doubling time and half life provide shortcuts for interpreting fast change. If a bacteria culture doubles every three hours, each three hour block multiplies the amount by two. If a medicine has a half life of six hours, each six hour block leaves half of what was present.

These statements describe repeated factors, not fixed additions or subtractions. When a time value is not an exact number of doubling periods or half lives, the exponent is a fraction. More advanced problems may require logarithms to solve for an unknown time.

Before using a calculator, estimate whether the answer should be greater or less than the starting amount. This simple check catches many sign, percent, and exponent mistakes.