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Logarithms help students solve equations where the variable is in an exponent. This cheat sheet summarizes the main logarithm properties used in Algebra 2, Precalculus, and advanced high school math. Students need these rules to simplify expressions, solve exponential equations, and understand inverse functions.

It is a quick reference for choosing the correct property without mixing up operations.

The most important idea is that logb(x)\log_b(x) answers the question, bb raised to what power equals xx. Logarithms turn multiplication into addition, division into subtraction, and powers into multiplication. The change of base formula lets students evaluate logs with bases not available on a calculator.

Domain restrictions matter because logb(x)\log_b(x) is defined only when b>0b>0, b1b\ne 1, and x>0x>0.

Key Facts

  • The logarithmic equation logb(x)=y\log_b(x)=y is equivalent to the exponential equation by=xb^y=x, where b>0b>0, b1b\ne 1, and x>0x>0.
  • The product property is logb(MN)=logb(M)+logb(N)\log_b(MN)=\log_b(M)+\log_b(N) for M>0M>0 and N>0N>0.
  • The quotient property is logb(MN)=logb(M)logb(N)\log_b\left(\frac{M}{N}\right)=\log_b(M)-\log_b(N) for M>0M>0 and N>0N>0.
  • The power property is logb(Mp)=plogb(M)\log_b(M^p)=p\log_b(M) for M>0M>0.
  • The change of base formula is logb(M)=loga(M)loga(b)\log_b(M)=\frac{\log_a(M)}{\log_a(b)}, where a>0a>0, a1a\ne 1, b>0b>0, and b1b\ne 1.
  • The inverse properties are logb(bx)=x\log_b(b^x)=x and blogb(x)=xb^{\log_b(x)}=x for x>0x>0.
  • The special values are logb(1)=0\log_b(1)=0 and logb(b)=1\log_b(b)=1 for b>0b>0 and b1b\ne 1.
  • A logarithm with base 1010 is written log(x)\log(x), and a logarithm with base ee is written ln(x)\ln(x).

Vocabulary

Logarithm
A logarithm logb(x)\log_b(x) is the exponent that base bb must be raised to in order to get xx.
Base
The base bb in logb(x)\log_b(x) is the number being raised to a power, and it must satisfy b>0b>0 and b1b\ne 1.
Argument
The argument is the input xx in logb(x)\log_b(x), and it must be positive.
Common Logarithm
A common logarithm is a logarithm with base 1010, written as log(x)\log(x).
Natural Logarithm
A natural logarithm is a logarithm with base ee, written as ln(x)\ln(x).
Change of Base
Change of base rewrites logb(M)\log_b(M) as loga(M)loga(b)\frac{\log_a(M)}{\log_a(b)} so it can be evaluated using another base.

Common Mistakes to Avoid

  • Writing logb(M+N)=logb(M)+logb(N)\log_b(M+N)=\log_b(M)+\log_b(N) is wrong because the product property works only for multiplication, not addition.
  • Writing logb(MN)=logb(M)logb(N)\log_b\left(\frac{M}{N}\right)=\frac{\log_b(M)}{\log_b(N)} is wrong because division inside a logarithm becomes subtraction, so the correct rule is logb(M)logb(N)\log_b(M)-\log_b(N).
  • Forgetting domain restrictions is wrong because logb(x)\log_b(x) is defined only when b>0b>0, b1b\ne 1, and x>0x>0.
  • Using the power property as logb(Mp)=(logb(M))p\log_b(M^p)=\left(\log_b(M)\right)^p is wrong because the exponent becomes a coefficient, so logb(Mp)=plogb(M)\log_b(M^p)=p\log_b(M).
  • Canceling incorrectly in expressions like logb(bx)\log_b(bx) is wrong because logb(bx)=logb(b)+logb(x)=1+logb(x)\log_b(bx)=\log_b(b)+\log_b(x)=1+\log_b(x), not xx.

Practice Questions

  1. 1 Rewrite log3(81)=4\log_3(81)=4 as an exponential equation.
  2. 2 Expand log2(8x3y)\log_2\left(\frac{8x^3}{y}\right) using logarithm properties, assuming x>0x>0 and y>0y>0.
  3. 3 Solve log5(x)=3\log_5(x)=3 for xx.
  4. 4 Explain why logb(M+N)\log_b(M+N) cannot be expanded as logb(M)+logb(N)\log_b(M)+\log_b(N), and describe which operation the product property actually applies to.