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Probability rules help students describe chance in a clear, organized way. This cheat sheet covers the formulas used to combine events, find complements, handle overlapping events, and solve conditional probability problems. It is useful for homework, tests, data analysis, and interpreting real-world situations involving risk or uncertainty. The most important ideas are that probabilities range from 00 to 11, complements add to 11, and overlapping events must be counted carefully. Conditional probability measures the chance that one event happens when another event is already known to have happened. Independence, multiplication rules, tree diagrams, and Bayes’ theorem help students connect multi-step probability situations.

Key Facts

  • Every probability satisfies 0P(A)10 \le P(A) \le 1, where P(A)=0P(A)=0 means impossible and P(A)=1P(A)=1 means certain.
  • The complement rule is P(Ac)=1P(A)P(A^c)=1-P(A), where AcA^c means the event AA does not occur.
  • The general addition rule is P(AB)=P(A)+P(B)P(AB)P(A\cup B)=P(A)+P(B)-P(A\cap B).
  • If events AA and BB are mutually exclusive, then P(AB)=0P(A\cap B)=0 and P(AB)=P(A)+P(B)P(A\cup B)=P(A)+P(B).
  • Conditional probability is P(AB)=P(AB)P(B)P(A\mid B)=\frac{P(A\cap B)}{P(B)}, as long as P(B)>0P(B)>0.
  • The general multiplication rule is P(AB)=P(A)P(BA)=P(B)P(AB)P(A\cap B)=P(A)P(B\mid A)=P(B)P(A\mid B).
  • Events AA and BB are independent if P(AB)=P(A)P(A\mid B)=P(A), which is equivalent to P(AB)=P(A)P(B)P(A\cap B)=P(A)P(B).
  • Bayes’ theorem is P(AB)=P(BA)P(A)P(B)P(A\mid B)=\frac{P(B\mid A)P(A)}{P(B)}, where P(B)>0P(B)>0.

Vocabulary

Event
An event is a set of outcomes from a probability experiment.
Sample Space
The sample space is the set of all possible outcomes of an experiment.
Complement
The complement of event AA, written AcA^c, is the event that AA does not happen.
Union
The union ABA\cup B is the event that AA happens, BB happens, or both happen.
Intersection
The intersection ABA\cap B is the event that both AA and BB happen.
Conditional Probability
Conditional probability P(AB)P(A\mid B) is the probability that AA occurs given that BB has already occurred.

Common Mistakes to Avoid

  • Adding overlapping events without subtracting the intersection is wrong because outcomes in ABA\cap B get counted twice in P(A)+P(B)P(A)+P(B).
  • Treating mutually exclusive events as independent is wrong because if AA and BB cannot both happen, knowing one occurred changes the probability of the other.
  • Reversing conditional probabilities is wrong because P(AB)P(A\mid B) and P(BA)P(B\mid A) usually describe different situations and are not usually equal.
  • Using P(AB)=P(A)P(B)P(A\cap B)=P(A)P(B) without checking independence is wrong because that formula only works when AA and BB are independent.
  • Forgetting that probabilities must stay between 00 and 11 is wrong because answers such as 1.21.2 or 0.1-0.1 cannot represent valid probabilities.

Practice Questions

  1. 1 If P(A)=0.45P(A)=0.45, P(B)=0.30P(B)=0.30, and P(AB)=0.12P(A\cap B)=0.12, find P(AB)P(A\cup B).
  2. 2 A class has 1818 students who play soccer, 1212 who play basketball, and 77 who play both. If one student is chosen at random, what is the probability the student plays soccer or basketball out of 3030 students?
  3. 3 If P(A)=0.60P(A)=0.60 and P(BA)=0.25P(B\mid A)=0.25, find P(AB)P(A\cap B).
  4. 4 Explain how you can tell from a two-way table whether two events are independent without relying only on the words in the problem.