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Integration by parts is a method for evaluating integrals of products of functions. It is especially useful when one factor becomes simpler after differentiation while the other is easy to integrate. This technique comes directly from the product rule for derivatives, so it connects differentiation and integration in a very natural way. Students use it often in calculus, differential equations, and physics.

The core formula is the udv=uvvdu\int u \, dv = uv - \int v \, du. You choose one part of the integrand to be uu and the other to be dvdv, then compute dudu and vv. A good choice makes the new integral simpler than the original one. Common examples include products such as xexx e^x, xsinxx \sin x, and xlnxx \ln x, and repeated use can handle higher powers like x2exx^2 e^x.

Key Facts

  • Integration by parts formula: udv=uvvdu\int u \, dv = uv - \int v \, du
  • It comes from the product rule: ddx(uv)=udvdx+vdudx\frac{d}{dx}(uv) = u \frac{dv}{dx} + v \frac{du}{dx}
  • Definite integral form: abudv=[uv]ababvdu\int_a^b u \, dv = [uv]_a^b - \int_a^b v \, du
  • Choose u so that differentiating it simplifies it, and choose dv so that integrating it is straightforward
  • A common guide is LIATE: Logarithmic, Inverse trig, Algebraic, Trig, Exponential
  • Repeated integration by parts is often needed for integrals like xnexdx\int x^n e^x \, dx or xnsinxdx\int x^n \sin x \, dx

Vocabulary

Integrand
The integrand is the expression inside an integral that is being integrated.
u
In integration by parts, u is the factor chosen to be differentiated into du.
dv
In integration by parts, dv is the factor chosen to be integrated into v.
Product rule
The product rule states that ddx(uv)=udvdx+vdudx\frac{d}{dx}(uv) = u \frac{dv}{dx} + v \frac{du}{dx} for two functions multiplied together.
LIATE
LIATE is a guideline for choosing u by preferring logarithmic, inverse trigonometric, algebraic, trigonometric, then exponential functions.

Common Mistakes to Avoid

  • Choosing uu and dvdv poorly, which makes the new integral harder than the original. Pick uu so differentiation simplifies it and dvdv so integration is easy.
  • Forgetting the minus sign in the formula, which changes the final answer. Write the full formula before substituting.
  • Differentiating or integrating the chosen parts incorrectly, especially when finding du or v. Check each derivative and antiderivative separately before continuing.
  • Ignoring the boundary term in definite integrals, which loses part of the answer. After finding uvuv, evaluate [uv][uv] from aa to bb before computing the remaining integral.

Practice Questions

  1. 1 Use integration by parts to evaluate the integral of xexdxx e^x \, dx.
  2. 2 Use integration by parts to evaluate the integral of xcosxdxx \cos x \, dx.
  3. 3 For the integral of xlnxdxx \ln x \, dx, explain why choosing u=lnxu = \ln x and dv=xdxdv = x \, dx is usually better than choosing u=xu = x and dv=lnxdxdv = \ln x \, dx.