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Epsilon-Delta Definition of a Limit Worked Examples cheat sheet - grade college

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The epsilon-delta definition of a limit is the formal way calculus explains what it means for a function to approach a value. This cheat sheet helps students turn the definition into a clear proof strategy instead of a memorized sentence. It focuses on worked-example patterns for linear, quadratic, rational, and absolute value limits.

Students need this reference because epsilon-delta proofs require both algebraic control and precise logical wording.

The central idea is to make f(x)L<ε|f(x)-L|<\varepsilon happen by requiring 0<xa<δ0<|x-a|<\delta. Most examples work by rewriting or bounding f(x)L|f(x)-L| in terms of xa|x-a|. Once a useful inequality is found, choose δ\delta as a function of ε\varepsilon, often using a minimum such as δ=min{1,ε5}\delta=\min\{1,\frac{\varepsilon}{5}\}.

A complete proof states the choice of δ\delta, assumes 0<xa<δ0<|x-a|<\delta, and then shows f(x)L<ε|f(x)-L|<\varepsilon.

Key Facts

  • The formal definition is limxaf(x)=L\lim_{x\to a} f(x)=L if for every ε>0\varepsilon>0 there exists δ>0\delta>0 such that 0<xa<δ0<|x-a|<\delta implies f(x)L<ε|f(x)-L|<\varepsilon.
  • For a linear function f(x)=mx+bf(x)=mx+b, the limit proof often uses f(x)L=mxa|f(x)-L|=|m||x-a|, so choosing δ=εm\delta=\frac{\varepsilon}{|m|} works when m0m\ne0.
  • For limxax2=a2\lim_{x\to a} x^2=a^2, use x2a2=xax+a|x^2-a^2|=|x-a||x+a| and bound x+a|x+a| by first forcing xa<1|x-a|<1.
  • A common quadratic choice is δ=min{1,ε2a+1}\delta=\min\{1,\frac{\varepsilon}{2|a|+1}\} because x+a<2a+1|x+a|<2|a|+1 when xa<1|x-a|<1.
  • For a rational function, factor or combine fractions first, then use a restriction such as xa<1|x-a|<1 to keep denominators away from 00.
  • The condition 0<xa0<|x-a| means xx may approach aa but does not have to equal aa, so the function value f(a)f(a) may be undefined.
  • The number δ\delta is allowed to depend on ε\varepsilon, but it must be positive and chosen before assuming 0<xa<δ0<|x-a|<\delta.
  • Using δ=min{c,g(ε)}\delta=\min\{c,g(\varepsilon)\} lets one condition control nearby behavior while another condition guarantees f(x)L<ε|f(x)-L|<\varepsilon.

Vocabulary

Epsilon
Epsilon, written ε\varepsilon, is a positive tolerance for how close f(x)f(x) must be to the limit value LL.
Delta
Delta, written δ\delta, is a positive distance from aa that controls how close xx must be to aa.
Limit
The limit limxaf(x)=L\lim_{x\to a} f(x)=L means f(x)f(x) can be made arbitrarily close to LL by taking xx sufficiently close to aa.
Punctured neighborhood
A punctured neighborhood of aa is the set of points satisfying 0<xa<δ0<|x-a|<\delta.
Bounding
Bounding is the process of replacing a difficult factor with a simpler upper estimate, such as using x+a<2a+1|x+a|<2|a|+1.
Minimum choice
A minimum choice such as δ=min{1,ε5}\delta=\min\{1,\frac{\varepsilon}{5}\} enforces multiple inequalities at the same time.

Common Mistakes to Avoid

  • Choosing δ\delta before analyzing f(x)L|f(x)-L| is wrong because the proof must show exactly how closeness in xx forces closeness in f(x)f(x).
  • Forgetting the condition 0<xa0<|x-a| is wrong because the epsilon-delta definition concerns values near aa, not necessarily the value at aa.
  • Using δ=ε\delta=\varepsilon in every problem is wrong because nonlinear expressions such as x2a2|x^2-a^2| usually require extra bounds.
  • Dividing by a quantity that might be 00 is wrong because rational limit proofs must first restrict xx so the denominator stays safely away from 00.
  • Proving only one numerical case such as ε=0.01\varepsilon=0.01 is wrong because the definition requires the argument to work for every ε>0\varepsilon>0.

Practice Questions

  1. 1 Prove using the epsilon-delta definition that limx3(2x1)=5\lim_{x\to 3}(2x-1)=5, and give an explicit formula for δ\delta in terms of ε\varepsilon.
  2. 2 Prove that limx2x2=4\lim_{x\to 2}x^2=4 by bounding x+2|x+2| after assuming x2<1|x-2|<1.
  3. 3 Find a valid δ\delta choice for proving limx1x21x1=2\lim_{x\to 1}\frac{x^2-1}{x-1}=2 for x1x\ne1.
  4. 4 Explain why the value of f(a)f(a) does not affect whether limxaf(x)=L\lim_{x\to a}f(x)=L exists under the epsilon-delta definition.

Understanding Epsilon-Delta Definition of a Limit Worked Examples

The difficulty in these proofs comes from the order of the choices. Think of epsilon as an error allowance set by someone else. Your job is to give a positive delta that works for that allowance.

Only after delta is fixed do you consider an input within that distance of the target point. This order prevents circular reasoning. A proof cannot say that the input is close enough without explaining what close enough means.

The proof must give a rule that works for every positive output tolerance, including extremely small ones. This is why a limit is a stronger statement than checking a table of nearby values.

A useful working method is to begin at the output side and work backward. For a polynomial, factor the difference before trying to choose delta. Suppose the input approaches two in a cubic function.

The output error is the absolute difference between the input cubed and eight. Factoring produces the input distance from two multiplied by the expression input squared plus two times input plus four. The first factor is controllable by delta.

The second factor needs a temporary bound. If the input distance from two is less than one, then the input lies between one and three. The second factor is then less than nineteen.

The output error is therefore less than nineteen times the input distance. Choosing delta no larger than epsilon divided by nineteen finishes the job.

The temporary restriction is not arbitrary. It turns a changing expression into a fixed numerical bound.

Rational functions need extra care because a denominator can become dangerously small. Near two, the function one divided by the input has values close to one half, but only because inputs near two stay away from zero. Requiring the input distance from two to be less than one guarantees that the input is greater than one.

This gives a safe lower bound for the denominator before the rest of the error is estimated. The same idea appears in science and computing whenever a calculation divides by a measured quantity.

Small measurement errors can become large output errors near zero. Epsilon-delta reasoning makes that risk visible and gives a way to control it.

When writing a proof, separate discovery from presentation. Scratch work may include guesses, rough bounds, and failed choices. The final proof should be clean.

State the chosen delta, explain why it is positive, assume the required input condition, then show each inequality in order until the output error is below epsilon. Watch the direction of inequalities carefully. A lower bound is usually needed for a denominator, while an upper bound is usually needed for a multiplying factor.

Do not try to make every bound sharp. A simple bound that works is better than a complicated best possible bound. With practice, the main skill becomes recognizing which part of an expression needs local control.