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Systems of linear ordinary differential equations use matrices to describe how several dependent variables change together. This cheat sheet covers first order homogeneous systems of the form x=Ax\mathbf{x}' = A\mathbf{x} and how eigenvalues determine solution behavior. It is useful when moving from single differential equations to coupled systems in calculus, differential equations, engineering, and physics.

The goal is to recognize the eigenvalue case quickly and write the correct general solution form.

Key Facts

  • A homogeneous linear system is written as x=Ax\mathbf{x}' = A\mathbf{x}, where x(t)\mathbf{x}(t) is a vector of unknown functions and AA is a constant matrix.
  • Eigenvalues are found from the characteristic equation det(AλI)=0\det(A - \lambda I) = 0.
  • For a real eigenvalue λ\lambda with eigenvector v\mathbf{v}, one solution is x(t)=eλtv\mathbf{x}(t) = e^{\lambda t}\mathbf{v}.
  • If AA has nn linearly independent eigenvectors v1,,vn\mathbf{v}_1,\ldots,\mathbf{v}_n, then x(t)=c1eλ1tv1++cneλntvn\mathbf{x}(t) = c_1 e^{\lambda_1 t}\mathbf{v}_1 + \cdots + c_n e^{\lambda_n t}\mathbf{v}_n.
  • For a repeated eigenvalue λ\lambda with one eigenvector v\mathbf{v} and generalized eigenvector w\mathbf{w} satisfying (AλI)w=v(A - \lambda I)\mathbf{w} = \mathbf{v}, two solutions are eλtve^{\lambda t}\mathbf{v} and eλt(tv+w)e^{\lambda t}(t\mathbf{v} + \mathbf{w}).
  • For complex eigenvalues λ=α±iβ\lambda = \alpha \pm i\beta with eigenvector v=p+iq\mathbf{v} = \mathbf{p} + i\mathbf{q}, real solutions come from eαt(pcos(βt)qsin(βt))e^{\alpha t}\left(\mathbf{p}\cos(\beta t) - \mathbf{q}\sin(\beta t)\right) and eαt(psin(βt)+qcos(βt))e^{\alpha t}\left(\mathbf{p}\sin(\beta t) + \mathbf{q}\cos(\beta t)\right).
  • The sign of Re(λ)\operatorname{Re}(\lambda) determines growth or decay: Re(λ)<0\operatorname{Re}(\lambda) < 0 gives decay, Re(λ)>0\operatorname{Re}(\lambda) > 0 gives growth, and Re(λ)=0\operatorname{Re}(\lambda) = 0 gives neutral oscillation in the linear model.
  • Initial conditions are applied by substituting t=0t = 0 into the general solution and solving for the constants c1,c2,,cnc_1,c_2,\ldots,c_n.

Vocabulary

Linear system
A set of differential equations that can be written in matrix form as x=Ax\mathbf{x}' = A\mathbf{x} for a constant matrix AA.
Eigenvalue
A scalar λ\lambda such that Av=λvA\mathbf{v} = \lambda\mathbf{v} for some nonzero vector v\mathbf{v}.
Eigenvector
A nonzero vector v\mathbf{v} that keeps its direction under multiplication by AA, changing only by the factor λ\lambda.
Generalized eigenvector
A vector w\mathbf{w} used for defective repeated eigenvalues, satisfying (AλI)w=v(A - \lambda I)\mathbf{w} = \mathbf{v}.
Fundamental solution set
A linearly independent collection of solution vectors that can be combined to form every solution of the system.
Phase portrait
A geometric picture of solution curves in the state plane showing how the vector x(t)\mathbf{x}(t) evolves over time.

Common Mistakes to Avoid

  • Using det(λIA)\det(\lambda I - A) inconsistently with det(AλI)\det(A - \lambda I), which can change signs in intermediate steps. The roots are the same, but algebra errors often appear if the convention is switched mid-problem.
  • Forgetting that eigenvectors are vectors, not constants, which leads to writing eλte^{\lambda t} alone instead of eλtve^{\lambda t}\mathbf{v}.
  • Treating a repeated eigenvalue as automatically giving two independent eigenvectors, which is not always true. If there is only one eigenvector, a generalized eigenvector must be used.
  • Leaving complex-valued solutions as the final answer for a real system, which misses the required real solution basis. Use real and imaginary parts to form real solutions.
  • Applying the initial condition before forming the full general solution, which can eliminate necessary constants. First build the complete solution, then substitute t=0t = 0.

Practice Questions

  1. 1 Find the eigenvalues and eigenvectors of A=(3102)A = \begin{pmatrix} 3 & 1 \\ 0 & 2 \end{pmatrix}, then write the general solution to x=Ax\mathbf{x}' = A\mathbf{x}.
  2. 2 Solve the initial value problem x=(1002)x\mathbf{x}' = \begin{pmatrix} 1 & 0 \\ 0 & -2 \end{pmatrix}\mathbf{x} with x(0)=(43)\mathbf{x}(0) = \begin{pmatrix} 4 \\ -3 \end{pmatrix}.
  3. 3 For A=(0550)A = \begin{pmatrix} 0 & -5 \\ 5 & 0 \end{pmatrix}, find the complex eigenvalues and describe the real solution behavior.
  4. 4 Explain how the long-term behavior of solutions changes when all eigenvalues satisfy Re(λ)<0\operatorname{Re}(\lambda) < 0 compared with when at least one eigenvalue satisfies Re(λ)>0\operatorname{Re}(\lambda) > 0.