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Organic Chemistry II Spectroscopy IR, NMR, MS cheat sheet - grade college

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This cheat sheet covers the core spectroscopy tools used in Organic Chemistry II: IR, NMR, and mass spectrometry. Students need these methods to identify functional groups, carbon frameworks, hydrogen environments, molecular masses, and likely molecular formulas. A compact reference helps connect spectral signals to structural evidence during homework, exams, and lab analysis.

The goal is to turn several spectra into one consistent structure rather than interpret each spectrum in isolation.

IR spectroscopy is most useful for recognizing key bonds and functional groups from diagnostic absorption ranges. 1H^1\mathrm{H} NMR and 13C^{13}\mathrm{C} NMR reveal chemical environments, splitting patterns, integration, and symmetry. Mass spectrometry gives molecular ion information, isotope patterns, and fragmentation clues.

Structure identification works best when you combine molecular formula, degrees of unsaturation, IR peaks, NMR data, and MS fragments into one evidence-based proposal.

Key Facts

  • The degree of unsaturation is DBE=2C+2+NHX2\mathrm{DBE} = \frac{2C + 2 + N - H - X}{2}, where XX counts halogens and oxygen is ignored.
  • A broad IR absorption near 3200 cm13200\text{ cm}^{-1} to 3600 cm13600\text{ cm}^{-1} often indicates an OH\mathrm{O-H} stretch, while a sharper peak near 3300 cm13300\text{ cm}^{-1} can indicate an NH\mathrm{N-H} or terminal alkyne CH\mathrm{C-H} stretch.
  • A strong IR absorption near 1650 cm11650\text{ cm}^{-1} to 1750 cm11750\text{ cm}^{-1} usually indicates a carbonyl C=O\mathrm{C=O} group.
  • In 1H^1\mathrm{H} NMR, the approximate splitting rule is n+1n + 1, meaning nn equivalent neighboring hydrogens split a signal into n+1n + 1 peaks.
  • In 1H^1\mathrm{H} NMR, integration is proportional to the number of hydrogens producing a signal, so a 3:2:13:2:1 integral ratio can represent 33, 22, and 11 hydrogens or any whole-number multiple.
  • Typical 1H^1\mathrm{H} NMR chemical shifts include alkyl protons at 0.8 ppm0.8\text{ ppm} to 2.0 ppm2.0\text{ ppm}, protons next to electronegative atoms at 3.0 ppm3.0\text{ ppm} to 4.5 ppm4.5\text{ ppm}, alkene protons at 4.5 ppm4.5\text{ ppm} to 6.5 ppm6.5\text{ ppm}, aromatic protons at 6.5 ppm6.5\text{ ppm} to 8.5 ppm8.5\text{ ppm}, and aldehyde protons near 9 ppm9\text{ ppm} to 10 ppm10\text{ ppm}.
  • In mass spectrometry, the molecular ion peak M+M^+ gives the molecular mass when it is visible, while the base peak is the tallest peak and is assigned 100%100\% relative intensity.
  • A chlorine-containing compound often shows an M:M+2M:M+2 isotope pattern of about 3:13:1, while a bromine-containing compound often shows an M:M+2M:M+2 pattern of about 1:11:1.

Vocabulary

Infrared spectroscopy
Infrared spectroscopy identifies bonds and functional groups by measuring the frequencies at which molecular bonds absorb IR radiation.
Chemical shift
Chemical shift is the position of an NMR signal in ppm\mathrm{ppm} relative to a reference standard and reflects the electronic environment of a nucleus.
Integration
Integration is the area under a 1H^1\mathrm{H} NMR signal and is proportional to the number of hydrogens in that environment.
Spin-spin splitting
Spin-spin splitting is the division of an NMR signal caused by neighboring nonequivalent nuclei, commonly estimated by the n+1n + 1 rule.
Molecular ion
The molecular ion is the ionized intact molecule, shown as M+M^+, and its m/zm/z value often equals the molecular mass.
Base peak
The base peak is the most intense peak in a mass spectrum and is assigned a relative abundance of 100%100\%.

Common Mistakes to Avoid

  • Using every IR peak as equally diagnostic is wrong because the fingerprint region below about 1500 cm11500\text{ cm}^{-1} is complex and is usually less useful than strong functional-group absorptions.
  • Assuming a missing M+M^+ peak means there is no molecular mass information is wrong because some compounds fragment easily, so isotope peaks and high-mass fragments may still provide clues.
  • Treating NMR integration as exact atom counts is wrong because integrations give ratios first and must be scaled to match the molecular formula.
  • Applying the n+1n + 1 rule to all NMR signals is wrong because equivalent neighbors do not split each other and exchangeable OH\mathrm{O-H} or NH\mathrm{N-H} protons may appear broad or unsplit.
  • Choosing a structure from one spectrum alone is wrong because IR, NMR, MS, and the molecular formula must all agree with the same proposed structure.

Practice Questions

  1. 1 A compound has formula C6H10O\mathrm{C_6H_{10}O} and a strong IR peak at 1715 cm11715\text{ cm}^{-1}. Calculate the degree of unsaturation and identify the likely functional group.
  2. 2 A 1H^1\mathrm{H} NMR signal integrates to 3H3\mathrm{H} and is split into a triplet by neighboring hydrogens. How many equivalent neighboring hydrogens caused the splitting?
  3. 3 A mass spectrum shows molecular ion peaks at m/z=122m/z = 122 and m/z=124m/z = 124 with nearly equal intensity. What halogen pattern is suggested, and why?
  4. 4 A proposed structure contains an alcohol, but the IR spectrum has no broad absorption near 3200 cm13200\text{ cm}^{-1} to 3600 cm13600\text{ cm}^{-1} and the 1H^1\mathrm{H} NMR has no exchangeable proton signal. Explain how this affects confidence in the structure.