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This cheat sheet covers how alcohols oxidize into aldehydes, ketones, and carboxylic acids. It helps students predict products from alcohol structure, choose suitable reagents, and recognize when oxidation stops. These patterns are essential for organic synthesis, reaction pathways, and exam product-prediction questions.

The most important idea is that primary, secondary, and tertiary alcohols behave differently. Primary alcohols can form aldehydes or carboxylic acids depending on reagent strength and conditions. Secondary alcohols form ketones, while tertiary alcohols usually resist oxidation because they lack the required hydrogen on the alcohol-bearing carbon.

Key Facts

  • A primary alcohol oxidizes first by RCH2OH+[O]RCHO+H2O\mathrm{RCH_2OH + [O] \rightarrow RCHO + H_2O} to form an aldehyde.
  • With excess strong oxidant, a primary alcohol continues by RCHO+[O]RCOOH\mathrm{RCHO + [O] \rightarrow RCOOH} to form a carboxylic acid.
  • A secondary alcohol oxidizes by R2CHOH+[O]R2C=O+H2O\mathrm{R_2CHOH + [O] \rightarrow R_2C{=}O + H_2O} to form a ketone.
  • A tertiary alcohol usually does not oxidize under normal classroom conditions because the carbon attached to OH\mathrm{OH} has no CH\mathrm{C-H} bond.
  • Mild, anhydrous oxidants such as PCC\mathrm{PCC} are used to stop primary alcohol oxidation at the aldehyde stage.
  • Strong oxidants such as acidified K2Cr2O7\mathrm{K_2Cr_2O_7} or KMnO4\mathrm{KMnO_4} often convert primary alcohols fully to carboxylic acids.
  • Oxidation of an organic molecule usually increases its number of CO\mathrm{C-O} bonds or decreases its number of CH\mathrm{C-H} bonds.
  • The carbonyl group in aldehydes and ketones is written as C=O\mathrm{C{=}O}, while the carboxyl group in acids is written as COOH\mathrm{COOH}.

Vocabulary

Oxidation
Oxidation is a reaction that increases bonding to oxygen, decreases bonding to hydrogen, or raises the oxidation state of carbon.
Primary alcohol
A primary alcohol has the OH\mathrm{OH} group on a carbon attached to only one other carbon, often written as RCH2OH\mathrm{RCH_2OH}.
Secondary alcohol
A secondary alcohol has the OH\mathrm{OH} group on a carbon attached to two other carbons, often written as R2CHOH\mathrm{R_2CHOH}.
Tertiary alcohol
A tertiary alcohol has the OH\mathrm{OH} group on a carbon attached to three other carbons, often written as R3COH\mathrm{R_3COH}.
Aldehyde
An aldehyde is a carbonyl compound with the group RCHO\mathrm{RCHO} at the end of a carbon chain.
Ketone
A ketone is a carbonyl compound with the group R2C=O\mathrm{R_2C{=}O} within a carbon chain.

Common Mistakes to Avoid

  • Oxidizing every alcohol to a carboxylic acid is wrong because secondary alcohols stop at ketones and tertiary alcohols usually do not oxidize.
  • Using PCC\mathrm{PCC} and expecting a carboxylic acid is wrong because PCC\mathrm{PCC} is a mild, anhydrous oxidant that usually stops primary alcohols at aldehydes.
  • Forgetting that aldehydes oxidize further is wrong because RCHO\mathrm{RCHO} can become RCOOH\mathrm{RCOOH} with strong oxidants and water present.
  • Calling the product of secondary alcohol oxidation an aldehyde is wrong because removing hydrogen from R2CHOH\mathrm{R_2CHOH} forms R2C=O\mathrm{R_2C{=}O}, a ketone.
  • Predicting oxidation of a tertiary alcohol without carbon skeleton breaking is wrong because the alcohol-bearing carbon has no CH\mathrm{C-H} bond needed for normal oxidation.

Practice Questions

  1. 1 Predict the product when CH3CH2OH\mathrm{CH_3CH_2OH} is treated with PCC\mathrm{PCC} under anhydrous conditions.
  2. 2 If 0.250 mol0.250\ \mathrm{mol} of CH3CH2OH\mathrm{CH_3CH_2OH} is completely oxidized to CH3COOH\mathrm{CH_3COOH}, how many moles of CH3COOH\mathrm{CH_3COOH} can form?
  3. 3 A sample contains 5.00 g5.00\ \mathrm{g} of propan-2-ol, C3H8O\mathrm{C_3H_8O}. Assuming complete oxidation to propanone, C3H6O\mathrm{C_3H_6O}, how many grams of propanone form if the mole ratio is 1:11:1?
  4. 4 Explain why butan-2-ol can be oxidized under normal conditions but 2-methylpropan-2-ol usually cannot.