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Mathematical proof techniques are the standard tools used to justify claims in higher mathematics. This cheat sheet organizes the major methods students use in discrete math, abstract algebra, analysis, number theory, and proof-based courses. It helps students choose an appropriate proof strategy, structure an argument clearly, and avoid common logical errors.

The focus is on readable college-level reference notes rather than memorizing isolated facts.

Core implication methods prove statements of the form PQP \Rightarrow Q by direct reasoning, contrapositive proof, contradiction, or cases. Induction methods prove statements indexed by natural numbers, usually by establishing a base case and an induction step. Existence and construction proofs show that at least one object satisfies a property, while uniqueness proofs show that no two different objects can satisfy it.

Disproof usually requires only one valid counterexample to a universal claim.

Key Facts

  • A direct proof of PQP \Rightarrow Q assumes PP is true and uses definitions, known results, and valid algebra to derive QQ.
  • A contrapositive proof uses the logically equivalent statement ¬Q¬P\neg Q \Rightarrow \neg P to prove PQP \Rightarrow Q.
  • A proof by contradiction assumes PP is true and QQ is false, then derives an impossibility such as R¬RR \land \neg R.
  • To prove xS, P(x)\forall x \in S,\ P(x) by cases, split SS into exhaustive cases S1,S2,,SkS_1, S_2, \ldots, S_k and prove P(x)P(x) in every case.
  • Weak induction proves P(n)P(n) for all nn0n \geq n_0 by proving P(n0)P(n_0) and then proving P(k)P(k+1)P(k) \Rightarrow P(k+1) for every kn0k \geq n_0.
  • Strong induction proves P(n)P(n) for all nn0n \geq n_0 by proving base cases and then proving P(n0)P(k)P(k+1)P(n_0) \land \cdots \land P(k) \Rightarrow P(k+1).
  • An existence proof establishes xS\exists x \in S such that P(x)P(x), either by constructing such an xx or proving one must exist indirectly.
  • To prove uniqueness, first prove existence of an object xx with property P(x)P(x), then prove that if P(a)P(a) and P(b)P(b), then a=ba=b.

Vocabulary

Implication
An implication is a statement of the form PQP \Rightarrow Q, meaning that whenever PP is true, QQ must also be true.
Contrapositive
The contrapositive of PQP \Rightarrow Q is ¬Q¬P\neg Q \Rightarrow \neg P, and it is logically equivalent to the original implication.
Contradiction
A contradiction is a statement that cannot be true, such as R¬RR \land \neg R or an equation like 0=10=1.
Induction Hypothesis
The induction hypothesis is the temporary assumption that P(k)P(k), or several earlier statements, are true during the induction step.
Counterexample
A counterexample is one specific value or object that makes a universal statement x, P(x)\forall x,\ P(x) false.
Uniqueness
Uniqueness means that at most one object satisfies a property, often proved by showing P(a)P(b)a=bP(a) \land P(b) \Rightarrow a=b.

Common Mistakes to Avoid

  • Assuming the conclusion in a direct proof is circular reasoning because it uses QQ before proving that PQP \Rightarrow Q is valid.
  • Proving the converse instead of the original statement is wrong because QPQ \Rightarrow P is not logically equivalent to PQP \Rightarrow Q.
  • Skipping the base case in induction is invalid because the induction step only transfers truth from one case to the next and does not start the chain.
  • Using a non-exhaustive case split is incomplete because the proof may ignore elements of the domain where the statement could fail.
  • Giving an example for a universal statement is insufficient because showing P(a)P(a) for one value does not prove xS, P(x)\forall x \in S,\ P(x).

Practice Questions

  1. 1 Prove directly that if nn is an even integer, then n2n^2 is even.
  2. 2 Use contrapositive proof to show that if n2n^2 is odd, then nn is odd.
  3. 3 Use induction to prove that 1+2++n=n(n+1)21+2+\cdots+n=\frac{n(n+1)}{2} for every integer n1n \geq 1.
  4. 4 For the claim xR, x2x\forall x \in \mathbb{R},\ x^2 \geq x, decide whether to prove it or disprove it, and explain which proof technique is appropriate.