Probability & Combinatorics cheat sheet - grade 9-11

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Math Grade 9-11

Probability & Combinatorics Cheat Sheet

A printable reference covering sample spaces, probability rules, permutations, combinations, factorials, and conditional probability for grades 9-11.

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Probability and combinatorics help students count possible outcomes and measure how likely events are. This cheat sheet covers sample spaces, events, probability rules, permutations, combinations, and conditional probability. Students need these tools for games of chance, surveys, genetics, simulations, and many standardized test problems. A clear reference makes it easier to decide which counting method or probability formula applies. The core idea is that probability compares favorable outcomes to total outcomes, often written as P(A)=favorable outcomestotal outcomesP(A)=\frac{\text{favorable outcomes}}{\text{total outcomes}}. Combinatorics provides counting shortcuts such as n!n!, nPr=n!(nr)!_nP_r=\frac{n!}{(n-r)!}, and nCr=n!r!(nr)!_nC_r=\frac{n!}{r!(n-r)!}. Probability rules such as P(Ac)=1P(A)P(A^c)=1-P(A) and P(AB)=P(A)+P(B)P(AB)P(A\cup B)=P(A)+P(B)-P(A\cap B) help organize overlapping and related events. Conditional probability uses P(AB)=P(AB)P(B)P(A\mid B)=\frac{P(A\cap B)}{P(B)} to update probability when new information is known.

Key Facts

  • The probability of an event is P(A)=number of outcomes in Anumber of outcomes in the sample spaceP(A)=\frac{\text{number of outcomes in }A}{\text{number of outcomes in the sample space}} when all outcomes are equally likely.
  • Every probability must satisfy 0P(A)10\le P(A)\le 1, where 00 means impossible and 11 means certain.
  • The complement rule is P(Ac)=1P(A)P(A^c)=1-P(A), so the probability that AA does not happen is found by subtracting from 11.
  • The addition rule is P(AB)=P(A)+P(B)P(AB)P(A\cup B)=P(A)+P(B)-P(A\cap B), and for mutually exclusive events it becomes P(AB)=P(A)+P(B)P(A\cup B)=P(A)+P(B).
  • For independent events, the multiplication rule is P(AB)=P(A)P(B)P(A\cap B)=P(A)P(B).
  • The number of permutations of rr objects chosen from nn objects is nPr=n!(nr)!_nP_r=\frac{n!}{(n-r)!} when order matters.
  • The number of combinations of rr objects chosen from nn objects is nCr=n!r!(nr)!_nC_r=\frac{n!}{r!(n-r)!} when order does not matter.
  • Conditional probability is P(AB)=P(AB)P(B)P(A\mid B)=\frac{P(A\cap B)}{P(B)}, where P(B)0P(B)\ne 0.

Vocabulary

Sample Space
The sample space is the set of all possible outcomes of an experiment.
Event
An event is a subset of the sample space that contains the outcomes being considered.
Complement
The complement of event AA, written AcA^c, is the event that AA does not occur.
Independent Events
Independent events are events where the occurrence of one event does not change the probability of the other.
Permutation
A permutation is an arrangement in which order matters, counted by nPr=n!(nr)!_nP_r=\frac{n!}{(n-r)!}.
Combination
A combination is a selection in which order does not matter, counted by nCr=n!r!(nr)!_nC_r=\frac{n!}{r!(n-r)!}.

Common Mistakes to Avoid

  • Using permutations when order does not matter is wrong because it counts the same group multiple times. Use nCr_nC_r for selections and nPr_nP_r for arrangements.
  • Forgetting to subtract the overlap in P(AB)P(A\cup B) is wrong because outcomes in ABA\cap B get counted twice. Use P(AB)=P(A)+P(B)P(AB)P(A\cup B)=P(A)+P(B)-P(A\cap B).
  • Treating dependent events as independent is wrong because the first event can change the probability of the second event. Use conditional probability or adjust the sample space after the first outcome.
  • Using nrn^r when choices cannot repeat is wrong because nrn^r assumes each choice has the same number of options every time. For no repetition, use a decreasing product or nPr_nP_r.
  • Confusing P(AB)P(A\mid B) with P(BA)P(B\mid A) is wrong because the given information is different. P(AB)P(A\mid B) means event BB is already known to have happened.

Practice Questions

  1. 1 A bag has 55 red marbles, 33 blue marbles, and 22 green marbles. What is the probability of choosing a blue marble?
  2. 2 How many different 44-letter arrangements can be made from 88 distinct letters if no letter is repeated?
  3. 3 A committee of 33 students is chosen from 1010 students. How many different committees are possible?
  4. 4 Explain how you can tell whether a problem should use a permutation or a combination without doing any calculation.