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Transformers use changing magnetic flux to transfer electrical energy between circuits without direct electrical contact. This cheat sheet covers ideal transformer ratios, mutual inductance, induced emf, power transfer, and common real-world losses. Students need these relationships to solve alternating current circuit problems and to understand how voltage is stepped up or stepped down in power systems.

The main ideas come from Faraday’s law and the link between changing current and changing magnetic flux. In an ideal transformer, the voltage ratio equals the turns ratio, while the current ratio is the inverse of the turns ratio. Mutual inductance connects one coil’s changing current to the emf induced in another coil, using formulas such as E2=MdI1dt\mathcal{E}_2 = -M\frac{dI_1}{dt}.

Key Facts

  • For an ideal transformer, the voltage ratio equals the turns ratio: VsVp=NsNp\frac{V_s}{V_p} = \frac{N_s}{N_p}.
  • For an ideal transformer, the current ratio is inverse to the turns ratio: IsIp=NpNs\frac{I_s}{I_p} = \frac{N_p}{N_s}.
  • Ideal transformer power is conserved, so Pp=PsP_p = P_s and VpIp=VsIsV_p I_p = V_s I_s.
  • A step-up transformer has Ns>NpN_s > N_p and increases voltage according to Vs>VpV_s > V_p.
  • A step-down transformer has Ns<NpN_s < N_p and decreases voltage according to Vs<VpV_s < V_p.
  • Mutual inductance relates induced emf in one coil to changing current in another: E2=MdI1dt\mathcal{E}_2 = -M\frac{dI_1}{dt}.
  • For a coil, self-induced emf is given by E=LdIdt\mathcal{E} = -L\frac{dI}{dt}.
  • Transformer efficiency is η=PoutPin×100%\eta = \frac{P_{out}}{P_{in}} \times 100\%.

Vocabulary

Transformer
A device that uses electromagnetic induction between coils to change alternating voltage and current levels.
Primary Coil
The coil connected to the input voltage source in a transformer.
Secondary Coil
The coil connected to the output circuit where an induced voltage appears.
Turns Ratio
The ratio of secondary turns to primary turns, written as NsNp\frac{N_s}{N_p}, which determines the ideal voltage ratio.
Mutual Inductance
A measure of how effectively a changing current in one coil induces an emf in another coil.
Induced emf
A voltage produced by a changing magnetic flux, often described by Faraday’s law.

Common Mistakes to Avoid

  • Reversing the turns ratio, which gives the wrong output voltage because VsVp\frac{V_s}{V_p} must match NsNp\frac{N_s}{N_p} for an ideal transformer.
  • Using the same ratio for current as for voltage, which is wrong because ideal transformer current follows IsIp=NpNs\frac{I_s}{I_p} = \frac{N_p}{N_s}.
  • Applying transformer equations to direct current, which is wrong because a transformer needs changing magnetic flux from alternating or changing current.
  • Ignoring the negative sign in E2=MdI1dt\mathcal{E}_2 = -M\frac{dI_1}{dt}, which loses the meaning of Lenz’s law and the opposition to the change causing the emf.
  • Assuming real transformers are perfectly efficient, which is wrong because heat, eddy currents, flux leakage, and core losses make Pout<PinP_{out} < P_{in}.

Practice Questions

  1. 1 An ideal transformer has Np=200N_p = 200 turns and Ns=800N_s = 800 turns. If Vp=120VV_p = 120\,\text{V}, find VsV_s.
  2. 2 An ideal transformer steps 240V240\,\text{V} down to 24V24\,\text{V}. If the secondary current is 5.0A5.0\,\text{A}, find the primary current.
  3. 3 Two coils have mutual inductance M=0.30HM = 0.30\,\text{H}. If the current in coil 1 changes at dI1dt=12A/s\frac{dI_1}{dt} = 12\,\text{A/s}, find the magnitude of the induced emf in coil 2.
  4. 4 Explain why transformers are useful for long-distance power transmission even though they do not create extra energy.