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Arc length and surface area of revolution connect derivatives, integrals, and geometric measurement. This cheat sheet helps students choose the correct formula for curves written as functions, parametric equations, or polar equations. It is useful when setting up problems where the hardest step is identifying the correct radius, interval, or differential length.

Clear formulas and rules reduce common errors with square roots and bounds.

The main idea is that a tiny piece of curve has length dsds, then total length is found by integrating dsds. For rectangular functions, ds=1+(dydx)2dxds=\sqrt{1+\left(\frac{dy}{dx}\right)^2}\,dx or ds=1+(dxdy)2dyds=\sqrt{1+\left(\frac{dx}{dy}\right)^2}\,dy. Surface area of revolution uses dS=2πrdsdS=2\pi r\,ds, where rr is the distance from the curve to the axis of rotation.

Parametric and polar formulas use the same idea with a version of dsds that matches the coordinate system.

Key Facts

  • For y=f(x)y=f(x) on axba\le x\le b, arc length is L=ab1+(f(x))2dxL=\int_a^b \sqrt{1+\left(f'(x)\right)^2}\,dx.
  • For x=g(y)x=g(y) on cydc\le y\le d, arc length is L=cd1+(g(y))2dyL=\int_c^d \sqrt{1+\left(g'(y)\right)^2}\,dy.
  • For parametric curves x=x(t)x=x(t) and y=y(t)y=y(t) on αtβ\alpha\le t\le \beta, arc length is L=αβ(dxdt)2+(dydt)2dtL=\int_{\alpha}^{\beta}\sqrt{\left(\frac{dx}{dt}\right)^2+\left(\frac{dy}{dt}\right)^2}\,dt.
  • For polar curves r=r(θ)r=r(\theta) on αθβ\alpha\le \theta\le \beta, arc length is L=αβr2+(drdθ)2dθL=\int_{\alpha}^{\beta}\sqrt{r^2+\left(\frac{dr}{d\theta}\right)^2}\,d\theta.
  • Surface area of revolution is S=2πrdsS=\int 2\pi r\,ds, where rr is the distance from the curve to the axis of rotation.
  • If y=f(x)y=f(x) rotates about the xx-axis, then S=2πabf(x)1+(f(x))2dxS=2\pi\int_a^b f(x)\sqrt{1+\left(f'(x)\right)^2}\,dx when f(x)0f(x)\ge 0.
  • If y=f(x)y=f(x) rotates about the yy-axis, then S=2πabx1+(f(x))2dxS=2\pi\int_a^b x\sqrt{1+\left(f'(x)\right)^2}\,dx when x0x\ge 0.
  • Always check the interval and use a nonnegative radius, because surface area cannot be negative.

Vocabulary

Arc length
Arc length is the total distance along a curve between two endpoints.
Differential arc length
Differential arc length, written dsds, represents a tiny piece of curve length used inside an integral.
Surface of revolution
A surface of revolution is formed when a curve is rotated around an axis.
Radius of rotation
The radius of rotation is the perpendicular distance from a point on the curve to the axis of rotation.
Parametric curve
A parametric curve gives coordinates as functions of a parameter, usually written x=x(t)x=x(t) and y=y(t)y=y(t).
Polar curve
A polar curve describes points using distance rr from the origin and angle θ\theta from the positive xx-axis.

Common Mistakes to Avoid

  • Using abf(x)dx\int_a^b f(x)\,dx for arc length is wrong because area under a curve is not the same as distance along the curve. Arc length needs the factor 1+(f(x))2\sqrt{1+\left(f'(x)\right)^2}.
  • Forgetting the square root in dsds is wrong because dsds comes from the distance formula. The correct rectangular form is ds=1+(dydx)2dxds=\sqrt{1+\left(\frac{dy}{dx}\right)^2}\,dx.
  • Using the function value as the radius for every rotation is wrong because the radius depends on the axis. Around the xx-axis use vertical distance, and around the yy-axis use horizontal distance.
  • Mixing variables in the bounds is wrong because the integration variable must match the differential. If the integral uses dydy, the bounds must be yy-values.
  • Dropping absolute distance for the radius is wrong because radius cannot be negative. Use the distance to the axis, such as r=f(x)kr=|f(x)-k| for rotation around y=ky=k.

Practice Questions

  1. 1 Find the arc length of y=23x3/2y=\frac{2}{3}x^{3/2} on 0x30\le x\le 3.
  2. 2 Set up and evaluate the surface area formed when y=x2y=x^2 on 0x10\le x\le 1 is rotated about the yy-axis.
  3. 3 Find the arc length of the parametric curve x=3tx=3t and y=4ty=4t on 0t20\le t\le 2.
  4. 4 A curve y=f(x)y=f(x) is rotated about the line y=5y=5. Explain how the radius in S=2πrdsS=\int 2\pi r\,ds should be chosen and why it must be nonnegative.