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Reduction formulas help turn difficult integrals into simpler integrals of the same type. They are especially useful when an integrand contains a high power, a repeated product, or a parameter such as nn. This cheat sheet gives college calculus students a compact reference for recognizing common patterns and applying each formula correctly.

It is designed to support homework, exam review, and symbolic integration practice.

The main idea is to express InI_n in terms of In1I_{n-1} or In2I_{n-2} until the integral reaches a simple base case. Many formulas come from integration by parts, trigonometric identities, or both. For trigonometric powers, parity matters because even and odd powers often reduce differently.

Always record the base cases, such as 1dx=x+C\int 1\,dx=x+C and sinxdx=cosx+C\int \sin x\,dx=-\cos x+C, because they complete the reduction chain.

Key Facts

  • A reduction formula rewrites an integral sequence InI_n in terms of a simpler integral such as In1I_{n-1} or In2I_{n-2}.
  • For In=sinnxdxI_n=\int \sin^n x\,dx, the reduction formula is In=sinn1xcosxn+n1nIn2I_n=-\frac{\sin^{n-1}x\cos x}{n}+\frac{n-1}{n}I_{n-2} for n2n\ge 2.
  • For In=cosnxdxI_n=\int \cos^n x\,dx, the reduction formula is In=cosn1xsinxn+n1nIn2I_n=\frac{\cos^{n-1}x\sin x}{n}+\frac{n-1}{n}I_{n-2} for n2n\ge 2.
  • For In=tannxdxI_n=\int \tan^n x\,dx, the reduction formula is In=tann1xn1In2I_n=\frac{\tan^{n-1}x}{n-1}-I_{n-2} for n1n\ne 1 and n2n\ge 2.
  • For In=secnxdxI_n=\int \sec^n x\,dx, the reduction formula is In=secn2xtanxn1+n2n1In2I_n=\frac{\sec^{n-2}x\tan x}{n-1}+\frac{n-2}{n-1}I_{n-2} for n>1n>1.
  • For In=xneaxdxI_n=\int x^n e^{ax}\,dx, integration by parts gives In=xneaxanaIn1I_n=\frac{x^n e^{ax}}{a}-\frac{n}{a}I_{n-1} when a0a\ne 0.
  • For In=xnlnxdxI_n=\int x^n\ln x\,dx, integration by parts gives In=xn+1lnxn+1xn+1(n+1)2+CI_n=\frac{x^{n+1}\ln x}{n+1}-\frac{x^{n+1}}{(n+1)^2}+C when n1n\ne -1.
  • A reduction process must stop at a base case such as I0=1dx=x+CI_0=\int 1\,dx=x+C, I1=sinxdx=cosx+CI_1=\int \sin x\,dx=-\cos x+C, or I1=secxdx=lnsecx+tanx+CI_1=\int \sec x\,dx=\ln|\sec x+\tan x|+C.

Vocabulary

Reduction formula
A formula that expresses an integral with parameter nn in terms of a related integral with a smaller parameter.
Base case
The simplest integral in a reduction chain, such as I0I_0 or I1I_1, that can be evaluated directly.
Integration by parts
A method based on udv=uvvdu\int u\,dv=uv-\int v\,du that is often used to derive reduction formulas.
Recursive relation
An equation that defines one term, such as InI_n, using earlier terms such as In1I_{n-1} or In2I_{n-2}.
Trigonometric power integral
An integral involving powers of trigonometric functions, such as sinnxdx\int \sin^n x\,dx or secnxdx\int \sec^n x\,dx.
Parameter
A symbol such as nn or aa that represents a fixed value while the integration variable, usually xx, changes.

Common Mistakes to Avoid

  • Forgetting the base case is wrong because a reduction formula alone does not finish the integral; continue until reaching an integral such as I0I_0 or I1I_1 that you can evaluate directly.
  • Using the sine reduction formula for cosine is wrong because the boundary term changes sign and form; sinnxdx\int \sin^n x\,dx starts with sinn1xcosxn-\frac{\sin^{n-1}x\cos x}{n}, while cosnxdx\int \cos^n x\,dx starts with cosn1xsinxn\frac{\cos^{n-1}x\sin x}{n}.
  • Dropping the constant of integration is wrong for indefinite integrals because the final answer must include +C+C, even if intermediate InI_n notation leaves it implicit.
  • Applying a formula outside its allowed values is wrong because denominators may become zero; for example, tannxdx\int \tan^n x\,dx uses tann1xn1In2\frac{\tan^{n-1}x}{n-1}-I_{n-2} only when n1n\ne 1.
  • Reducing only once when the power is still high is wrong because InI_n may need repeated reductions, such as I6I4I2I0I_6\to I_4\to I_2\to I_0.

Practice Questions

  1. 1 Use the reduction formula for In=sinnxdxI_n=\int \sin^n x\,dx to find sin4xdx\int \sin^4 x\,dx.
  2. 2 Use the reduction formula for In=secnxdxI_n=\int \sec^n x\,dx to express sec4xdx\int \sec^4 x\,dx in elementary functions.
  3. 3 Apply integration by parts reduction to compute x3e2xdx\int x^3 e^{2x}\,dx.
  4. 4 Explain why a reduction formula for InI_n must include or eventually reach a base case, and describe what can go wrong if it does not.