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Alkene addition reactions are reactions in which atoms add across the carbon-carbon double bond of an alkene. Students need this cheat sheet because many organic chemistry problems ask for the major product, the reagent type, and the regiochemistry. Markovnikov's rule is especially important because it predicts where hydrogen and the other group attach in unsymmetrical alkenes.

This reference helps organize the most common patterns in a clear, formula-forward way.

The key idea is that the alkene π\pi bond is electron-rich and reacts with electrophiles. In many acid-catalyzed additions, the reaction forms the more stable carbocation intermediate, so the major product follows Markovnikov orientation. Some reactions, such as hydroboration-oxidation, give anti-Markovnikov hydration without a carbocation.

Stereochemistry also matters because halogenation usually gives anti addition, while catalytic hydrogenation gives syn addition.

Key Facts

  • In Markovnikov addition of HX\mathrm{HX} to an unsymmetrical alkene, H\mathrm{H} adds to the alkene carbon that already has more hydrogens.
  • The general hydrohalogenation pattern is RCH=CH2+HXRCHXCH3\mathrm{RCH{=}CH_2} + \mathrm{HX} \rightarrow \mathrm{RCHXCH_3} when the Markovnikov product is favored.
  • Markovnikov's rule works because the pathway forms the more stable carbocation intermediate before the nucleophile attacks.
  • Carbocation stability generally increases in the order 1<2<31^{\circ} < 2^{\circ} < 3^{\circ} because alkyl groups stabilize positive charge.
  • Acid-catalyzed hydration converts an alkene to an alcohol using H2O\mathrm{H_2O} and acid, with the pattern alkene+H2Oalcohol\mathrm{alkene} + \mathrm{H_2O} \rightarrow \mathrm{alcohol}.
  • Hydroboration-oxidation adds water across an alkene with anti-Markovnikov regiochemistry using BH3\mathrm{BH_3} then H2O2,OH\mathrm{H_2O_2, OH^-}.
  • Halogenation adds Br2\mathrm{Br_2} or Cl2\mathrm{Cl_2} across the double bond to form a vicinal dihalide, such as CH2=CH2+Br2BrCH2CH2Br\mathrm{CH_2{=}CH_2} + \mathrm{Br_2} \rightarrow \mathrm{BrCH_2CH_2Br}.
  • Catalytic hydrogenation adds H2\mathrm{H_2} across the double bond using a metal catalyst such as Pt\mathrm{Pt}, Pd\mathrm{Pd}, or Ni\mathrm{Ni}.

Vocabulary

Alkene
An alkene is a hydrocarbon that contains at least one carbon-carbon double bond, written as C=C\mathrm{C{=}C}.
Addition reaction
An addition reaction is a reaction in which atoms or groups add across a multiple bond to form a more saturated product.
Markovnikov's rule
Markovnikov's rule states that in many additions of HX\mathrm{HX} or H2O\mathrm{H_2O} to an unsymmetrical alkene, H\mathrm{H} adds to the carbon with more hydrogens.
Carbocation
A carbocation is an organic intermediate with a positively charged carbon, usually written as C+\mathrm{C^+}.
Regiochemistry
Regiochemistry describes which atom or group attaches to which carbon when more than one constitutional product is possible.
Anti-Markovnikov addition
Anti-Markovnikov addition places H\mathrm{H} on the more substituted alkene carbon and the other group on the less substituted carbon.

Common Mistakes to Avoid

  • Putting the halogen on the carbon with more hydrogens in Markovnikov hydrohalogenation is wrong because H\mathrm{H} adds to that carbon and X\mathrm{X} goes to the more substituted carbon.
  • Ignoring carbocation stability is wrong because the major product usually comes from the pathway with the more stable carbocation, often 33^{\circ} over 22^{\circ} over 11^{\circ}.
  • Treating hydroboration-oxidation as Markovnikov hydration is wrong because BH3\mathrm{BH_3} followed by H2O2,OH\mathrm{H_2O_2, OH^-} gives anti-Markovnikov alcohol placement.
  • Forgetting that halogenation adds two halogens is wrong because Br2\mathrm{Br_2} or Cl2\mathrm{Cl_2} adds one halogen to each alkene carbon to form a vicinal dihalide.
  • Using Markovnikov's rule on a symmetrical alkene as if two different products form is wrong because both alkene carbons are equivalent and give the same product.

Practice Questions

  1. 1 Predict the major product of CH3CH=CH2+HBr\mathrm{CH_3CH{=}CH_2} + \mathrm{HBr} under normal conditions.
  2. 2 How many moles of H2\mathrm{H_2} are required to completely hydrogenate 2.50 mol2.50\ \mathrm{mol} of cyclohexene, if each double bond consumes 1 mol1\ \mathrm{mol} of H2\mathrm{H_2}?
  3. 3 Predict the major alcohol product from CH3CH2CH=CH2\mathrm{CH_3CH_2CH{=}CH_2} treated with H2O\mathrm{H_2O} and H2SO4\mathrm{H_2SO_4}.
  4. 4 Explain why acid-catalyzed hydration of propene gives CH3CH(OH)CH3\mathrm{CH_3CH(OH)CH_3} as the major product instead of CH3CH2CH2OH\mathrm{CH_3CH_2CH_2OH}.