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This cheat sheet covers how to estimate enthalpy change from average bond energies in chemical reactions. Students need it because bond energy calculations are a common way to connect molecular structure with energy changes. It is especially useful for checking whether a reaction is exothermic or endothermic.

Worked examples help students organize bonds broken and bonds formed without losing signs.

Key Facts

  • The main formula is ΔHrxn=Ebonds brokenEbonds formed\Delta H_{\text{rxn}} = \sum E_{\text{bonds broken}} - \sum E_{\text{bonds formed}}.
  • Breaking bonds requires energy, so bonds broken are counted as positive energy changes.
  • Forming bonds releases energy, so bonds formed are subtracted in the formula.
  • A negative value of ΔHrxn\Delta H_{\text{rxn}} means the reaction is exothermic and releases heat.
  • A positive value of ΔHrxn\Delta H_{\text{rxn}} means the reaction is endothermic and absorbs heat.
  • Bond energy values are usually measured in kJ mol1\text{kJ mol}^{-1}, so the final ΔH\Delta H is often reported in kJ mol1\text{kJ mol}^{-1} of reaction as written.
  • Coefficients in a balanced equation multiply every bond count in that substance.
  • Average bond energies give estimates because real bond strengths depend on the molecule and its surroundings.

Vocabulary

Enthalpy change
The heat energy change of a reaction at constant pressure, written as ΔH\Delta H.
Bond enthalpy
The energy needed to break one mole of a specified covalent bond in the gas phase.
Bonds broken
The bonds in the reactants that must be separated before new products can form.
Bonds formed
The bonds made in the products, which release energy as atoms become more stable.
Exothermic reaction
A reaction with ΔH<0\Delta H < 0 because more energy is released by forming bonds than is absorbed breaking bonds.
Endothermic reaction
A reaction with ΔH>0\Delta H > 0 because more energy is absorbed breaking bonds than is released forming bonds.

Common Mistakes to Avoid

  • Adding bonds formed instead of subtracting them is wrong because bond formation releases energy and lowers ΔH\Delta H.
  • Forgetting to multiply by coefficients is wrong because the balanced equation tells how many molecules and therefore how many bonds are involved.
  • Counting atoms instead of bonds is wrong because bond energy calculations depend on the number and type of covalent bonds, not just the formula.
  • Using an unbalanced equation is wrong because the bond totals will not represent the actual reaction stoichiometry.
  • Reporting the wrong sign is wrong because ΔH<0\Delta H < 0 means exothermic and ΔH>0\Delta H > 0 means endothermic.

Practice Questions

  1. 1 For H2+Cl22HCl\text{H}_2 + \text{Cl}_2 \rightarrow 2\text{HCl}, estimate ΔH\Delta H using EH-H=436kJ mol1E_{\text{H-H}} = 436\,\text{kJ mol}^{-1}, ECl-Cl=243kJ mol1E_{\text{Cl-Cl}} = 243\,\text{kJ mol}^{-1}, and EH-Cl=431kJ mol1E_{\text{H-Cl}} = 431\,\text{kJ mol}^{-1}.
  2. 2 For CH4+2O2CO2+2H2O\text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O}, count the bonds broken and formed before calculating ΔH\Delta H.
  3. 3 Estimate ΔH\Delta H for N2+3H22NH3\text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3 using ENN=945kJ mol1E_{\text{N}\equiv\text{N}} = 945\,\text{kJ mol}^{-1}, EH-H=436kJ mol1E_{\text{H-H}} = 436\,\text{kJ mol}^{-1}, and EN-H=391kJ mol1E_{\text{N-H}} = 391\,\text{kJ mol}^{-1}.
  4. 4 Explain why average bond energies give approximate values rather than exact experimental enthalpy changes.