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The binomial distribution models the number of successes in a fixed number of repeated trials. Students need this reference because binomial problems appear often in probability, statistics, biology, business, and test preparation. This cheat sheet helps you identify when a situation is binomial and choose the correct formula quickly. The most important ideas are the four binomial conditions, the probability formula, and the meaning of the parameters nn and pp. A binomial random variable is written XB(n,p)X \sim B(n,p), where nn is the number of trials and pp is the probability of success on each trial. Key summary formulas include the mean μ=np\mu = np, variance σ2=np(1p)\sigma^2 = np(1-p), and standard deviation σ=np(1p)\sigma = \sqrt{np(1-p)}.

Key Facts

  • A binomial setting has a fixed number of trials nn, only two outcomes per trial, a constant success probability pp, and independent trials.
  • If XX counts the number of successes in nn trials with success probability pp, then XB(n,p)X \sim B(n,p).
  • The binomial probability formula is P(X=k)=(nk)pk(1p)nkP(X=k)=\binom{n}{k}p^k(1-p)^{n-k} for k=0,1,2,,nk=0,1,2,\ldots,n.
  • The combination formula is (nk)=n!k!(nk)!\binom{n}{k}=\frac{n!}{k!(n-k)!}, which counts the number of ways to choose kk successes from nn trials.
  • The mean of a binomial distribution is μ=np\mu = np.
  • The variance of a binomial distribution is σ2=np(1p)\sigma^2 = np(1-p).
  • The standard deviation of a binomial distribution is σ=np(1p)\sigma = \sqrt{np(1-p)}.
  • A normal approximation is often reasonable when np10np \ge 10 and n(1p)10n(1-p) \ge 10.

Vocabulary

Binomial distribution
A probability distribution for the number of successes in a fixed number of independent trials with the same success probability.
Trial
One repetition of a random experiment, such as flipping a coin once or asking one person a survey question.
Success
The outcome being counted in a binomial problem, even if it is not a positive or desirable result.
Parameter
A number that defines a probability model, such as nn for the number of trials and pp for the probability of success.
Combination
A count of selections where order does not matter, written as (nk)\binom{n}{k}.
Cumulative probability
The probability of getting a value within a range, such as P(Xk)P(X \le k) or P(Xk)P(X \ge k).

Common Mistakes to Avoid

  • Using the binomial formula when trials are not independent is wrong because the probability of success must stay the same from trial to trial.
  • Confusing pp and 1p1-p changes the meaning of success and failure, so always define the success outcome before substituting into P(X=k)=(nk)pk(1p)nkP(X=k)=\binom{n}{k}p^k(1-p)^{n-k}.
  • Forgetting the combination factor (nk)\binom{n}{k} gives the probability of one specific order only, not all possible orders with kk successes.
  • Using P(X=k)P(X=k) when the question asks for at least or at most is wrong because cumulative wording requires adding several probabilities, such as P(Xk)P(X \le k) or P(Xk)P(X \ge k).
  • Applying the normal approximation when np<10np < 10 or n(1p)<10n(1-p) < 10 can be inaccurate because the binomial distribution may be too skewed.

Practice Questions

  1. 1 A fair coin is flipped 88 times. If XX is the number of heads, find P(X=5)P(X=5).
  2. 2 A basketball player makes 70%70\% of free throws. If the player takes 1010 free throws, find the mean and standard deviation of the number made.
  3. 3 A multiple-choice quiz has 1212 questions with 44 choices each. If a student guesses on every question, what is P(X10)P(X \ge 10), where XX is the number correct?
  4. 4 A factory samples items without replacement from a small batch. Explain why this situation may not satisfy the binomial conditions.