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When an object moves along a line, its velocity tells both how fast it moves and which direction it moves. Calculus lets us turn a velocity-time graph into a statement about position by adding up tiny changes over time. The signed area under a velocity curve gives net displacement, which is the overall change in position.

This idea matters in physics, engineering, and any situation where motion changes continuously.

Key Facts

  • Net displacement from velocity: Δx = ∫ from a to b v(t) dt
  • Total distance traveled: distance = ∫ from a to b |v(t)| dt
  • Area above the time axis counts as positive displacement.
  • Area below the time axis counts as negative displacement.
  • If velocity changes sign, split the integral at each zero of v(t).
  • Average velocity on [a, b]: v_avg = (1/(b - a)) ∫ from a to b v(t) dt

Vocabulary

Velocity
Velocity is the rate of change of position with direction included.
Displacement
Displacement is the signed change in position from the starting point to the ending point.
Total distance
Total distance is the full length of the path traveled, regardless of direction.
Definite integral
A definite integral gives the accumulated signed area under a curve over an interval.
Absolute value
Absolute value gives the nonnegative size of a quantity, so |v(t)| represents speed.

Common Mistakes to Avoid

  • Using ∫ v(t) dt for total distance, because negative velocity subtracts area and can cancel positive motion.
  • Ignoring where v(t) crosses zero, because total distance requires splitting the interval wherever the velocity changes sign.
  • Treating negative velocity as negative speed, because speed is always nonnegative and equals |v(t)|.
  • Forgetting units, because integrating velocity in meters per second over seconds gives meters, not meters per second.

Practice Questions

  1. 1 A particle has velocity v(t) = 3t - 6 meters per second from t = 0 to t = 5 seconds. Find its net displacement.
  2. 2 A particle has velocity v(t) = 4 - t meters per second from t = 0 to t = 6 seconds. Find the total distance traveled.
  3. 3 A velocity-time graph has equal positive area above the axis and negative area below the axis over a time interval. Explain what this means for net displacement and total distance.