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Implicit differentiation is used when xx and yy are connected by an equation that is not solved for yy. This cheat sheet helps students differentiate curves like circles, ellipses, and mixed polynomial equations without first isolating yy. It is especially useful for finding slopes, tangent lines, and rates of change on relations.

Students need it because many calculus problems use equations where solving for yy is difficult or impossible.

The main idea is to treat yy as a function of xx, so every derivative involving yy includes a factor of dydx\frac{dy}{dx}. The chain rule is the key rule, such as ddx(yn)=nyn1dydx\frac{d}{dx}\left(y^n\right)=n y^{n-1}\frac{dy}{dx}. After differentiating both sides, collect all terms containing dydx\frac{dy}{dx}, factor it out, and solve.

The same method can be extended to tangent lines, normal lines, related rates, and second derivatives.

Key Facts

  • When differentiating with respect to xx, treat yy as a function of xx, so ddx(y)=dydx\frac{d}{dx}(y)=\frac{dy}{dx}.
  • The chain rule gives ddx(yn)=nyn1dydx\frac{d}{dx}\left(y^n\right)=n y^{n-1}\frac{dy}{dx} for any differentiable function y(x)y(x).
  • For a product involving xx and yy, use ddx(xy)=xdydx+y\frac{d}{dx}(xy)=x\frac{dy}{dx}+y.
  • For a quotient involving yy, use ddx(yx)=xdydxyx2\frac{d}{dx}\left(\frac{y}{x}\right)=\frac{x\frac{dy}{dx}-y}{x^2}.
  • After differentiating, collect all terms with dydx\frac{dy}{dx} on one side, factor out dydx\frac{dy}{dx}, and solve for dydx\frac{dy}{dx}.
  • The slope of the tangent line to an implicit curve at a point is m=dydxm=\frac{dy}{dx} evaluated at that point.
  • A tangent line through (x1,y1)(x_1,y_1) with slope mm is written as yy1=m(xx1)y-y_1=m(x-x_1).
  • For a second derivative, differentiate dydx\frac{dy}{dx} again with respect to xx to get d2ydx2=ddx(dydx)\frac{d^2y}{dx^2}=\frac{d}{dx}\left(\frac{dy}{dx}\right).

Vocabulary

Implicit equation
An equation where xx and yy are related but yy is not necessarily solved as a function of xx.
Implicit differentiation
A method for finding dydx\frac{dy}{dx} by differentiating both sides of an equation while treating yy as a function of xx.
Chain rule
A differentiation rule that says the derivative of a composite function is the outside derivative times the inside derivative.
Tangent line
A line that touches a curve at a point and has slope equal to dydx\frac{dy}{dx} at that point.
Related rates
Problems where two or more changing quantities are connected by an equation and their derivatives are related.
Second derivative
The derivative of the first derivative, written d2ydx2\frac{d^2y}{dx^2}, which describes how the slope is changing.

Common Mistakes to Avoid

  • Forgetting the factor dydx\frac{dy}{dx} when differentiating a term with yy is wrong because yy depends on xx, so ddx(y2)=2ydydx\frac{d}{dx}(y^2)=2y\frac{dy}{dx}, not 2y2y.
  • Using the power rule on xyxy as if it were one variable is wrong because xyxy is a product, so ddx(xy)=xdydx+y\frac{d}{dx}(xy)=x\frac{dy}{dx}+y.
  • Not collecting every dydx\frac{dy}{dx} term before solving is wrong because isolated terms can lead to an incomplete or incorrect derivative.
  • Substituting the point before differentiating is wrong because it can destroy the variable relationship needed to find dydx\frac{dy}{dx}.
  • Confusing the tangent slope with the normal slope is wrong because the normal slope is the negative reciprocal, mnormal=1mtangentm_{\text{normal}}=-\frac{1}{m_{\text{tangent}}}, when mtangent0m_{\text{tangent}}\neq 0.

Practice Questions

  1. 1 Find dydx\frac{dy}{dx} for x2+y2=25x^2+y^2=25.
  2. 2 Find the slope of the tangent line to x2+xy+y2=7x^2+xy+y^2=7 at (1,2)(1,2).
  3. 3 Find an equation of the tangent line to y3+x2y=10y^3+x^2y=10 at (1,2)(1,2).
  4. 4 Explain why implicit differentiation is more efficient than solving for yy first when differentiating x2+y2=36x^2+y^2=36.

Understanding Implicit Differentiation Reference

An implicit equation often describes more than one branch of a curve. A circle is a familiar case. For many horizontal positions, it has one point above the axis and one below it.

Solving for y creates separate formulas for those branches, each with its own domain. Working from the original relation keeps the whole curve together.

The derivative found by implicit differentiation can still give different slopes at different points because its value depends on both coordinates. This is why students should substitute the full point only after finding the general derivative.

The hardest part is usually not the algebra at the end. It is noticing every place where y changes as x changes. A term such as the square of y needs an extra derivative factor.

A trigonometric expression containing y needs that factor too. Products need special care because both factors may vary. A useful checking habit is to mark every y before starting.

Then inspect the derivative line by line and ask whether each marked y produced a derivative factor. Missing one factor is the most common error. Another good habit is to keep the derivative of y in a single form until it has been factored out, rather than moving pieces around too early.

Related rates problems give this method a physical meaning. The variables may represent a radius, height, distance, or angle, and all of them can change with time. Begin with a relationship that describes the situation at every instant.

Differentiate with respect to time, not with respect to one chosen length. Each changing measurement then produces its own rate. Insert the given measurements and rates only after differentiation.

This order matters because putting in numbers too soon can hide a variable that is still changing. Units provide a strong check.

A length rate should have units such as meters per second, while an area rate should have square meters per second. Negative rates indicate a decreasing measurement, not an incorrect answer by themselves.

A tangent line is local information. It predicts the curve’s direction very close to one point, but it may quickly stop matching a curved path farther away. The derivative can reveal special locations.

If its denominator becomes zero while the numerator does not, the curve may have a vertical tangent. If both parts become zero, more investigation is needed because the point might be a cusp, a crossing, or a place where the formula gives no immediate answer. Second derivatives require extra patience.

The first derivative usually contains x, y, and the derivative of y. When differentiating again, y still changes with x and the first derivative changes too.

The result helps identify concavity, meaning whether the curve bends upward or downward near a point. Always evaluate it at points that actually lie on the original relation.