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This cheat sheet covers L'Hôpital's Rule and the main indeterminate forms that appear in calculus limits. Students need it because many difficult limits cannot be solved by direct substitution alone. It gives a clear process for recognizing when the rule applies and when an expression must be rewritten first. It also helps students avoid using L'Hôpital's Rule when simpler algebra or standard limits are better.

Key Facts

  • L'Hôpital's Rule applies to limits of the form 00\frac{0}{0} or \frac{\infty}{\infty} when limxaf(x)g(x)=limxaf(x)g(x)\lim_{x \to a}\frac{f(x)}{g(x)} = \lim_{x \to a}\frac{f'(x)}{g'(x)} exists.
  • Before using L'Hôpital's Rule, direct substitution should give an indeterminate form such as 00\frac{0}{0} or \frac{\infty}{\infty}.
  • For products of the form 00 \cdot \infty, rewrite as a quotient such as f(x)g(x)=f(x)1/g(x)f(x)g(x)=\frac{f(x)}{1/g(x)} or g(x)1/f(x)\frac{g(x)}{1/f(x)}.
  • For differences of the form \infty - \infty, combine terms using a common denominator, conjugate, or algebraic simplification before applying L'Hôpital's Rule.
  • For powers of the forms 000^0, 11^{\infty}, and 0\infty^0, use logarithms by setting y=[f(x)]g(x)y = [f(x)]^{g(x)} and studying lny=g(x)ln(f(x))\ln y = g(x)\ln(f(x)).
  • L'Hôpital's Rule may be applied more than once if each new quotient still has the form 00\frac{0}{0} or \frac{\infty}{\infty}.
  • L'Hôpital's Rule does not mean differentiating the entire quotient, so f(x)g(x)\frac{f(x)}{g(x)} becomes f(x)g(x)\frac{f'(x)}{g'(x)}, not (f(x)g(x))\left(\frac{f(x)}{g(x)}\right)'.
  • If a simpler method works, such as factoring, rationalizing, or using limx0sinxx=1\lim_{x \to 0}\frac{\sin x}{x}=1, that method is often faster and safer.

Vocabulary

Indeterminate form
An expression such as 00\frac{0}{0} or \infty - \infty whose limiting value cannot be determined from substitution alone.
L'Hôpital's Rule
A limit rule that allows certain quotients to be evaluated by replacing f(x)g(x)\frac{f(x)}{g(x)} with f(x)g(x)\frac{f'(x)}{g'(x)}.
Direct substitution
The method of evaluating a limit by replacing xx with the value it approaches, such as x=ax=a.
One-sided limit
A limit in which xx approaches a value from only the left or the right, written limxaf(x)\lim_{x \to a^-}f(x) or limxa+f(x)\lim_{x \to a^+}f(x).
Logarithmic transformation
A method for power limits that uses lny\ln y to turn exponents into products, especially for 000^0, 11^{\infty}, and 0\infty^0.
Rationalizing
An algebraic method that multiplies by a conjugate to simplify expressions with radicals, such as x+11\sqrt{x+1}-1.

Common Mistakes to Avoid

  • Using L'Hôpital's Rule without checking the form is wrong because the rule only applies directly to 00\frac{0}{0} or \frac{\infty}{\infty} quotients.
  • Differentiating the quotient as (f(x)g(x))\left(\frac{f(x)}{g(x)}\right)' is wrong because L'Hôpital's Rule requires the quotient f(x)g(x)\frac{f'(x)}{g'(x)}.
  • Applying the rule to 00 \cdot \infty without rewriting is wrong because products must first be converted into a quotient form.
  • Stopping after one use when the result is still 00\frac{0}{0} is wrong because L'Hôpital's Rule may need to be applied repeatedly.
  • Ignoring domain and one-sided behavior is wrong because expressions involving lnx\ln x, radicals, or vertical asymptotes may only be valid from one side.

Practice Questions

  1. 1 Evaluate limx0sin(3x)x\lim_{x \to 0}\frac{\sin(3x)}{x}.
  2. 2 Evaluate limx2x2+5xex\lim_{x \to \infty}\frac{2x^2+5x}{e^x}.
  3. 3 Evaluate limx0+xlnx\lim_{x \to 0^+}x\ln x by first rewriting it as a quotient.
  4. 4 Explain why L'Hôpital's Rule cannot be applied directly to limx0(1x1sinx)\lim_{x \to 0}(\frac{1}{x}-\frac{1}{\sin x}) before rewriting the expression.