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Electrolysis uses electrical energy to force a nonspontaneous redox reaction to occur. This cheat sheet helps students track electron flow, identify anode and cathode reactions, and connect electric current to chemical change. It is especially useful for solving plating, gas production, and molten or aqueous electrolysis problems. Students need these tools to move confidently between balanced half-reactions, charge, moles of electrons, and mass.

Key Facts

  • In an electrolytic cell, oxidation occurs at the anode and reduction occurs at the cathode.
  • In electrolysis, the anode is positive and the cathode is negative because the power supply pulls electrons from the anode and pushes electrons to the cathode.
  • Electric charge is calculated by Q=ItQ = It, where QQ is charge in coulombs, II is current in amperes, and tt is time in seconds.
  • Moles of electrons are found using ne=QFn_{e^-} = \frac{Q}{F}, where F=96485 C mol1F = 96485\ \text{C mol}^{-1}.
  • Faraday’s law for deposited mass is m=ItMnFm = \frac{ItM}{nF}, where MM is molar mass and nn is electrons transferred per ion.
  • For a metal ion Mn+M^{n+}, the cathode half-reaction is Mn++neM(s)M^{n+} + ne^- \rightarrow M(s).
  • For electrolysis problems, always convert time to seconds using t(s)=t(min)×60t(\text{s}) = t(\text{min}) \times 60 or t(s)=t(h)×3600t(\text{s}) = t(\text{h}) \times 3600.
  • The stoichiometric ratio between product and electrons comes from the balanced half-reaction, not from the coefficient of the compound alone.

Vocabulary

Electrolytic cell
A cell that uses electrical energy to drive a nonspontaneous redox reaction.
Anode
The electrode where oxidation occurs and electrons are produced by the reacting species.
Cathode
The electrode where reduction occurs and electrons are gained by the reacting species.
Faraday’s constant
The charge carried by one mole of electrons, equal to F=96485 C mol1F = 96485\ \text{C mol}^{-1}.
Electroplating
A process in which electrolysis deposits a thin layer of metal onto an object.
Half-reaction
A balanced equation showing either oxidation or reduction, including the electrons transferred.

Common Mistakes to Avoid

  • Confusing anode and cathode signs, because galvanic and electrolytic cells have different electrode polarities. In electrolysis, the anode is positive and the cathode is negative.
  • Forgetting to convert time to seconds, which makes Q=ItQ = It wrong because amperes mean coulombs per second. Convert minutes or hours before calculating charge.
  • Using the wrong value of nn in m=ItMnFm = \frac{ItM}{nF}, because nn must come from the balanced half-reaction. For Cu2++2eCu(s)Cu^{2+} + 2e^- \rightarrow Cu(s), n=2n = 2.
  • Treating FF as charge for one electron, which is incorrect because FF is charge for one mole of electrons. Use ne=QFn_{e^-} = \frac{Q}{F} to find moles of electrons.
  • Ignoring competing reactions in aqueous electrolysis, because water can be oxidized or reduced along with dissolved ions. Always consider which species is easier to discharge at each electrode.

Practice Questions

  1. 1 A current of 2.50 A2.50\ \text{A} passes through molten NaClNaCl for 30.0 min30.0\ \text{min}. What charge QQ passes through the cell?
  2. 2 How many grams of copper are deposited when 3.00 A3.00\ \text{A} flows through CuSO4(aq)CuSO_4(aq) for 20.0 min20.0\ \text{min}, using Cu2++2eCu(s)Cu^{2+} + 2e^- \rightarrow Cu(s) and MCu=63.55 g mol1M_{Cu} = 63.55\ \text{g mol}^{-1}?
  3. 3 How long, in minutes, is needed to deposit 5.00 g5.00\ \text{g} of silver from Ag+(aq)Ag^+(aq) using a current of 1.50 A1.50\ \text{A}, given Ag++eAg(s)Ag^+ + e^- \rightarrow Ag(s) and MAg=107.87 g mol1M_{Ag} = 107.87\ \text{g mol}^{-1}?
  4. 4 Explain why the cathode in an electrolytic cell is negative even though reduction always occurs at the cathode.