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Gas stoichiometry connects balanced chemical equations to gas volumes, moles, and masses. Students need this cheat sheet because gas problems often mix reaction ratios with gas laws. It helps organize when to use STP shortcuts and when to use the ideal gas law.

Worked-example steps make multi-step problems easier to follow.

At STP, one mole of any ideal gas occupies 22.4 L22.4\ \text{L}, so volume can be converted directly to moles. At non-STP conditions, use PV=nRTPV = nRT to find moles before applying stoichiometric ratios. Balanced equations give mole ratios, and equal gas volumes at the same temperature and pressure follow those same ratios.

Limiting reactant problems compare possible product amounts from each reactant.

Key Facts

  • At STP, 1 mol1\ \text{mol} of an ideal gas occupies 22.4 L22.4\ \text{L}, so n=V22.4 L/moln = \frac{V}{22.4\ \text{L/mol}}.
  • For non-STP gases, use the ideal gas law PV=nRTPV = nRT and solve for moles with n=PVRTn = \frac{PV}{RT}.
  • Use R=0.0821 LatmmolKR = 0.0821\ \frac{\text{L}\cdot\text{atm}}{\text{mol}\cdot\text{K}} when pressure is in atm, volume is in liters, and temperature is in kelvin.
  • Convert Celsius to kelvin using TK=TC+273.15T_K = T_{^\circ\text{C}} + 273.15 before using any gas law formula.
  • Coefficients in a balanced equation give mole ratios, such as 2H2+O22H2O2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O} meaning 2 mol H2:1 mol O2:2 mol H2O2\ \text{mol H}_2 : 1\ \text{mol O}_2 : 2\ \text{mol H}_2\text{O}.
  • For gases at the same temperature and pressure, volume ratios equal mole ratios, so 2 L H22\ \text{L H}_2 reacts with 1 L O21\ \text{L O}_2 in 2H2+O22H2O2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O}.
  • A common gas stoichiometry path is given gas volumemoles givenmoles wantedwanted volume or mass\text{given gas volume} \rightarrow \text{moles given} \rightarrow \text{moles wanted} \rightarrow \text{wanted volume or mass}.
  • In limiting reactant problems, calculate product from each reactant and choose the smaller product amount as the theoretical yield.

Vocabulary

STP
STP means standard temperature and pressure, usually 0C0^\circ\text{C} or 273.15 K273.15\ \text{K} and 1 atm1\ \text{atm}.
Molar Volume
Molar volume is the volume occupied by 1 mol1\ \text{mol} of a gas, which is 22.4 L22.4\ \text{L} for an ideal gas at STP.
Ideal Gas Law
The ideal gas law is PV=nRTPV = nRT, which relates pressure, volume, moles, and temperature for an ideal gas.
Mole Ratio
A mole ratio is a conversion factor made from coefficients in a balanced chemical equation.
Limiting Reactant
The limiting reactant is the reactant that runs out first and determines the maximum amount of product formed.
Theoretical Yield
The theoretical yield is the maximum amount of product predicted by stoichiometry from the limiting reactant.

Common Mistakes to Avoid

  • Using 22.4 L/mol22.4\ \text{L/mol} at non-STP conditions is wrong because molar volume changes when temperature or pressure is not STP.
  • Forgetting to convert C^\circ\text{C} to kelvin is wrong because gas law temperature must use the absolute scale, so use TK=TC+273.15T_K = T_{^\circ\text{C}} + 273.15.
  • Using an unbalanced equation is wrong because mole ratios must come from the balanced coefficients, not from the unbalanced formula count.
  • Mixing pressure units is wrong because R=0.0821 LatmmolKR = 0.0821\ \frac{\text{L}\cdot\text{atm}}{\text{mol}\cdot\text{K}} requires pressure in atm, not kPa or mmHg.
  • Comparing reactant volumes directly in a limiting reactant problem is wrong unless the gases are at the same temperature and pressure.

Practice Questions

  1. 1 At STP, how many liters of O2\text{O}_2 are needed to react completely with 8.00 L8.00\ \text{L} of H2\text{H}_2 in 2H2+O22H2O2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O}?
  2. 2 How many moles of gas are in a 5.60 L5.60\ \text{L} sample at STP?
  3. 3 A 3.00 L3.00\ \text{L} sample of N2\text{N}_2 gas is at 1.20 atm1.20\ \text{atm} and 27.0C27.0^\circ\text{C}. Find the moles of N2\text{N}_2 using PV=nRTPV = nRT.
  4. 4 Explain why a gas volume ratio from a balanced equation can be used only when the gases are measured at the same temperature and pressure.