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Limiting reactant and percent yield problems connect balanced chemical equations to real laboratory results. This cheat sheet helps students set up stoichiometry, identify which reactant runs out first, and calculate how much product should form. It is useful for homework, lab reports, test review, and checking multi-step chemistry work. Clear formulas and organized steps help prevent common unit and mole-ratio errors. The core idea is that a balanced equation gives mole ratios, not mass ratios. To compare reactants, convert given amounts to moles, use coefficients to predict product, and choose the reactant that produces the smaller amount. The theoretical yield is the maximum product predicted by stoichiometry. Percent yield compares the actual lab yield to the theoretical yield using % yield=actual yieldtheoretical yield×100%\%\text{ yield} = \frac{\text{actual yield}}{\text{theoretical yield}} \times 100\%.

Key Facts

  • A balanced chemical equation is required before any stoichiometry calculation because coefficients give the mole ratios.
  • Convert mass to moles using n=mMn = \frac{m}{M}, where nn is moles, mm is mass in grams, and MM is molar mass in g/mol\text{g/mol}.
  • Use the mole ratio from the balanced equation as moles wanted=moles given×coefficient wantedcoefficient given\text{moles wanted} = \text{moles given} \times \frac{\text{coefficient wanted}}{\text{coefficient given}}.
  • The limiting reactant is the reactant that produces the smaller calculated amount of product.
  • The excess reactant is the reactant left over after the limiting reactant is completely consumed.
  • Theoretical yield is the maximum product possible from the limiting reactant under ideal conditions.
  • Percent yield is calculated with % yield=actual yieldtheoretical yield×100%\%\text{ yield} = \frac{\text{actual yield}}{\text{theoretical yield}} \times 100\%.
  • Actual yield must be less than or equal to theoretical yield in typical school laboratory calculations, so percent yield is usually 100%\leq 100\%.

Vocabulary

Limiting Reactant
The reactant that is used up first and determines the maximum amount of product that can form.
Excess Reactant
The reactant that remains after the limiting reactant has been completely consumed.
Mole Ratio
A conversion factor made from coefficients in a balanced chemical equation.
Theoretical Yield
The maximum amount of product predicted by stoichiometry from the limiting reactant.
Actual Yield
The amount of product actually collected or measured in an experiment.
Percent Yield
A comparison of actual yield to theoretical yield, calculated as actual yieldtheoretical yield×100%\frac{\text{actual yield}}{\text{theoretical yield}} \times 100\%.

Common Mistakes to Avoid

  • Using grams directly in the mole ratio is wrong because balanced equation coefficients compare moles, not masses.
  • Choosing the reactant with the smaller starting mass as the limiting reactant is wrong because molar mass and equation coefficients must be considered.
  • Forgetting to balance the equation first gives incorrect mole ratios, so every later calculation will be unreliable.
  • Dividing theoretical yield by actual yield in percent yield is wrong because the formula is % yield=actual yieldtheoretical yield×100%\%\text{ yield} = \frac{\text{actual yield}}{\text{theoretical yield}} \times 100\%.
  • Rounding too early can change the limiting reactant or final percent yield, so keep extra digits until the final answer.

Practice Questions

  1. 1 For 2H2+O22H2O2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O}, if you have 5.00 mol5.00\text{ mol} of H2\text{H}_2 and 2.00 mol2.00\text{ mol} of O2\text{O}_2, identify the limiting reactant and calculate the theoretical yield of H2O\text{H}_2\text{O} in moles.
  2. 2 For N2+3H22NH3\text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3, if 14.0 g14.0\text{ g} of N2\text{N}_2 reacts with excess H2\text{H}_2, calculate the theoretical yield of NH3\text{NH}_3 in grams.
  3. 3 A reaction has a theoretical yield of 25.0 g25.0\text{ g}, but only 18.5 g18.5\text{ g} of product is collected. Calculate the percent yield.
  4. 4 Explain why the limiting reactant, not the excess reactant, determines the theoretical yield of a reaction.