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This cheat sheet covers the Midsegment Theorem and the Triangle Proportionality Theorem, two important tools for solving geometry problems with triangles and parallel lines. Students use these theorems to find missing side lengths, prove segments are parallel, and recognize similar triangles. These ideas appear often in coordinate geometry, similarity proofs, and multi-step triangle problems.

A clear reference helps students choose the correct theorem quickly and avoid mixing up length and ratio relationships.

The Midsegment Theorem says that a segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length. The Triangle Proportionality Theorem says that a line parallel to one side of a triangle divides the other two sides proportionally. Its converse lets students prove that a segment is parallel when the divided side lengths form equal ratios.

Many problems come down to setting up a correct proportion such as ADDB=AEEC\frac{AD}{DB} = \frac{AE}{EC} or using the midsegment formula MN=12BCMN = \frac{1}{2}BC.

Key Facts

  • If MM and NN are midpoints of ABAB and ACAC in ABC\triangle ABC, then MNBCMN \parallel BC and MN=12BCMN = \frac{1}{2}BC.
  • If MNMN is a midsegment of ABC\triangle ABC, then the third side has length BC=2MNBC = 2MN.
  • If DEBCDE \parallel BC in ABC\triangle ABC with DD on ABAB and EE on ACAC, then ADDB=AEEC\frac{AD}{DB} = \frac{AE}{EC}.
  • If DEBCDE \parallel BC in ABC\triangle ABC, then the smaller triangle is similar to the larger triangle, so ADEABC\triangle ADE \sim \triangle ABC.
  • For similar triangles ADEABC\triangle ADE \sim \triangle ABC, corresponding side ratios are equal, so ADAB=AEAC=DEBC\frac{AD}{AB} = \frac{AE}{AC} = \frac{DE}{BC}.
  • The converse of the Triangle Proportionality Theorem says that if ADDB=AEEC\frac{AD}{DB} = \frac{AE}{EC}, then DEBCDE \parallel BC.
  • When a line parallel to one side of a triangle cuts the other two sides, always match corresponding segments in the same order before writing a proportion.
  • A midpoint divides a segment into two equal parts, so if MM is the midpoint of ABAB, then AM=MBAM = MB and AB=2AMAB = 2AM.

Vocabulary

Midsegment
A midsegment is a segment that connects the midpoints of two sides of a triangle.
Midpoint
A midpoint is a point that divides a segment into two congruent parts.
Parallel Lines
Parallel lines are coplanar lines that never intersect and have the same direction.
Proportion
A proportion is an equation showing that two ratios are equal, such as ab=cd\frac{a}{b} = \frac{c}{d}.
Similar Triangles
Similar triangles have congruent corresponding angles and proportional corresponding side lengths.
Converse
A converse reverses the hypothesis and conclusion of a theorem to create a related statement.

Common Mistakes to Avoid

  • Using the full third side instead of half for a midsegment is wrong because the Midsegment Theorem gives MN=12BCMN = \frac{1}{2}BC, not MN=BCMN = BC.
  • Setting up mismatched ratios is wrong because proportional segments must be paired consistently, such as ADDB=AEEC\frac{AD}{DB} = \frac{AE}{EC} rather than mixing a part with a whole on only one side.
  • Assuming a segment is parallel without proof is wrong because the Triangle Proportionality Theorem applies only when the segment is known to be parallel, or when the converse proves it.
  • Confusing ADDB\frac{AD}{DB} with ADAB\frac{AD}{AB} is wrong because one ratio compares two parts while the other compares a part to the whole side.
  • Forgetting to double a midsegment length is wrong when solving for the third side because BC=2MNBC = 2MN.

Practice Questions

  1. 1 In ABC\triangle ABC, MM and NN are midpoints of ABAB and ACAC. If BC=18BC = 18, what is MNMN?
  2. 2 In ABC\triangle ABC, DEBCDE \parallel BC, DD is on ABAB, and EE is on ACAC. If AD=6AD = 6, DB=9DB = 9, and AE=8AE = 8, find ECEC.
  3. 3 In ABC\triangle ABC, DEBCDE \parallel BC and ADEABC\triangle ADE \sim \triangle ABC. If AD=5AD = 5, AB=15AB = 15, and BC=24BC = 24, find DEDE.
  4. 4 A segment connects two points on the sides of a triangle and divides the two sides in equal ratios. Explain why this can be used to prove the segment is parallel to the third side.