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Continuous probability distributions describe random variables that can take any value in an interval, such as time, height, distance, or measurement error. This cheat sheet helps students connect graphs, formulas, and probability statements in a clear way. It is especially useful for distinguishing probability density from actual probability.

Students in grades 11-12 need these tools for statistics, precalculus, calculus, and science applications.

The most important ideas are the probability density function, the cumulative distribution function, expected value, and variance. For a continuous random variable, probabilities come from area under a curve, not from the height of the curve at one point. Common models include the uniform distribution, normal distribution, and exponential distribution.

Standardizing with z=xμσz = \frac{x - \mu}{\sigma} lets students compare values using the standard normal distribution.

Key Facts

  • For a continuous random variable XX, the probability at one exact value is P(X=a)=0P(X = a) = 0.
  • A probability density function f(x)f(x) must satisfy f(x)0f(x) \ge 0 and f(x)dx=1\int_{-\infty}^{\infty} f(x)\,dx = 1.
  • The probability that XX lies between aa and bb is P(aXb)=abf(x)dxP(a \le X \le b) = \int_a^b f(x)\,dx.
  • The cumulative distribution function is F(x)=P(Xx)=xf(t)dtF(x) = P(X \le x) = \int_{-\infty}^{x} f(t)\,dt.
  • For a continuous random variable, expected value is E(X)=xf(x)dxE(X) = \int_{-\infty}^{\infty} x f(x)\,dx.
  • Variance is Var(X)=E(X2)(E(X))2\operatorname{Var}(X) = E\left(X^2\right) - \left(E(X)\right)^2, and standard deviation is σ=Var(X)\sigma = \sqrt{\operatorname{Var}(X)}.
  • For a uniform distribution on [a,b][a,b], f(x)=1baf(x) = \frac{1}{b-a}, μ=a+b2\mu = \frac{a+b}{2}, and σ2=(ba)212\sigma^2 = \frac{(b-a)^2}{12}.
  • For a normal distribution, standardization uses z=xμσz = \frac{x - \mu}{\sigma} so probabilities can be found from the standard normal model N(0,1)N(0,1).

Vocabulary

Continuous random variable
A variable that can take any value in an interval, such as all real numbers between 22 and 33.
Probability density function
A function f(x)f(x) whose area over an interval gives the probability that a continuous random variable falls in that interval.
Cumulative distribution function
A function F(x)F(x) that gives the probability P(Xx)P(X \le x) for a random variable XX.
Expected value
The long-run average value of a random variable, calculated for continuous variables by E(X)=xf(x)dxE(X) = \int_{-\infty}^{\infty} x f(x)\,dx.
Normal distribution
A bell-shaped continuous distribution described by its mean μ\mu and standard deviation σ\sigma.
Standard normal distribution
The normal distribution with mean 00 and standard deviation 11, written as N(0,1)N(0,1).

Common Mistakes to Avoid

  • Treating f(a)f(a) as P(X=a)P(X = a) is wrong because a density height is not a probability. For continuous variables, P(X=a)=0P(X = a) = 0 and probability comes from area.
  • Forgetting that total area must equal 11 is wrong because a valid density function must satisfy f(x)dx=1\int_{-\infty}^{\infty} f(x)\,dx = 1. Always check the full area under the curve.
  • Using P(aXb)=f(b)f(a)P(a \le X \le b) = f(b) - f(a) is wrong because probability uses the area under f(x)f(x), not the change in height. The correct form is P(aXb)=abf(x)dxP(a \le X \le b) = \int_a^b f(x)\,dx.
  • Standardizing with z=x+μσz = \frac{x + \mu}{\sigma} is wrong because the mean must be subtracted. The correct formula is z=xμσz = \frac{x - \mu}{\sigma}.
  • Confusing variance and standard deviation is wrong because variance is measured in squared units. Standard deviation is σ=Var(X)\sigma = \sqrt{\operatorname{Var}(X)} and matches the original units.

Practice Questions

  1. 1 A continuous random variable has density f(x)=15f(x) = \frac{1}{5} on 0x50 \le x \le 5. Find P(1X4)P(1 \le X \le 4).
  2. 2 A normal random variable has mean μ=80\mu = 80 and standard deviation σ=10\sigma = 10. Find the zz-score for x=95x = 95.
  3. 3 For an exponential distribution with rate λ=0.25\lambda = 0.25, use P(Xx)=1eλxP(X \le x) = 1 - e^{-\lambda x} to find P(X4)P(X \le 4).
  4. 4 Explain why the probability that a continuous random variable is exactly equal to one specific number is 00, even if the density curve is high at that number.