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Parametric and polar equations describe curves in ways that are often easier than standard Cartesian equations. This cheat sheet helps students convert between forms, graph curves, and interpret motion or direction. It is useful for precalculus, calculus, and advanced algebra topics involving circles, spirals, conics, and particle paths.

Parametric equations use a parameter such as tt to define xx and yy separately, while polar equations use a distance rr and angle θ\theta. The most important conversions are x=rcosθx = r\cos \theta, y=rsinθy = r\sin \theta, r2=x2+y2r^2 = x^2 + y^2, and tanθ=yx\tan \theta = \frac{y}{x}. Students should also know how to eliminate a parameter, convert equations carefully, and interpret orientation as the parameter changes.

Key Facts

  • A parametric curve is defined by x=f(t)x = f(t) and y=g(t)y = g(t), where tt is the parameter that traces points on the curve.
  • To eliminate a parameter, solve one equation for tt when possible and substitute into the other equation.
  • The polar to Cartesian conversion formulas are x=rcosθx = r\cos \theta and y=rsinθy = r\sin \theta.
  • The Cartesian to polar conversion formulas are r2=x2+y2r^2 = x^2 + y^2 and tanθ=yx\tan \theta = \frac{y}{x}, with quadrant checked separately.
  • For a parametric curve, the slope is dydx=dydtdxdt\frac{dy}{dx} = \frac{\frac{dy}{dt}}{\frac{dx}{dt}} when dxdt0\frac{dx}{dt} \ne 0.
  • A horizontal tangent occurs when dydt=0\frac{dy}{dt} = 0 and dxdt0\frac{dx}{dt} \ne 0, while a vertical tangent occurs when dxdt=0\frac{dx}{dt} = 0 and dydt0\frac{dy}{dt} \ne 0.
  • The polar equation r=ar = a represents a circle centered at the origin with radius aa when a>0a > 0.
  • The polar equation θ=α\theta = \alpha represents a line through the origin making angle α\alpha with the positive xx-axis.

Vocabulary

Parametric equation
An equation system where coordinates are written separately as x=f(t)x = f(t) and y=g(t)y = g(t) using a parameter tt.
Parameter
A variable, often tt, that controls the position of a point on a parametric curve.
Polar coordinate
A coordinate written as (r,θ)(r, \theta), where rr is directed distance from the origin and θ\theta is the angle from the positive xx-axis.
Pole
The origin in the polar coordinate system, corresponding to the point where r=0r = 0.
Eliminating the parameter
The process of removing tt from parametric equations to produce a relationship involving only xx and yy.
Orientation
The direction a parametric or polar curve is traced as the parameter or angle increases.

Common Mistakes to Avoid

  • Using tanθ=yx\tan \theta = \frac{y}{x} without checking the quadrant is wrong because tangent repeats values in opposite quadrants.
  • Forgetting that rr can be negative in polar coordinates is wrong because a point with negative rr is plotted in the opposite direction from angle θ\theta.
  • Eliminating tt without keeping restrictions is wrong because the Cartesian equation may include points not reached by the original parametric equations.
  • Writing dydx=dydt\frac{dy}{dx} = \frac{dy}{dt} for parametric equations is wrong because slope must compare changes in yy to changes in xx, so dydx=dydtdxdt\frac{dy}{dx} = \frac{\frac{dy}{dt}}{\frac{dx}{dt}}.
  • Replacing r2r^2 with rr during polar conversion is wrong because r2=x2+y2r^2 = x^2 + y^2, while r=x2+y2r = \sqrt{x^2 + y^2} only gives the nonnegative distance.

Practice Questions

  1. 1 Eliminate the parameter from x=2t+1x = 2t + 1 and y=t23y = t^2 - 3.
  2. 2 Convert the polar point (4,π3)(4, \frac{\pi}{3}) to Cartesian coordinates using x=rcosθx = r\cos \theta and y=rsinθy = r\sin \theta.
  3. 3 Convert the Cartesian equation x2+y2=25x^2 + y^2 = 25 to polar form.
  4. 4 Explain why the parametric equations x=costx = \cos t and y=sinty = \sin t include orientation information that the Cartesian equation x2+y2=1x^2 + y^2 = 1 does not show.