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Doppler Effect for Light & Sound Reference cheat sheet - grade 10-12

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The Doppler effect describes how the observed frequency or wavelength of a wave changes when the source and observer move relative to each other. This cheat sheet helps students compare sound waves, which need a medium, with light waves, which do not. It is useful for solving problems about sirens, moving vehicles, stars, galaxies, radar, and astronomy spectra. Clear sign conventions are especially important because many wrong answers come from choosing the wrong direction of motion. For sound, the observed frequency depends on the speeds of the source, observer, and wave in the medium. For light, the shift is usually described using redshift and blueshift, and at high speeds it requires the relativistic Doppler formula. Approaching motion increases observed frequency and decreases wavelength, while receding motion decreases observed frequency and increases wavelength. The most important formulas connect ff, λ\lambda, vv, and redshift zz.

Key Facts

  • For any wave, speed, frequency, and wavelength are related by v=fλv = f\lambda.
  • For sound in still air, the Doppler formula is f=fv+vovvsf' = f\frac{v + v_o}{v - v_s} when the observer moves toward the source and the source moves toward the observer.
  • If a sound source and observer move closer together, the observed frequency increases, so f>ff' > f.
  • If a sound source and observer move farther apart, the observed frequency decreases, so f<ff' < f.
  • For light at low relative speeds, the approximate Doppler shift is Δλλvrc\frac{\Delta \lambda}{\lambda} \approx \frac{v_r}{c}, where vrv_r is positive for recession.
  • Redshift is defined by z=λobsλemitλemitz = \frac{\lambda_{\text{obs}} - \lambda_{\text{emit}}}{\lambda_{\text{emit}}}.
  • A positive redshift z>0z > 0 means the source is moving away, while a negative redshift z<0z < 0 means the source is moving toward the observer.
  • For relativistic light Doppler shift along the line of sight, fobsfemit=1β1+β\frac{f_{\text{obs}}}{f_{\text{emit}}} = \sqrt{\frac{1 - \beta}{1 + \beta}} for a receding source, where β=vc\beta = \frac{v}{c}.

Vocabulary

Doppler effect
The Doppler effect is the change in observed frequency or wavelength caused by relative motion between a wave source and an observer.
Observed frequency
Observed frequency is the frequency measured by an observer, often written as ff' or fobsf_{\text{obs}}.
Redshift
Redshift is an increase in observed wavelength, described by z=λobsλemitλemitz = \frac{\lambda_{\text{obs}} - \lambda_{\text{emit}}}{\lambda_{\text{emit}}}.
Blueshift
Blueshift is a decrease in observed wavelength that occurs when a light source moves toward an observer.
Wave speed
Wave speed is the speed at which a wave travels through a medium or through space, related by v=fλv = f\lambda.
Relative velocity
Relative velocity is the velocity of one object as measured from another object's frame of reference.

Common Mistakes to Avoid

  • Using the sound Doppler formula for light is wrong because sound depends on motion through a medium, while light in vacuum always travels at cc for all observers.
  • Reversing the sign convention gives the wrong shift because approaching motion should make fobsf_{\text{obs}} larger and λobs\lambda_{\text{obs}} smaller.
  • Confusing frequency shift with wavelength shift is wrong because frequency and wavelength change in opposite directions when wave speed is fixed by v=fλv = f\lambda.
  • Forgetting to convert units can make the calculation inconsistent because speeds such as 340m/s340\,\text{m/s} and 60km/h60\,\text{km/h} cannot be used together without conversion.
  • Using the low-speed light approximation at very high speeds is wrong because Δλλvrc\frac{\Delta \lambda}{\lambda} \approx \frac{v_r}{c} is only accurate when vrcv_r \ll c.

Practice Questions

  1. 1 A police siren emits 700Hz700\,\text{Hz} while moving toward a stationary observer at 30m/s30\,\text{m/s}. If the speed of sound is 343m/s343\,\text{m/s}, find the observed frequency using f=fvvvsf' = f\frac{v}{v - v_s}.
  2. 2 A stationary sound source emits 500Hz500\,\text{Hz}. An observer moves away from the source at 20m/s20\,\text{m/s} while sound travels at 340m/s340\,\text{m/s}. Find ff' using f=fvvovf' = f\frac{v - v_o}{v}.
  3. 3 A galaxy has an emitted spectral line at 500nm500\,\text{nm} and an observed line at 525nm525\,\text{nm}. Calculate the redshift using z=λobsλemitλemitz = \frac{\lambda_{\text{obs}} - \lambda_{\text{emit}}}{\lambda_{\text{emit}}}.
  4. 4 Explain why an approaching ambulance has a higher-pitched siren as it comes toward you but a lower-pitched siren after it passes you.