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Standing waves form when waves reflect and interfere so that fixed points called nodes and high-motion points called antinodes appear. This cheat sheet covers standing waves on strings fixed at both ends, pipes open at both ends, and pipes closed at one end. Students need these patterns because many sound and vibration problems depend on choosing the correct harmonic model before using formulas.

Worked examples help connect diagrams, boundary conditions, wavelengths, and frequencies.

The central relationship is v=fλv=f\lambda, where vv is wave speed, ff is frequency, and λ\lambda is wavelength. For strings fixed at both ends and open pipes, allowed wavelengths follow λn=2Ln\lambda_n=\frac{2L}{n} and frequencies follow fn=nv2Lf_n=\frac{nv}{2L}. For pipes closed at one end, only odd harmonics occur, with λn=4Ln\lambda_n=\frac{4L}{n} and fn=nv4Lf_n=\frac{nv}{4L} for odd nn.

In air at room temperature, many problems use v343m/sv\approx343\,\text{m/s} for sound.

Key Facts

  • For any wave, the speed equation is v=fλv=f\lambda, so frequency can be found with f=vλf=\frac{v}{\lambda}.
  • A string fixed at both ends has nodes at both ends, and its allowed wavelengths are λn=2Ln\lambda_n=\frac{2L}{n} for n=1,2,3,n=1,2,3,\ldots.
  • The harmonic frequencies for a string fixed at both ends are fn=nv2Lf_n=\frac{nv}{2L}, where nn is the harmonic number.
  • An open pipe has antinodes at both ends, and its allowed wavelengths are λn=2Ln\lambda_n=\frac{2L}{n} for n=1,2,3,n=1,2,3,\ldots.
  • The harmonic frequencies for an open pipe are fn=nv2Lf_n=\frac{nv}{2L}, using the sound speed in air for vv.
  • A pipe closed at one end has a node at the closed end and an antinode at the open end.
  • A pipe closed at one end supports only odd harmonics, so n=1,3,5,n=1,3,5,\ldots and fn=nv4Lf_n=\frac{nv}{4L}.
  • The fundamental frequency is the lowest allowed frequency, so it is f1=v2Lf_1=\frac{v}{2L} for strings and open pipes, but f1=v4Lf_1=\frac{v}{4L} for a closed pipe.

Vocabulary

Standing wave
A wave pattern formed by interference in which nodes and antinodes stay in fixed positions.
Node
A point in a standing wave where the medium has zero displacement.
Antinode
A point in a standing wave where the medium has maximum displacement.
Harmonic
An allowed standing-wave frequency that fits the boundary conditions of the string or pipe.
Fundamental frequency
The lowest allowed frequency of a standing wave system, also called the first harmonic.
Boundary condition
A required behavior at the end of a string or pipe, such as a node at a fixed end or an antinode at an open end.

Common Mistakes to Avoid

  • Using the open-pipe formula for a closed pipe is wrong because a closed pipe has one node and one antinode, so its fundamental wavelength is λ1=4L\lambda_1=4L, not λ1=2L\lambda_1=2L.
  • Including even harmonics for a closed pipe is wrong because a pipe closed at one end supports only n=1,3,5,n=1,3,5,\ldots.
  • Forgetting that LL is the physical length of the string or pipe is wrong because λ\lambda may be 2L2L, LL, 2L3\frac{2L}{3}, or 4L4L depending on the system and harmonic.
  • Using the speed of sound for a vibrating string is wrong because a string wave speed depends on the string tension and mass per length, not the air temperature.
  • Treating nodes and antinodes as interchangeable is wrong because fixed string ends and closed pipe ends are nodes, while open pipe ends are antinodes.

Practice Questions

  1. 1 A string fixed at both ends is 0.80m0.80\,\text{m} long and has wave speed 120m/s120\,\text{m/s}. Find the fundamental frequency f1f_1 and the third harmonic frequency f3f_3.
  2. 2 An open pipe is 0.50m0.50\,\text{m} long. Using v=343m/sv=343\,\text{m/s}, find f1f_1 and f2f_2.
  3. 3 A pipe closed at one end is 0.75m0.75\,\text{m} long. Using v=343m/sv=343\,\text{m/s}, find the first three allowed harmonic frequencies.
  4. 4 Explain why a closed pipe does not produce a second harmonic, even though an open pipe of the same length can.