Sign in to save

Bookmark this page so you can find it later.

Sign in to save

Bookmark this page so you can find it later.

Thermal Conduction, Convection & Radiation Worked Problems cheat sheet - grade 11-12

Click image to open full size

Thermal conduction, convection, and radiation explain how energy moves because of temperature differences. This cheat sheet helps students choose the correct heat transfer model, substitute units correctly, and solve worked-problem style questions. It is useful for physics, engineering, and environmental science problems involving insulation, cooling, heating, and energy loss.

Key Facts

  • Conduction through a flat wall is modeled by Qt=kAΔTL\frac{Q}{t}=\frac{kA\Delta T}{L}, where kk is thermal conductivity, AA is area, and LL is thickness.
  • Thermal resistance for conduction is Rcond=LkAR_{\mathrm{cond}}=\frac{L}{kA}, so heat transfer rate can be written as Q˙=ΔTRcond\dot{Q}=\frac{\Delta T}{R_{\mathrm{cond}}}.
  • For layers in series, total thermal resistance is Rtotal=R1+R2+R3+R_{\mathrm{total}}=R_1+R_2+R_3+\cdots and the same heat rate passes through each layer at steady state.
  • Convective heat transfer is estimated by Newton's law of cooling, Q˙=hA(TsT)\dot{Q}=hA\left(T_s-T_{\infty}\right), where hh is the convection coefficient.
  • Radiation from an object is given by the Stefan-Boltzmann law P=εσAT4P=\varepsilon\sigma A T^4, where σ=5.67×108 Wm2K4\sigma=5.67\times10^{-8}\ \mathrm{W\,m^{-2}\,K^{-4}}.
  • Net radiation between an object and large surroundings is Pnet=εσA(T4Tsurr4)P_{\mathrm{net}}=\varepsilon\sigma A\left(T^4-T_{\mathrm{surr}}^4\right), with all temperatures measured in kelvin.
  • Temperatures must be converted using TK=TC+273.15T_{\mathrm{K}}=T_{^\circ\mathrm{C}}+273.15 before using any T4T^4 radiation formula.
  • When conduction, convection, and radiation act together, the total heat transfer rate is often found by adding parallel contributions, such as Q˙total=Q˙conv+Q˙rad\dot{Q}_{\mathrm{total}}=\dot{Q}_{\mathrm{conv}}+\dot{Q}_{\mathrm{rad}}.

Vocabulary

Conduction
Conduction is heat transfer through direct particle interactions, usually strongest in solids with high thermal conductivity.
Convection
Convection is heat transfer between a surface and a moving fluid such as air or water.
Radiation
Radiation is heat transfer by electromagnetic waves and can occur through empty space.
Thermal Conductivity
Thermal conductivity kk measures how easily a material conducts heat, with larger kk giving a larger heat transfer rate.
Emissivity
Emissivity ε\varepsilon is a number from 00 to 11 that describes how effectively a surface emits thermal radiation.
Steady State
Steady state means temperatures at each point are constant in time, even though heat continues to flow.

Common Mistakes to Avoid

  • Using Celsius in radiation formulas is wrong because P=εσAT4P=\varepsilon\sigma A T^4 requires absolute temperature in kelvin.
  • Forgetting the thickness LL in conduction changes the physics because thicker materials reduce heat flow according to Q˙=kAΔTL\dot{Q}=\frac{kA\Delta T}{L}.
  • Adding conductivities instead of thermal resistances for layered walls is wrong because layers in series combine as Rtotal=R1+R2+R_{\mathrm{total}}=R_1+R_2+\cdots.
  • Using the wrong area gives an incorrect heat rate because all three main formulas depend directly on surface area AA.
  • Ignoring the sign of the temperature difference can confuse direction because heat flows from higher temperature to lower temperature, even when the calculated rate is written as a positive magnitude.

Practice Questions

  1. 1 A glass window has A=2.0 m2A=2.0\ \mathrm{m^2}, L=4.0×103 mL=4.0\times10^{-3}\ \mathrm{m}, k=0.80 Wm1K1k=0.80\ \mathrm{W\,m^{-1}\,K^{-1}}, and inside and outside temperatures of 20C20^\circ\mathrm{C} and 5C5^\circ\mathrm{C}. Find the conductive heat loss rate Q˙\dot{Q}.
  2. 2 A metal plate of area 0.60 m20.60\ \mathrm{m^2} is at 80C80^\circ\mathrm{C} in air at 25C25^\circ\mathrm{C} with h=12 Wm2K1h=12\ \mathrm{W\,m^{-2}\,K^{-1}}. Calculate the convective heat transfer rate.
  3. 3 A black surface with ε=0.95\varepsilon=0.95 and A=1.5 m2A=1.5\ \mathrm{m^2} is at 310 K310\ \mathrm{K} in surroundings at 290 K290\ \mathrm{K}. Use Pnet=εσA(T4Tsurr4)P_{\mathrm{net}}=\varepsilon\sigma A\left(T^4-T_{\mathrm{surr}}^4\right) to find the net radiated power.
  4. 4 A house wall loses heat by conduction through insulation and then by convection from the outer surface to the air. Explain why adding insulation reduces heat loss more effectively than simply painting the wall a different color in many winter heating situations.