Sign in to save

Bookmark this page so you can find it later.

Sign in to save

Bookmark this page so you can find it later.

Two dimensional collisions combine vector motion with the conservation of momentum. Students need this cheat sheet because collision problems often look complicated when velocities point in different directions. Worked examples become easier when each vector is split into xx and yy components.

The goal is to organize information clearly before solving equations.

Key Facts

  • Momentum is a vector, so for each object p=mv\vec{p} = m\vec{v} and its components are px=mvxp_x = mv_x and py=mvyp_y = mv_y.
  • In every isolated collision, total momentum is conserved in both directions: px,i=px,f\sum p_{x,i} = \sum p_{x,f} and py,i=py,f\sum p_{y,i} = \sum p_{y,f}.
  • Velocity components from an angle θ\theta measured from the positive xx direction are vx=vcosθv_x = v\cos\theta and vy=vsinθv_y = v\sin\theta.
  • Speed and direction can be rebuilt from components using v=vx2+vy2v = \sqrt{v_x^2 + v_y^2} and θ=tan1(vyvx)\theta = \tan^{-1}\left(\frac{v_y}{v_x}\right).
  • For a perfectly inelastic collision where objects stick together, use m1v1i+m2v2i=(m1+m2)vfm_1\vec{v}_{1i} + m_2\vec{v}_{2i} = (m_1 + m_2)\vec{v}_f.
  • For an elastic collision, kinetic energy is also conserved, so 12m1v1i2+12m2v2i2=12m1v1f2+12m2v2f2\frac{1}{2}m_1v_{1i}^2 + \frac{1}{2}m_2v_{2i}^2 = \frac{1}{2}m_1v_{1f}^2 + \frac{1}{2}m_2v_{2f}^2.
  • If one object is initially at rest, its initial momentum components are px,i=0p_{x,i} = 0 and py,i=0p_{y,i} = 0 for that object.
  • A correct two dimensional solution must satisfy both component momentum equations, not just the equation in the direction of the initial motion.

Vocabulary

Momentum
Momentum is the vector quantity p=mv\vec{p} = m\vec{v} that measures an object's mass in motion.
Impulse
Impulse is the change in momentum, written J=Δp\vec{J} = \Delta \vec{p}.
Elastic collision
An elastic collision is a collision in which both momentum and kinetic energy are conserved.
Inelastic collision
An inelastic collision is a collision in which momentum is conserved but kinetic energy is not conserved.
Component
A component is the part of a vector along one axis, such as vxv_x or vyv_y.
Isolated system
An isolated system has no net external force, so its total momentum remains constant.

Common Mistakes to Avoid

  • Adding speeds instead of momentum vectors is wrong because momentum depends on both mass and direction, so use px=mvxp_x = mv_x and py=mvyp_y = mv_y.
  • Using only one conservation equation is wrong because two dimensional collisions require both px,i=px,f\sum p_{x,i} = \sum p_{x,f} and py,i=py,f\sum p_{y,i} = \sum p_{y,f}.
  • Forgetting signs on components is wrong because motion left or downward should usually be negative relative to the chosen axes.
  • Assuming kinetic energy is always conserved is wrong because only elastic collisions conserve kinetic energy, while inelastic collisions lose some mechanical energy.
  • Using tan1(vyvx)\tan^{-1}\left(\frac{v_y}{v_x}\right) without checking the quadrant is wrong because the signs of vxv_x and vyv_y determine the actual direction.

Practice Questions

  1. 1 A 2.0kg2.0\,\text{kg} puck moving east at 6.0m/s6.0\,\text{m/s} collides and sticks to a 3.0kg3.0\,\text{kg} puck moving north at 4.0m/s4.0\,\text{m/s}. Find the final speed and direction of the combined pucks.
  2. 2 A 0.50kg0.50\,\text{kg} ball moving at 10m/s10\,\text{m/s} along the +x+x direction breaks into two pieces. One 0.20kg0.20\,\text{kg} piece moves at 12m/s12\,\text{m/s} at 3030^\circ above +x+x. Find the velocity components of the 0.30kg0.30\,\text{kg} piece.
  3. 3 A 1.5kg1.5\,\text{kg} cart moving at 8.0m/s8.0\,\text{m/s} east collides with a 1.0kg1.0\,\text{kg} cart initially at rest. After the collision, the first cart moves at 5.0m/s5.0\,\text{m/s} at 2525^\circ north of east. Find the second cart's final velocity components.
  4. 4 In a two dimensional collision, why can the total kinetic energy decrease while total momentum in the xx and yy directions still remains conserved?

Understanding Two Dimensional Collisions Worked Examples

Start every worked example by choosing axes that make the motion easy to describe. A common choice is right as positive x and upward as positive y. Keep that choice for the whole calculation.

An object moving left has a negative x velocity component. An object moving downward has a negative y component. These signs are not optional details.

They tell the equations which momenta oppose each other. Draw each incoming and outgoing velocity as an arrow.

Label the angle and state clearly which axis the angle is measured from. If an angle is measured from the vertical, the sine and cosine roles switch from the usual horizontal reference case.

Conservation of momentum depends on treating the colliding objects as one system during the short impact. Forces between the objects can be very large, but they are internal forces and cancel when the whole system is considered. External forces such as friction or gravity may still act.

Usually their impulse during a very brief collision is small enough to ignore. This is why a puck collision on a smooth table is a useful model.

For a longer event, such as two vehicles remaining tangled while sliding across a road, friction after impact can no longer be ignored. Momentum conservation describes the impact itself, not every part of the later motion.

The number of unknowns determines what extra information is needed. Two final velocity components give two unknowns, so the x momentum equation and the y momentum equation may be enough. Often there are more unknowns.

A problem might give the final direction of one object, which links its two components. A perfectly inelastic collision has one shared final velocity, making the calculation simpler. In an elastic collision, kinetic energy provides another condition.

Be careful with this condition. Kinetic energy uses speed squared, so direction signs disappear there. Momentum equations must still retain signs.

A collision described as elastic does not mean the objects move in opposite directions or exchange velocities. Those outcomes occur only in special cases.

After finding components, check the result before trusting it. Add the final x momenta and compare them with the initial x total. Repeat for y.

Small differences can come from rounding, but a large difference usually means a missing negative sign, a wrong angle reference, or a calculator set to radians instead of degrees. Rebuild each final velocity from its components only after the momentum checks work. Then use the signs of both components to place the direction in the correct quadrant.

These habits matter in pool shots, air hockey, particle tracks, and crash analysis. The arrows show the physical story, while the component equations test whether that story is possible.