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Uniform Circular Motion cheat sheet - grade 9-12

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Uniform circular motion describes an object moving at constant speed around a circular path. Even though the speed stays constant, the velocity changes because the direction changes at every point. This cheat sheet helps students connect circle geometry, motion variables, and force diagrams in one place.

It is useful for solving problems involving cars turning, satellites orbiting, and objects moving on strings.

The most important idea is that circular motion requires an inward centripetal acceleration. That acceleration is caused by a net inward force, not by a separate new force. Key formulas connect tangential speed, radius, period, frequency, acceleration, and force.

Direction matters because velocity is tangent to the circle while acceleration and net force point toward the center.

Key Facts

  • Tangential speed in uniform circular motion is v=2πrTv = \frac{2\pi r}{T}, where rr is radius and TT is period.
  • Frequency and period are related by f=1Tf = \frac{1}{T} and T=1fT = \frac{1}{f}.
  • Tangential speed can also be written as v=2πrfv = 2\pi r f when frequency ff is known.
  • Centripetal acceleration is ac=v2ra_c = \frac{v^2}{r} and always points toward the center of the circle.
  • Centripetal acceleration can also be written as ac=4π2rT2a_c = \frac{4\pi^2 r}{T^2} or ac=4π2rf2a_c = 4\pi^2 r f^2.
  • The net inward force required for circular motion is Fc=mac=mv2rF_c = ma_c = \frac{mv^2}{r}.
  • Velocity is always tangent to the circular path, while acceleration and net force are always radial and inward.
  • Uniform circular motion has constant speed but changing velocity because velocity includes direction.

Vocabulary

Uniform circular motion
Motion in a circular path at constant speed, with velocity continuously changing direction.
Tangential speed
The linear speed of an object along the edge of a circle, given by v=2πrTv = \frac{2\pi r}{T}.
Centripetal acceleration
The inward acceleration needed to keep an object moving in a circle, given by ac=v2ra_c = \frac{v^2}{r}.
Centripetal force
The net inward force that causes centripetal acceleration, given by Fc=mv2rF_c = \frac{mv^2}{r}.
Period
The time for one complete revolution, represented by TT and measured in seconds.
Frequency
The number of revolutions per second, represented by ff and measured in hertz.

Common Mistakes to Avoid

  • Calling centripetal force a new type of force is wrong because FcF_c is the net inward force made by real forces such as tension, gravity, friction, or normal force.
  • Pointing acceleration in the direction of motion is wrong because in uniform circular motion aca_c points toward the center while vv is tangent to the circle.
  • Using diameter instead of radius in ac=v2ra_c = \frac{v^2}{r} is wrong because rr is the distance from the center to the object, not the full width of the circle.
  • Forgetting to square the speed in ac=v2ra_c = \frac{v^2}{r} is wrong because doubling vv makes the required centripetal acceleration four times larger.
  • Mixing up period and frequency is wrong because TT is time per revolution while ff is revolutions per second, and they satisfy f=1Tf = \frac{1}{T}.

Practice Questions

  1. 1 A ball moves in a circle of radius 0.80m0.80\,\text{m} with a speed of 4.0m/s4.0\,\text{m/s}. Find its centripetal acceleration.
  2. 2 A 1200kg1200\,\text{kg} car travels around a curve of radius 50m50\,\text{m} at 10m/s10\,\text{m/s}. Find the required centripetal force.
  3. 3 An object completes 55 revolutions in 10s10\,\text{s} on a circle of radius 2.0m2.0\,\text{m}. Find its frequency, period, and tangential speed.
  4. 4 A satellite moves at constant speed in a circular orbit. Explain why it is accelerating even though its speed does not change.