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The half-life of a reaction is the time required for the concentration of a reactant to decrease to half of its current value. It is a useful way to describe how fast a reactant is being consumed without tracking the entire reaction from start to finish. On a concentration versus time graph, each half-life marks a drop from [A]0 to [A]0/2, then [A]0/4, then [A]0/8.

This idea is especially important in chemical kinetics, medicine, environmental chemistry, and radioactive decay models.

Key Facts

  • Half-life means [A] changes from [A]initial to [A]initial/2.
  • For a first-order reaction, [A] = [A]0e^(-kt).
  • For a first-order reaction, t1/2 = ln(2)/k = 0.693/k.
  • For a zero-order reaction, [A] = [A]0 - kt and t1/2 = [A]0/(2k).
  • For a second-order reaction in one reactant, 1/[A] = 1/[A]0 + kt and t1/2 = 1/(k[A]0).
  • Only first-order half-life is independent of starting concentration.

Vocabulary

Half-life
The half-life of a reaction is the time it takes for a reactant concentration to fall to one half of its current value.
Reaction order
Reaction order describes how the reaction rate depends on the concentration of one or more reactants.
Rate constant
The rate constant k is the proportionality constant in a rate law and depends on the reaction and temperature.
First-order reaction
A first-order reaction has a rate directly proportional to the concentration of one reactant, so rate = k[A].
Integrated rate law
An integrated rate law relates reactant concentration to time and is used to calculate concentrations or half-lives.

Common Mistakes to Avoid

  • Assuming every reaction has a constant half-life is wrong because only first-order reactions have half-lives that do not depend on starting concentration.
  • Using t1/2 = 0.693/k for every reaction order is wrong because that formula applies only to first-order kinetics.
  • Forgetting the units of k is wrong because the units of the rate constant change with reaction order, such as s^-1 for first order and M^-1 s^-1 for second order.
  • Reading equal vertical drops as equal half-lives is wrong because half-life is based on halving the concentration, not subtracting the same concentration amount each time.

Practice Questions

  1. 1 A first-order reaction has k = 0.0250 s^-1. Calculate its half-life in seconds.
  2. 2 A zero-order reaction has [A]0 = 0.800 M and k = 0.0400 M/s. Calculate the time needed for [A] to fall to 0.400 M.
  3. 3 Two reactions both start at 1.00 M. Reaction X has the same half-life after each halving, while Reaction Y has a shorter half-life when the starting concentration is higher. Identify which reaction is first order and explain your reasoning.