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Arc Length & Surface of Revolution Explorer

Choose a function and interval, pick an axis of revolution, and read off the arc length and surface area. Both are computed numerically with Simpson's rule so you can see how the integral formulas turn into a single number.

Axis of revolution
Presets
Surface of revolution schematic for y = x about the x-axisds
generating curve ds sliceaxis of revolution dashed, cross-section bands thin

Results for y = x

Arc length L
1.41421
Surface area S (about x-axis)
4.44288
f(x)
y = x
Interval
[0.00, 1.00]
Radius
y (about x-axis)
S (other axis)
4.44288

Arc length

Surface of revolution (about x-axis)

Revolving the curve generates a surface whose radius at each slice is the distance from the curve to the axis. Here the radius is y.

Reference Guide

Arc Length

The arc length of y = f(x) over an interval comes from adding up tiny hypotenuses ds along the curve. Each piece has horizontal run dx and vertical rise f'(x) dx, so by the Pythagorean theorem ds = sqrt(1 + (f'(x))^2) dx.

L=ab1+(dydx)2dxL = \int_a^b \sqrt{1 + \left(\frac{dy}{dx}\right)^2}\, dx

Integrating ds from a to b accumulates the full length of the curve.

Surface of Revolution

Revolving the curve about an axis sweeps out a surface. A slice of length ds at distance r from the axis traces a band of area 2 pi r ds, so the surface area is the integral of 2 pi r ds.

S=ab2πrdsS = \int_a^b 2\pi\, r\, ds

About the x-axis the radius is r = y; about the y-axis it is r = x. This is surface area only. Volume of a solid of revolution is a different integral.

Endpoints Where the Slope Diverges

Some curves have a vertical tangent at an endpoint. For y = sqrt(x) the derivative is f'(x) = 1 / (2 sqrt(x)), which blows up as x approaches 0. The integrand sqrt(1 + (f'(x))^2) still gives a finite arc length, but a naive sample exactly at x = 0 is undefined.

f(x)=x,f(x)=12xf(x) = \sqrt{x}, \quad f'(x) = \frac{1}{2\sqrt{x}}

This tool starts the sqrt interval at a small positive value and Simpson's rule skips any non-finite sample, so the computed length stays accurate without dividing by zero.

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