Limits & Continuity cheat sheet - grade 11-12

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Calculus Grade 11-12

Limits & Continuity Cheat Sheet

A printable reference covering limit laws, one-sided limits, infinite limits, continuity, and the Intermediate Value Theorem for grades 11-12.

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Limits describe the value a function approaches as the input gets close to a number, even when the function is not defined there. This cheat sheet helps students organize the main rules for evaluating limits quickly and accurately. It also connects limits to continuity, which is one of the foundations of calculus. Students need these ideas before learning derivatives, tangent lines, and many real-world rate problems. Core concepts include direct substitution, algebraic simplification, one-sided limits, infinite limits, and special limit theorems. A function is continuous at x=ax=a when f(a)f(a) exists, limxaf(x)\lim_{x \to a} f(x) exists, and limxaf(x)=f(a)\lim_{x \to a} f(x)=f(a). Important formulas include the quotient law limxaf(x)g(x)=limxaf(x)limxag(x)\lim_{x \to a} \frac{f(x)}{g(x)}=\frac{\lim_{x \to a} f(x)}{\lim_{x \to a} g(x)} when the denominator limit is not 00. The Intermediate Value Theorem explains why continuous functions take every value between two endpoint values on a closed interval.

Key Facts

  • Direct substitution works when ff is continuous at x=ax=a, so limxaf(x)=f(a)\lim_{x \to a} f(x)=f(a).
  • The sum and difference laws state that limxa[f(x)±g(x)]=limxaf(x)±limxag(x)\lim_{x \to a} [f(x) \pm g(x)]=\lim_{x \to a} f(x) \pm \lim_{x \to a} g(x) when both limits exist.
  • The product law states that limxa[f(x)g(x)]=[limxaf(x)][limxag(x)]\lim_{x \to a} [f(x)g(x)]=[\lim_{x \to a} f(x)][\lim_{x \to a} g(x)] when both limits exist.
  • The quotient law states that limxaf(x)g(x)=limxaf(x)limxag(x)\lim_{x \to a} \frac{f(x)}{g(x)}=\frac{\lim_{x \to a} f(x)}{\lim_{x \to a} g(x)} when limxag(x)0\lim_{x \to a} g(x) \ne 0.
  • A two-sided limit exists only if limxaf(x)=limxa+f(x)\lim_{x \to a^-} f(x)=\lim_{x \to a^+} f(x).
  • A vertical asymptote occurs at x=ax=a if limxaf(x)=\lim_{x \to a} f(x)=\infty or limxaf(x)=\lim_{x \to a} f(x)=-\infty.
  • The Squeeze Theorem says if g(x)f(x)h(x)g(x) \le f(x) \le h(x) near x=ax=a and limxag(x)=limxah(x)=L\lim_{x \to a} g(x)=\lim_{x \to a} h(x)=L, then limxaf(x)=L\lim_{x \to a} f(x)=L.
  • Continuity at x=ax=a requires f(a)f(a) to exist, limxaf(x)\lim_{x \to a} f(x) to exist, and limxaf(x)=f(a)\lim_{x \to a} f(x)=f(a).

Vocabulary

Limit
A limit is the value that f(x)f(x) approaches as xx gets close to a number aa.
One-sided limit
A one-sided limit describes what f(x)f(x) approaches as xx approaches aa from only the left or only the right.
Continuity
Continuity at x=ax=a means the graph has no hole, jump, or break there, and limxaf(x)=f(a)\lim_{x \to a} f(x)=f(a).
Removable discontinuity
A removable discontinuity is a hole in the graph where the limit exists but the function value is missing or different.
Jump discontinuity
A jump discontinuity occurs when limxaf(x)\lim_{x \to a^-} f(x) and limxa+f(x)\lim_{x \to a^+} f(x) both exist but are not equal.
Vertical asymptote
A vertical asymptote is a line x=ax=a where the function grows without bound toward \infty or -\infty.

Common Mistakes to Avoid

  • Substituting immediately into every limit is wrong because expressions such as 00\frac{0}{0} are indeterminate and need simplification first.
  • Assuming a hole changes the limit is wrong because a limit depends on nearby values of f(x)f(x), not only on the value of f(a)f(a).
  • Combining one-sided limits without checking equality is wrong because limxaf(x)\lim_{x \to a} f(x) exists only when limxaf(x)=limxa+f(x)\lim_{x \to a^-} f(x)=\lim_{x \to a^+} f(x).
  • Treating k0\frac{k}{0} as 00 is wrong because division by 00 is undefined, and the expression may indicate an infinite limit or no limit.
  • Calling a function continuous just because it is defined at x=ax=a is wrong because continuity also requires limxaf(x)\lim_{x \to a} f(x) to exist and equal f(a)f(a).

Practice Questions

  1. 1 Evaluate limx3x29x3\lim_{x \to 3} \frac{x^2-9}{x-3}.
  2. 2 Evaluate limx0sinxx\lim_{x \to 0} \frac{\sin x}{x}.
  3. 3 For f(x)={2x+1,x<15,x=1x2+2,x>1f(x)=\begin{cases}2x+1, & x<1 \\ 5, & x=1 \\ x^2+2, & x>1\end{cases}, determine whether limx1f(x)\lim_{x \to 1} f(x) exists and whether ff is continuous at x=1x=1.
  4. 4 Explain why a function can have a limit at x=ax=a even if it is not continuous at x=ax=a.