Solutions are mixtures in which a solute is evenly distributed in a solvent. This cheat sheet helps students connect concentration units, dilution calculations, and solubility ideas in one quick reference. It is especially useful for lab work, chemical equations, and multi-step stoichiometry problems. Students need these tools to describe how much substance is dissolved and how solutions behave. The most important idea is that concentration compares the amount of solute to the amount of solution. Common formulas include molarity, M=nVM = \frac{n}{V}, dilution, M1V1=M2V2M_1V_1 = M_2V_2, and mass percent, % by mass=msolutemsolution×100%\%\ \mathrm{by\ mass} = \frac{m_{\mathrm{solute}}}{m_{\mathrm{solution}}} \times 100\%. Solubility depends on temperature, pressure, and the identities of the solute and solvent. Electrolytes form ions in solution, so they affect conductivity and many reaction calculations.

Key Facts

  • Molarity is calculated with M=nVM = \frac{n}{V}, where nn is moles of solute and VV is volume of solution in liters.
  • Moles of solute in a solution can be found with n=MVn = MV, which is useful before doing stoichiometry.
  • Dilution problems use M1V1=M2V2M_1V_1 = M_2V_2 because the moles of solute stay constant when only solvent is added.
  • Mass percent is calculated with % by mass=msolutemsolution×100%\%\ \mathrm{by\ mass} = \frac{m_{\mathrm{solute}}}{m_{\mathrm{solution}}} \times 100\%.
  • For dilute aqueous solutions, parts per million can be estimated with ppmmg soluteL solution\mathrm{ppm} \approx \frac{\mathrm{mg\ solute}}{\mathrm{L\ solution}}.
  • A saturated solution contains the maximum amount of dissolved solute at a given temperature and pressure.
  • For most solid solutes, solubility increases as temperature increases, but gas solubility usually decreases as temperature increases.
  • Strong electrolytes dissociate almost completely into ions, so NaCl(s)Na+(aq)+Cl(aq)\mathrm{NaCl}(s) \rightarrow \mathrm{Na}^{+}(aq) + \mathrm{Cl}^{-}(aq) represents ion formation in water.

Vocabulary

Solution
A homogeneous mixture in which a solute is evenly distributed throughout a solvent.
Solute
The substance that is dissolved in a solution, such as NaCl\mathrm{NaCl} in salt water.
Solvent
The substance that dissolves the solute and is usually present in the larger amount.
Molarity
A concentration unit equal to moles of solute per liter of solution, written as M=nVM = \frac{n}{V}.
Dilution
The process of lowering concentration by adding solvent while keeping the moles of solute constant.
Electrolyte
A substance that forms ions in solution and allows the solution to conduct electricity.

Common Mistakes to Avoid

  • Using milliliters directly in M=nVM = \frac{n}{V} is wrong because molarity requires volume in liters, so 250 mL250\ \mathrm{mL} must be converted to 0.250 L0.250\ \mathrm{L}.
  • Confusing solute mass with solution mass in mass percent is wrong because msolution=msolute+msolventm_{\mathrm{solution}} = m_{\mathrm{solute}} + m_{\mathrm{solvent}}.
  • Changing moles during dilution is wrong because adding solvent changes VV and MM, but the amount of solute stays the same.
  • Treating all dissolved substances as strong electrolytes is wrong because molecular compounds such as sugar dissolve without forming many ions.
  • Ignoring stoichiometric coefficients in solution reactions is wrong because n=MVn = MV gives moles of one substance, but the balanced equation gives the mole ratio.

Practice Questions

  1. 1 What is the molarity of a solution made by dissolving 0.750 mol0.750\ \mathrm{mol} of KNO3\mathrm{KNO_3} in enough water to make 2.50 L2.50\ \mathrm{L} of solution?
  2. 2 How many milliliters of 6.00 M6.00\ \mathrm{M} HCl\mathrm{HCl} are needed to prepare 250.0 mL250.0\ \mathrm{mL} of 0.500 M0.500\ \mathrm{M} HCl\mathrm{HCl}?
  3. 3 A solution contains 12.0 g12.0\ \mathrm{g} of glucose dissolved in 188.0 g188.0\ \mathrm{g} of water. What is the mass percent of glucose in the solution?
  4. 4 Explain why a solution of NaCl\mathrm{NaCl} conducts electricity but a solution of sugar does not, even though both substances dissolve in water.