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Stefan-Boltzmann & Blackbody Radiation cheat sheet - grade 11-12

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Blackbody radiation describes the electromagnetic radiation emitted by an ideal object that absorbs all incoming light. This cheat sheet helps students connect temperature, emitted power, wavelength, and color using the main radiation laws. These ideas are important in thermodynamics, astronomy, climate physics, and modern physics.

Key Facts

  • The Stefan-Boltzmann law for total emitted power is P=σAT4P = \sigma A T^{4} for an ideal blackbody.
  • For a real surface, emitted power is P=eσAT4P = e\sigma A T^{4}, where 0e10 \le e \le 1 is emissivity.
  • The net radiated power between an object and its surroundings is Pnet=eσA(T4Tsurr4)P_{\text{net}} = e\sigma A\left(T^{4} - T_{\text{surr}}^{4}\right).
  • The Stefan-Boltzmann constant is σ=5.67×108 Wm2K4\sigma = 5.67 \times 10^{-8}\ \text{W}\,\text{m}^{-2}\,\text{K}^{-4}.
  • Wien's displacement law is λmaxT=b\lambda_{\max}T = b, where b=2.90×103 mKb = 2.90 \times 10^{-3}\ \text{m}\cdot\text{K}.
  • All temperatures in radiation formulas must be measured in kelvins, so TK=TC+273.15T_{\text{K}} = T_{^\circ\text{C}} + 273.15.
  • The intensity of blackbody radiation increases rapidly with temperature because total emitted power is proportional to T4T^{4}.
  • A blackbody spectrum is continuous, and increasing temperature shifts the peak wavelength toward shorter wavelengths.

Vocabulary

Blackbody
An ideal object that absorbs all incident electromagnetic radiation and emits the maximum possible radiation for its temperature.
Emissivity
A number ee between 00 and 11 that compares how well a real surface emits radiation to an ideal blackbody.
Stefan-Boltzmann Law
The law stating that the total radiant power emitted by a blackbody is P=σAT4P = \sigma A T^{4}.
Wien's Law
The law stating that the peak wavelength of emitted radiation satisfies λmaxT=b\lambda_{\max}T = b.
Radiant Power
The rate at which energy is emitted as electromagnetic radiation, measured in watts.
Thermal Equilibrium
A condition in which an object absorbs and emits energy at equal rates, so its temperature remains constant.

Common Mistakes to Avoid

  • Using Celsius in P=eσAT4P = e\sigma A T^{4} is wrong because radiation laws require absolute temperature in kelvins.
  • Forgetting the fourth power in the Stefan-Boltzmann law is wrong because doubling TT increases emitted power by a factor of 24=162^{4} = 16, not 22.
  • Using P=σT4P = \sigma T^{4} when surface area matters is wrong because total power depends on area through P=σAT4P = \sigma A T^{4}.
  • Treating emissivity as a percentage without converting is wrong because 80%80\% emissivity must be used as e=0.80e = 0.80.
  • Subtracting temperatures before raising to the fourth power is wrong because net radiation is Pnet=eσA(T4Tsurr4)P_{\text{net}} = e\sigma A\left(T^{4} - T_{\text{surr}}^{4}\right), not eσA(TTsurr)4e\sigma A\left(T - T_{\text{surr}}\right)^{4}.

Practice Questions

  1. 1 A blackbody has surface area A=0.50 m2A = 0.50\ \text{m}^{2} and temperature T=600 KT = 600\ \text{K}. Find its emitted power using P=σAT4P = \sigma A T^{4}.
  2. 2 A star has surface temperature T=5800 KT = 5800\ \text{K}. Use Wien's law to estimate its peak wavelength λmax\lambda_{\max}.
  3. 3 A metal plate has e=0.70e = 0.70, A=2.0 m2A = 2.0\ \text{m}^{2}, T=400 KT = 400\ \text{K}, and surroundings at Tsurr=300 KT_{\text{surr}} = 300\ \text{K}. Calculate PnetP_{\text{net}}.
  4. 4 Explain why a hotter object can appear bluer than a cooler object even if both objects are emitting continuous blackbody spectra.