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Math Grade 9-12 Answer Key

Precalculus: Trigonometric Identities

Simplifying, verifying, and applying trigonometric identities

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Precalculus: Trigonometric Identities

Simplifying, verifying, and applying trigonometric identities

Math - Grade 9-12

Instructions: Read each problem carefully. Show each algebraic step clearly and state any restrictions when needed.
  1. 1

    Simplify the expression sin^2 x + cos^2 x + tan^2 x.

    Start with the Pythagorean identity sin^2 x + cos^2 x = 1.

    The expression simplifies to sec^2 x because sin^2 x + cos^2 x = 1, so the expression becomes 1 + tan^2 x = sec^2 x.
  2. 2

    Verify the identity (1 - cos^2 θ) / sin θ = sin θ.

    Using 1 - cos^2 θ = sin^2 θ, the left side becomes sin^2 θ / sin θ. For sin θ not equal to 0, this simplifies to sin θ, so the identity is verified where both sides are defined.
  3. 3

    Simplify the expression (sec x - cos x) / tan x.

    Rewrite sec x and tan x using sine and cosine.

    The expression simplifies to sin x. Rewriting in sine and cosine gives (1/cos x - cos x) / (sin x/cos x), which becomes ((1 - cos^2 x)/cos x)(cos x/sin x) = sin^2 x/sin x = sin x.
  4. 4

    Prove the identity tan θ + cot θ = sec θ csc θ.

    The left side becomes sin θ/cos θ + cos θ/sin θ. With a common denominator, this is (sin^2 θ + cos^2 θ)/(sin θ cos θ). Since sin^2 θ + cos^2 θ = 1, the expression becomes 1/(sin θ cos θ) = sec θ csc θ.
  5. 5

    Rewrite cos^2 x using a double-angle identity.

    Solve the double-angle identity cos 2x = 2cos^2 x - 1 for cos^2 x.

    The expression cos^2 x can be rewritten as (1 + cos 2x) / 2 using the identity cos 2x = 2cos^2 x - 1.
  6. 6

    Use an identity to find the exact value of sin 75°.

    Break 75° into 45° + 30°.

    Using sin(45° + 30°), sin 75° = sin 45° cos 30° + cos 45° sin 30°. This equals (√2/2)(√3/2) + (√2/2)(1/2) = (√6 + √2)/4.
  7. 7

    Use an identity to find the exact value of cos 15°.

    Using cos(45° - 30°), cos 15° = cos 45° cos 30° + sin 45° sin 30°. This equals (√2/2)(√3/2) + (√2/2)(1/2) = (√6 + √2)/4.
  8. 8

    Verify the identity sec^2 x - tan^2 x = 1.

    Use the Pythagorean identity involving tan x and sec x.

    The identity is verified because the Pythagorean identity 1 + tan^2 x = sec^2 x can be rearranged by subtracting tan^2 x from both sides, giving sec^2 x - tan^2 x = 1.
  9. 9

    Simplify the expression sin x csc x + cos x sec x.

    The expression simplifies to 2 because sin x csc x = 1 and cos x sec x = 1 wherever the expression is defined.
  10. 10

    Rewrite tan(π/2 - x) using a cofunction identity.

    Cofunction identities connect complementary angles.

    The expression tan(π/2 - x) is equal to cot x by the cofunction identity for tangent.
  11. 11

    Prove the identity (1 + sin x)(1 - sin x) = cos^2 x.

    The left side is a difference of squares: (1 + sin x)(1 - sin x) = 1 - sin^2 x. Since 1 - sin^2 x = cos^2 x, the identity is verified.
  12. 12

    Simplify the expression cos 2x + 2sin^2 x.

    Choose the double-angle form of cosine that contains sin^2 x.

    The expression simplifies to 1. Using cos 2x = 1 - 2sin^2 x, the expression becomes 1 - 2sin^2 x + 2sin^2 x = 1.
  13. 13

    If sin x = 3/5 and x is in Quadrant I, find cos 2x.

    Use a 3-4-5 right triangle to find cos x.

    Since x is in Quadrant I, cos x = 4/5. Then cos 2x = cos^2 x - sin^2 x = (4/5)^2 - (3/5)^2 = 16/25 - 9/25 = 7/25.
  14. 14

    Solve the equation 2sin x cos x = 1 for 0 ≤ x < 2π.

    Using the identity 2sin x cos x = sin 2x, the equation becomes sin 2x = 1. Thus 2x = π/2 or 5π/2 within the needed range, so x = π/4 or 5π/4.
  15. 15

    Use a half-angle identity to find the exact value of sin 15°.

    Since 15° is in Quadrant I, choose the positive square root.

    Using sin(15°) = sin(30°/2), sin 15° = √((1 - cos 30°)/2). Since cos 30° = √3/2, this becomes √((1 - √3/2)/2) = √((2 - √3)/4) = √(2 - √3)/2.
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