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Galvanic and electrolytic cells both use redox reactions to transfer electrons, but they do opposite energy conversions. A galvanic cell produces electrical energy from a spontaneous chemical reaction. An electrolytic cell uses electrical energy to drive a nonspontaneous chemical reaction. This cheat sheet helps students compare the two cell types quickly and avoid sign, electrode, and electron-flow errors. The most important ideas are oxidation, reduction, electrode identity, electron flow, and cell potential. Oxidation always occurs at the anode, and reduction always occurs at the cathode. For any electrochemical cell, the standard cell potential is found using Ecell=EcathodeEanodeE^{\circ}_{\text{cell}} = E^{\circ}_{\text{cathode}} - E^{\circ}_{\text{anode}}. Spontaneity is connected to free energy by ΔG=nFEcell\Delta G^{\circ} = -nFE^{\circ}_{\text{cell}}.

Key Facts

  • Oxidation is loss of electrons, reduction is gain of electrons, and this can be remembered as OIL RIG.
  • Oxidation always occurs at the anode, and reduction always occurs at the cathode in both galvanic and electrolytic cells.
  • In a galvanic cell, the reaction is spontaneous, so Ecell>0E^{\circ}_{\text{cell}} > 0 and ΔG<0\Delta G^{\circ} < 0.
  • In an electrolytic cell, the reaction is nonspontaneous, so an external power source is required and Ecell<0E^{\circ}_{\text{cell}} < 0 for the reaction as written.
  • The standard cell potential is calculated with Ecell=EcathodeEanodeE^{\circ}_{\text{cell}} = E^{\circ}_{\text{cathode}} - E^{\circ}_{\text{anode}} using reduction potentials.
  • The relationship between cell potential and free energy is ΔG=nFEcell\Delta G^{\circ} = -nFE^{\circ}_{\text{cell}}, where nn is moles of electrons and F=96485 C/mol eF = 96485\ \text{C/mol e}^{-}.
  • The Nernst equation at 25C25^{\circ}\text{C} is Ecell=Ecell0.0592nlogQE_{\text{cell}} = E^{\circ}_{\text{cell}} - \frac{0.0592}{n}\log Q.
  • In line notation, the anode is written on the left, the cathode is written on the right, and the salt bridge is shown with ||.

Vocabulary

Galvanic cell
A cell that converts chemical energy into electrical energy using a spontaneous redox reaction.
Electrolytic cell
A cell that uses electrical energy from an outside source to force a nonspontaneous redox reaction.
Anode
The electrode where oxidation occurs in any electrochemical cell.
Cathode
The electrode where reduction occurs in any electrochemical cell.
Cell potential
The voltage of an electrochemical cell, calculated under standard conditions by Ecell=EcathodeEanodeE^{\circ}_{\text{cell}} = E^{\circ}_{\text{cathode}} - E^{\circ}_{\text{anode}}.
Salt bridge
A connection that allows ions to move between half-cells so charge does not build up.

Common Mistakes to Avoid

  • Calling the anode positive in every cell is wrong because the anode is negative in a galvanic cell but positive in an electrolytic cell.
  • Reversing oxidation and reduction is wrong because oxidation always happens at the anode and reduction always happens at the cathode.
  • Multiplying reduction potentials when balancing electrons is wrong because EE^{\circ} values are intensive and do not change when half-reactions are multiplied.
  • Using Ecell=EanodeEcathodeE^{\circ}_{\text{cell}} = E^{\circ}_{\text{anode}} - E^{\circ}_{\text{cathode}} is wrong because standard cell potential must be calculated as Ecell=EcathodeEanodeE^{\circ}_{\text{cell}} = E^{\circ}_{\text{cathode}} - E^{\circ}_{\text{anode}}.
  • Forgetting the salt bridge is wrong because ion flow is needed to maintain electrical neutrality and keep current flowing.

Practice Questions

  1. 1 A cell has Ecathode=+0.80 VE^{\circ}_{\text{cathode}} = +0.80\ \text{V} and Eanode=0.76 VE^{\circ}_{\text{anode}} = -0.76\ \text{V}. Calculate EcellE^{\circ}_{\text{cell}}.
  2. 2 For a reaction with n=2n = 2 and Ecell=1.10 VE^{\circ}_{\text{cell}} = 1.10\ \text{V}, calculate ΔG\Delta G^{\circ} using ΔG=nFEcell\Delta G^{\circ} = -nFE^{\circ}_{\text{cell}} and F=96485 C/mol eF = 96485\ \text{C/mol e}^{-}.
  3. 3 At 25C25^{\circ}\text{C}, calculate EcellE_{\text{cell}} if Ecell=1.50 VE^{\circ}_{\text{cell}} = 1.50\ \text{V}, n=3n = 3, and Q=10Q = 10. Use Ecell=Ecell0.0592nlogQE_{\text{cell}} = E^{\circ}_{\text{cell}} - \frac{0.0592}{n}\log Q.
  4. 4 Explain why a galvanic cell can power a device without an external battery, while an electrolytic cell cannot.