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Thermodynamics explains how energy changes determine whether chemical and physical processes are likely to occur. This cheat sheet helps students connect heat flow, disorder, temperature, and spontaneity in one organized reference. It is especially useful for predicting reactions using enthalpy, entropy, and Gibbs free energy. These ideas are central in chemistry, biology, environmental science, and engineering.

Key Facts

  • Gibbs free energy is calculated by ΔG=ΔHTΔS\Delta G = \Delta H - T\Delta S, where TT must be in kelvins.
  • A process is spontaneous at constant temperature and pressure when ΔG<0\Delta G < 0.
  • A process is nonspontaneous at constant temperature and pressure when ΔG>0\Delta G > 0.
  • A system is at equilibrium when ΔG=0\Delta G = 0 and there is no net change in reaction progress.
  • Entropy change can be estimated by ΔS=SproductsSreactants\Delta S = S_{\text{products}} - S_{\text{reactants}} using standard molar entropy values.
  • Standard Gibbs free energy and equilibrium are related by ΔG=RTlnK\Delta G^\circ = -RT\ln K.
  • For nonstandard conditions, Gibbs free energy is calculated by ΔG=ΔG+RTlnQ\Delta G = \Delta G^\circ + RT\ln Q.
  • A temperature threshold for spontaneity occurs when ΔG=0\Delta G = 0, so T=ΔHΔST = \frac{\Delta H}{\Delta S} if ΔH\Delta H and ΔS\Delta S use compatible units.

Vocabulary

Enthalpy
Enthalpy is the heat content of a system at constant pressure, represented by HH.
Entropy
Entropy is a measure of energy dispersal or disorder in a system, represented by SS.
Gibbs Free Energy
Gibbs free energy is the energy available to do useful work, represented by GG.
Spontaneous Process
A spontaneous process is one that can occur without continuous outside energy input when ΔG<0\Delta G < 0.
Equilibrium Constant
The equilibrium constant KK compares product and reactant amounts at equilibrium for a reversible reaction.
Reaction Quotient
The reaction quotient QQ compares product and reactant amounts at any moment before equilibrium is reached.

Common Mistakes to Avoid

  • Using Celsius instead of kelvins in ΔG=ΔHTΔS\Delta G = \Delta H - T\Delta S is wrong because thermodynamic temperature must be absolute.
  • Forgetting to convert ΔS\Delta S from Jmol1K1\text{J}\,\text{mol}^{-1}\,\text{K}^{-1} to kJmol1K1\text{kJ}\,\text{mol}^{-1}\,\text{K}^{-1} is wrong when ΔH\Delta H is in kJmol1\text{kJ}\,\text{mol}^{-1}.
  • Assuming every exothermic reaction is spontaneous is wrong because entropy and temperature also affect ΔG\Delta G.
  • Confusing ΔG\Delta G with ΔG\Delta G^\circ is wrong because ΔG\Delta G^\circ applies only to standard-state conditions.
  • Treating a positive ΔS\Delta S as always spontaneous is wrong because ΔH\Delta H may still make ΔG\Delta G positive at a given temperature.

Practice Questions

  1. 1 Calculate ΔG\Delta G for a reaction with ΔH=45.0 kJmol1\Delta H = -45.0\ \text{kJ}\,\text{mol}^{-1}, ΔS=120 Jmol1K1\Delta S = -120\ \text{J}\,\text{mol}^{-1}\,\text{K}^{-1}, and T=298 KT = 298\ \text{K}.
  2. 2 Find the temperature at which a reaction changes spontaneity if ΔH=80.0 kJmol1\Delta H = 80.0\ \text{kJ}\,\text{mol}^{-1} and ΔS=200 Jmol1K1\Delta S = 200\ \text{J}\,\text{mol}^{-1}\,\text{K}^{-1}.
  3. 3 Use ΔG=RTlnK\Delta G^\circ = -RT\ln K to determine whether KK is greater than 11 or less than 11 when ΔG=12.5 kJmol1\Delta G^\circ = -12.5\ \text{kJ}\,\text{mol}^{-1} at 298 K298\ \text{K}.
  4. 4 Explain why a reaction with ΔH>0\Delta H > 0 and ΔS>0\Delta S > 0 may be nonspontaneous at low temperature but spontaneous at high temperature.