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Latent heat describes the energy absorbed or released when a substance changes phase without changing temperature. This cheat sheet helps students connect melting, freezing, vaporization, condensation, sublimation, and deposition to energy transfer. It is useful for solving calorimetry problems, reading heating curves, and deciding when to use temperature change formulas instead of phase change formulas. The most important idea is that temperature changes use Q=mcΔTQ = mc\Delta T, while phase changes use Q=mLQ = mL. During a phase change, added or removed energy changes the arrangement of particles, not their average kinetic energy. Heating and cooling curves show sloped regions for temperature changes and flat regions for phase changes. Energy conservation is often written as Qlost+Qgained=0Q_{\text{lost}} + Q_{\text{gained}} = 0 for insulated systems.

Key Facts

  • For a temperature change with no phase change, thermal energy is Q=mcΔTQ = mc\Delta T, where mm is mass, cc is specific heat, and ΔT=TfTi\Delta T = T_f - T_i.
  • For a phase change at constant temperature, thermal energy is Q=mLQ = mL, where LL is the latent heat for that phase change.
  • Melting and freezing use latent heat of fusion, so Q=mLfQ = mL_f at the melting or freezing point.
  • Vaporization and condensation use latent heat of vaporization, so Q=mLvQ = mL_v at the boiling or condensation point.
  • During melting, vaporization, and sublimation, the substance absorbs energy, so Q>0Q > 0.
  • During freezing, condensation, and deposition, the substance releases energy, so Q<0Q < 0.
  • On a heating curve, sloped segments represent Q=mcΔTQ = mc\Delta T and flat segments represent Q=mLQ = mL.
  • In an insulated calorimetry problem, energy is conserved with Qlost+Qgained=0Q_{\text{lost}} + Q_{\text{gained}} = 0.

Vocabulary

Latent heat
Latent heat is the thermal energy absorbed or released during a phase change without a temperature change.
Specific heat
Specific heat is the energy needed to raise the temperature of 1kg1\,\text{kg} of a substance by 1C1\,^{\circ}\text{C} or 1K1\,\text{K}.
Latent heat of fusion
Latent heat of fusion, LfL_f, is the energy per kilogram needed to melt or freeze a substance at its melting point.
Latent heat of vaporization
Latent heat of vaporization, LvL_v, is the energy per kilogram needed to vaporize or condense a substance at its boiling point.
Heating curve
A heating curve is a graph of temperature versus heat added that shows temperature increases and phase changes.
Thermal equilibrium
Thermal equilibrium occurs when objects in contact reach the same temperature and no net heat flows between them.

Common Mistakes to Avoid

  • Using Q=mcΔTQ = mc\Delta T during a phase change is wrong because the temperature stays constant while the substance changes phase.
  • Using Q=mLQ = mL when temperature is changing is wrong because latent heat only applies during a phase change at constant temperature.
  • Forgetting the sign of QQ can lead to incorrect energy conservation equations because melting and boiling absorb energy while freezing and condensing release energy.
  • Mixing units such as grams with J/kg\text{J}/\text{kg} is wrong because mass must match the units of LL and cc before calculating heat.
  • Assuming all added heat raises temperature is wrong because energy added during a flat part of a heating curve breaks or loosens intermolecular bonds instead.

Practice Questions

  1. 1 How much energy is needed to melt 0.250kg0.250\,\text{kg} of ice at 0C0\,^{\circ}\text{C} if Lf=3.34×105J/kgL_f = 3.34 \times 10^5\,\text{J/kg}?
  2. 2 How much heat is released when 0.080kg0.080\,\text{kg} of steam condenses at 100C100\,^{\circ}\text{C} if Lv=2.26×106J/kgL_v = 2.26 \times 10^6\,\text{J/kg}?
  3. 3 A 0.500kg0.500\,\text{kg} sample of water is heated from 20C20\,^{\circ}\text{C} to 100C100\,^{\circ}\text{C}, then completely vaporized. Find the total heat required using c=4186J/(kgC)c = 4186\,\text{J/(kg}\cdot^{\circ}\text{C)} and Lv=2.26×106J/kgL_v = 2.26 \times 10^6\,\text{J/kg}.
  4. 4 On a heating curve, explain why the temperature remains constant during melting even though heat is still being added.