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Polarization describes the direction in which the electric field of a light wave oscillates. This cheat sheet helps students connect wave behavior, filter experiments, reflection, and intensity changes in one place. It is useful for solving optics problems involving polarizers, reflected light, and electromagnetic wave direction.

Students need these ideas to understand why light can be transverse and how polarized light is used in real devices.

The most important rule is Malus’s law, I=I0cos2θI = I_0 \cos^2 \theta, which gives the transmitted intensity through an ideal analyzer. Unpolarized light passing through one ideal polarizer has intensity I=I02I = \frac{I_0}{2}. Brewster’s angle is found from tanθB=n2n1\tan \theta_B = \frac{n_2}{n_1} and gives reflected light that is strongly plane-polarized.

Polarization direction is always the direction of the electric field, not the direction the light ray travels.

Key Facts

  • Light is a transverse electromagnetic wave, so its electric field E\vec{E} oscillates perpendicular to its direction of travel.
  • The polarization direction of light is defined as the direction of the electric field E\vec{E}.
  • For unpolarized light passing through one ideal polarizer, the transmitted intensity is I=I02I = \frac{I_0}{2}.
  • For polarized light passing through an analyzer, Malus’s law gives I=I0cos2θI = I_0 \cos^2 \theta, where θ\theta is the angle between the light polarization and analyzer axis.
  • Two ideal polarizers crossed at 9090^\circ transmit no light because I=I0cos290=0I = I_0 \cos^2 90^\circ = 0.
  • Brewster’s angle satisfies tanθB=n2n1\tan \theta_B = \frac{n_2}{n_1} for light going from medium 11 into medium 22.
  • At Brewster’s angle, the reflected ray and refracted ray are perpendicular, so θB+θ2=90\theta_B + \theta_2 = 90^\circ.
  • Circular and elliptical polarization occur when perpendicular electric field components have phase differences such as Δϕ=π2\Delta \phi = \frac{\pi}{2}.

Vocabulary

Polarization
Polarization is the orientation pattern of the electric field E\vec{E} in a transverse light wave.
Polarizer
A polarizer is an optical filter that transmits light whose electric field is aligned with its transmission axis.
Analyzer
An analyzer is a second polarizer used to measure or test the polarization direction of light.
Malus’s Law
Malus’s law states that transmitted intensity through an ideal analyzer is I=I0cos2θI = I_0 \cos^2 \theta.
Brewster’s Angle
Brewster’s angle θB\theta_B is the angle of incidence where reflected light is maximally plane-polarized and tanθB=n2n1\tan \theta_B = \frac{n_2}{n_1}.
Unpolarized Light
Unpolarized light contains electric field oscillations in many random transverse directions.

Common Mistakes to Avoid

  • Using I=I0cosθI = I_0 \cos \theta instead of I=I0cos2θI = I_0 \cos^2 \theta is wrong because light intensity depends on the square of the electric field amplitude.
  • Forgetting the first polarizer halves unpolarized light is wrong because unpolarized light has no single starting polarization direction, so one ideal polarizer gives I=I02I = \frac{I_0}{2}.
  • Measuring θ\theta from the light ray direction is wrong because Malus’s law uses the angle between polarization axes, not the direction of propagation.
  • Assuming crossed polarizers always stay dark when a third polarizer is inserted is wrong because an intermediate angle can rotate the transmitted component and allow some light through.
  • Using tanθB=n1n2\tan \theta_B = \frac{n_1}{n_2} without checking media order is wrong because for light entering medium 22 from medium 11, Brewster’s law is tanθB=n2n1\tan \theta_B = \frac{n_2}{n_1}.

Practice Questions

  1. 1 Unpolarized light with intensity I0=80 W/m2I_0 = 80\ \text{W/m}^2 passes through one ideal polarizer. What is the transmitted intensity?
  2. 2 Polarized light of intensity I0=60 W/m2I_0 = 60\ \text{W/m}^2 passes through an analyzer at 3030^\circ to its polarization direction. Use I=I0cos2θI = I_0 \cos^2 \theta to find II.
  3. 3 Light travels from air with n1=1.00n_1 = 1.00 into glass with n2=1.50n_2 = 1.50. Find Brewster’s angle using tanθB=n2n1\tan \theta_B = \frac{n_2}{n_1}.
  4. 4 Why can transverse light waves be polarized, but longitudinal sound waves in air cannot be polarized in the same way?