Sign in to save

Bookmark this page so you can find it later.

Sign in to save

Bookmark this page so you can find it later.

This cheat sheet compares series and parallel circuits, two of the most important circuit layouts in physics. Students need these patterns to predict current, voltage, resistance, and bulb brightness in real circuits. It is especially useful for solving problems with batteries, resistors, switches, and light bulbs.

The goal is to make circuit behavior easier to recognize before doing calculations.

In a series circuit, charges have only one path, so the current is the same through every component. In a parallel circuit, charges have multiple paths, so the voltage is the same across each branch. Total resistance increases when resistors are added in series, but decreases when more branches are added in parallel.

Bulb brightness depends on electrical power, usually calculated with P=IVP = IV, P=I2RP = I^2R, or P=V2RP = \frac{V^2}{R}.

Key Facts

  • Ohm’s law relates voltage, current, and resistance using V=IRV = IR.
  • In a series circuit, the equivalent resistance is Req=R1+R2+R3+R_{\text{eq}} = R_1 + R_2 + R_3 + \cdots.
  • In a series circuit, the current is the same through every component, so Itotal=I1=I2=I3I_{\text{total}} = I_1 = I_2 = I_3.
  • In a series circuit, the battery voltage is shared by the components, so Vtotal=V1+V2+V3+V_{\text{total}} = V_1 + V_2 + V_3 + \cdots.
  • In a parallel circuit, the equivalent resistance is found with 1Req=1R1+1R2+1R3+\frac{1}{R_{\text{eq}}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \cdots.
  • In a parallel circuit, the voltage across each branch is the same, so Vtotal=V1=V2=V3V_{\text{total}} = V_1 = V_2 = V_3.
  • In a parallel circuit, total current is the sum of branch currents, so Itotal=I1+I2+I3+I_{\text{total}} = I_1 + I_2 + I_3 + \cdots.
  • Bulb brightness is proportional to power, and power can be calculated with P=IVP = IV, P=I2RP = I^2R, or P=V2RP = \frac{V^2}{R}.

Vocabulary

Series circuit
A circuit with only one path for current, so every component has the same current.
Parallel circuit
A circuit with two or more branches, so current can split and travel through different paths.
Equivalent resistance
The single resistance value that would have the same effect as all resistors in the circuit combined.
Current
The rate of flow of electric charge, measured in amperes, and represented by II.
Voltage
The electric potential difference that pushes charge through a circuit, measured in volts, and represented by VV.
Power
The rate at which electrical energy is transferred or used, measured in watts, and represented by PP.

Common Mistakes to Avoid

  • Adding parallel resistances as Req=R1+R2R_{\text{eq}} = R_1 + R_2 is wrong because that rule only applies to series circuits.
  • Assuming current is the same in every branch of a parallel circuit is wrong because current splits between branches based on resistance.
  • Assuming voltage is split equally in every circuit is wrong because voltage is the same across parallel branches and only divides across series components.
  • Thinking adding another parallel branch increases total resistance is wrong because more branches create more paths for current, so ReqR_{\text{eq}} decreases.
  • Judging bulb brightness only by resistance is wrong because brightness depends on power, such as P=V2RP = \frac{V^2}{R} or P=I2RP = I^2R.

Practice Questions

  1. 1 Three resistors, 4 Ω4\ \Omega, 6 Ω6\ \Omega, and 10 Ω10\ \Omega, are connected in series to a 12 V12\ \text{V} battery. Find ReqR_{\text{eq}} and ItotalI_{\text{total}}.
  2. 2 Two resistors, 6 Ω6\ \Omega and 3 Ω3\ \Omega, are connected in parallel across a 12 V12\ \text{V} battery. Find ReqR_{\text{eq}} and ItotalI_{\text{total}}.
  3. 3 A bulb has 6 V6\ \text{V} across it and a current of 0.50 A0.50\ \text{A}. Find its power using P=IVP = IV.
  4. 4 Two identical bulbs are connected to the same battery, first in series and then in parallel. Explain which arrangement makes the bulbs brighter and why.