Sign in to save

Bookmark this page so you can find it later.

Sign in to save

Bookmark this page so you can find it later.

This cheat sheet compares series and parallel circuits, two of the most important circuit layouts in physics. Students need these patterns to predict current, voltage, resistance, and bulb brightness in real circuits. It is especially useful for solving problems with batteries, resistors, switches, and light bulbs.

The goal is to make circuit behavior easier to recognize before doing calculations.

In a series circuit, charges have only one path, so the current is the same through every component. In a parallel circuit, charges have multiple paths, so the voltage is the same across each branch. Total resistance increases when resistors are added in series, but decreases when more branches are added in parallel.

Bulb brightness depends on electrical power, usually calculated with P=IVP = IV, P=I2RP = I^2R, or P=V2RP = \frac{V^2}{R}.

Key Facts

  • Ohm’s law relates voltage, current, and resistance using V=IRV = IR.
  • In a series circuit, the equivalent resistance is Req=R1+R2+R3+R_{\text{eq}} = R_1 + R_2 + R_3 + \cdots.
  • In a series circuit, the current is the same through every component, so Itotal=I1=I2=I3I_{\text{total}} = I_1 = I_2 = I_3.
  • In a series circuit, the battery voltage is shared by the components, so Vtotal=V1+V2+V3+V_{\text{total}} = V_1 + V_2 + V_3 + \cdots.
  • In a parallel circuit, the equivalent resistance is found with 1Req=1R1+1R2+1R3+\frac{1}{R_{\text{eq}}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \cdots.
  • In a parallel circuit, the voltage across each branch is the same, so Vtotal=V1=V2=V3V_{\text{total}} = V_1 = V_2 = V_3.
  • In a parallel circuit, total current is the sum of branch currents, so Itotal=I1+I2+I3+I_{\text{total}} = I_1 + I_2 + I_3 + \cdots.
  • Bulb brightness is proportional to power, and power can be calculated with P=IVP = IV, P=I2RP = I^2R, or P=V2RP = \frac{V^2}{R}.

Vocabulary

Series circuit
A circuit with only one path for current, so every component has the same current.
Parallel circuit
A circuit with two or more branches, so current can split and travel through different paths.
Equivalent resistance
The single resistance value that would have the same effect as all resistors in the circuit combined.
Current
The rate of flow of electric charge, measured in amperes, and represented by II.
Voltage
The electric potential difference that pushes charge through a circuit, measured in volts, and represented by VV.
Power
The rate at which electrical energy is transferred or used, measured in watts, and represented by PP.

Common Mistakes to Avoid

  • Adding parallel resistances as Req=R1+R2R_{\text{eq}} = R_1 + R_2 is wrong because that rule only applies to series circuits.
  • Assuming current is the same in every branch of a parallel circuit is wrong because current splits between branches based on resistance.
  • Assuming voltage is split equally in every circuit is wrong because voltage is the same across parallel branches and only divides across series components.
  • Thinking adding another parallel branch increases total resistance is wrong because more branches create more paths for current, so ReqR_{\text{eq}} decreases.
  • Judging bulb brightness only by resistance is wrong because brightness depends on power, such as P=V2RP = \frac{V^2}{R} or P=I2RP = I^2R.

Practice Questions

  1. 1 Three resistors, 4 Ω4\ \Omega, 6 Ω6\ \Omega, and 10 Ω10\ \Omega, are connected in series to a 12 V12\ \text{V} battery. Find ReqR_{\text{eq}} and ItotalI_{\text{total}}.
  2. 2 Two resistors, 6 Ω6\ \Omega and 3 Ω3\ \Omega, are connected in parallel across a 12 V12\ \text{V} battery. Find ReqR_{\text{eq}} and ItotalI_{\text{total}}.
  3. 3 A bulb has 6 V6\ \text{V} across it and a current of 0.50 A0.50\ \text{A}. Find its power using P=IVP = IV.
  4. 4 Two identical bulbs are connected to the same battery, first in series and then in parallel. Explain which arrangement makes the bulbs brighter and why.

Understanding Series vs Parallel Circuits

A circuit works because a battery creates an electric potential difference. This gives charges in the wire energy to move through the circuit. The charges do not get used up by a bulb.

Instead, energy carried by the charges is transferred into light and heat in the bulb filament. Think of current as the rate at which charge passes a point. At a junction, charge cannot build up for long.

The amount of current entering the junction must equal the total amount leaving it. This conservation rule explains why current divides between branches. A branch with less resistance allows a larger share of the current to pass.

Voltage is best understood as energy transferred per unit of charge. A resistor causes a voltage drop because charges transfer electrical energy there. In one loop, the energy supplied by the battery must match all the energy transferred by the components.

This is why the voltage drops around a complete loop add up to the battery voltage. For unequal resistors placed in one path, the larger resistance has the larger voltage drop because the same current passes through both. This result helps students predict measurements before calculating them.

A voltmeter is connected across a component because it compares the potential at two points. An ammeter is placed in the path of the current because it counts charge flow through that path.

Brightness questions need careful reading. Two identical bulbs connected to the same ideal battery in separate branches each receive the full battery voltage. Each can therefore operate at its normal power.

If the same bulbs are placed in one path, the supply voltage is divided between them. Their power is lower, so they are dimmer. Unequal bulbs can give less obvious results.

In one path, a bulb with greater resistance transfers more power when the current is the same. In separate branches, a bulb with lower resistance transfers more power when the voltage is the same.

These conclusions apply to bulbs treated as resistors. Real filament bulbs change resistance as they heat up, so advanced experiments may not match a simple calculation exactly.

Home wiring uses separate branches for a practical safety reason. Turning off one lamp does not stop current in the other rooms. If one appliance fails with an open break, the remaining branches can still work.

A short circuit is different. It provides a very low resistance path, which can produce a dangerously large current and heat wires quickly. Fuses and circuit breakers disconnect the supply when current becomes too large.

In classroom diagrams, first identify the junctions and trace complete paths rather than trusting the drawing shape. Components that look side by side are not necessarily in separate branches.

Check whether they connect across the same two points. Then choose known values, mark current directions and voltage drops, and use power only after the circuit layout is clear.