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Geometric and wave optics explains how light travels, bends, reflects, forms images, and produces wave effects such as interference and diffraction. Students need this cheat sheet to connect ray diagrams with equations and to choose the correct model for a problem. It is especially useful for comparing mirrors, lenses, and wave phenomena in one organized reference.

The core ideas include the law of reflection, Snell’s law, the thin lens and mirror equation, magnification, and wave relationships. Geometric optics treats light as rays moving in straight lines through uniform media, while wave optics treats light as a wave with wavelength, frequency, and phase. Interference and diffraction depend on path difference, wavelength, and geometry, while polarization describes the direction of the light’s electric field oscillation.

Key Facts

  • The law of reflection is θi=θr\theta_i = \theta_r, where both angles are measured from the normal line.
  • Snell’s law is n1sinθ1=n2sinθ2n_1 \sin \theta_1 = n_2 \sin \theta_2, where nn is the index of refraction.
  • The speed of light in a medium is v=cnv = \frac{c}{n}, so a larger nn means light travels more slowly.
  • The thin lens and mirror equation is 1f=1do+1di\frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}, where ff is focal length, dod_o is object distance, and did_i is image distance.
  • Magnification is m=hiho=didom = \frac{h_i}{h_o} = -\frac{d_i}{d_o}, where a negative value means the image is inverted.
  • For a double slit, bright fringes occur when dsinθ=mλd \sin \theta = m\lambda and dark fringes occur when dsinθ=(m+12)λd \sin \theta = \left(m + \frac{1}{2}\right)\lambda.
  • For a single slit, diffraction minima occur when asinθ=mλa \sin \theta = m\lambda, where m=1,2,3,m = 1, 2, 3, \ldots.
  • Malus’s law for polarized light is I=I0cos2θI = I_0 \cos^2 \theta, where θ\theta is the angle between the light’s polarization direction and the polarizer axis.

Vocabulary

Index of refraction
The index of refraction nn is a measure of how much a medium slows light, defined by n=cvn = \frac{c}{v}.
Focal length
Focal length ff is the distance from a lens or mirror to the point where parallel incoming rays converge or appear to diverge.
Real image
A real image forms where light rays actually meet and can be projected onto a screen.
Virtual image
A virtual image forms where light rays only appear to come from and cannot be projected onto a screen.
Interference
Interference is the combining of waves, producing brighter regions by constructive interference and darker regions by destructive interference.
Diffraction
Diffraction is the bending and spreading of waves when they pass through an opening or around an obstacle.

Common Mistakes to Avoid

  • Measuring angles from the surface instead of the normal is wrong because reflection and refraction angles must be measured from the perpendicular normal line.
  • Using degrees in calculations without checking the calculator mode is wrong because trigonometric values in Snell’s law depend on whether the calculator is set to degrees or radians.
  • Forgetting the sign convention for did_i, ff, or mm is wrong because image type, orientation, and lens or mirror behavior depend on signs as well as magnitudes.
  • Treating every image as real is wrong because virtual images occur when rays appear to meet, such as in a plane mirror or a diverging lens.
  • Using the double-slit bright-fringe formula for single-slit diffraction is wrong because dsinθ=mλd \sin \theta = m\lambda and asinθ=mλa \sin \theta = m\lambda describe different physical situations.

Practice Questions

  1. 1 Light travels from air with n1=1.00n_1 = 1.00 into glass with n2=1.50n_2 = 1.50 at an angle of incidence of 3030^\circ. Find the angle of refraction using n1sinθ1=n2sinθ2n_1 \sin \theta_1 = n_2 \sin \theta_2.
  2. 2 An object is placed 20 cm20\text{ cm} in front of a converging lens with focal length 10 cm10\text{ cm}. Use 1f=1do+1di\frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} to find the image distance.
  3. 3 A double-slit experiment uses slit spacing d=2.0×104 md = 2.0 \times 10^{-4}\text{ m} and light of wavelength λ=600 nm\lambda = 600\text{ nm}. Find θ\theta for the first bright fringe using dsinθ=mλd \sin \theta = m\lambda with m=1m = 1.
  4. 4 Explain why a narrow slit causes a wider diffraction pattern, even though the opening becomes smaller.